If a^2 + b^2 = 8 and (a-b)^2 = 4. What is the value of ab?
Explanation
Explanation
Given: a^2 + b^2 = 8 ... (Equation 1) (a - b)^2 = 4 Expanding the left side of the equation: a^2 - 2ab + b^2 = 4 Now, substitute Equation 1 into this equation: 8 - 2ab = 4 Subtract 8 from both sides: -2ab = -4 Divide both sides by -2: ab = 2 So, the value of ab is 2.
