Explanation
Solution : If x= 2, y = 3, z = 4 then 3x^2-4y^2+2z^2 3 x 2 − 4 y 2 + 2 z 2 = 3(2)^2-4(3)^2+2(4)^2 3 ( 2 ) 2 − 4 ( 3 ) 2 + 2 ( 4 ) 2 = left(3times4right)-left(4times9right)+left(2times16right) ( 3 × 4 ) − ( 4 × 9 ) + ( 2 × 1 6 ) = 12-36+32 1 2 − 3 6 + 3 2 = 44-36 4 4 − 3 6 = 8 8 ∴ 3x^2-4y^2+2z^2=8 3 x 2 − 4 y 2 + 2 z 2 = 8