Continuous Pattern Series — Part 2 MCQs with Explanations

The series is c a b/aa/ c aca b /cac a b/ a a/cac a b/ca. Thus, the pattern 'cacab/cacab/aa' is repeated.

The series is adb c /ac b d/ a bcd/dcba/dbca/cbda. Thus, the letters equidistant from the beginning and the end of series are the same.

The series is a bcd/bc a d/cabd/ a bcd/bc a d/c a bd. Clearly, each group consists of letters of the previous group in the order - second, third, first and fourth.

The series is a a bcc/b b caa/cca b b/aab c c. Thus, the letters move in a cyclic order and in each group, the middle letter occurs only once.

The series is a aab/a a bb/a b bb/ a aab/aa b b.

The series is a a a/bbb b /cccc/d d dd/ccc c /bb b b/a.

The series is ab c bc/bca c a/c a bab, Thus, the series consists of three sequences. The first sequence begins with a, the second with b, and the third with c. Each sequence consists of a letter followed by the pair of other two letters repeated twice.

The series is c a/cca a /ccca a a/cccc a aaa.

The series is a b cac/bc a ba/ca bc b. Thus, the series consists of three sequences. The first three letters of each sequence are in a cyclic order and the last two letters of each sequence are the same as the first and third letters of the sequence.

The series is aa/b c ab/ b cab/cca a /bcab/ b c. Thus, the pattern 'ccaa' followed by 'bcab' repeated twice, makes up the series.

The series is a b ca b /bc a bc/c a bca.

The series is c c ac c /aa b aa/ b bc b b/cc.

The series is ab c /b/bc a /c/ c ab/ a /ab c /b.

The series is mno/nopq/opqrs/ pqrst .

The series is b bca/ b cca/ b ca a /b b c.

The series is ccba/b b ca/a a bc/cc b a/ b .

The series is b a b b /bb a b/bbb a /bb b b.. Thus, in each sequence, 'a' moves one step forward and 'b' takes its place and finally in the fourth sequence, it is eliminated.

The series is abc d d/ a bc c d/ a b b cd/a.

The series is a b c c ab/b c a a bc/ a bc c ab. Thus, the pattern 'abccab/bcaabc' is repeated.

The series is a a bc c /c c abb/ b bca a .

The series is aa b /aaa b /aaaa b /aaaa a b. Thus, the number of a's increasing by one in the successive sequence,

The given series can be divided into five groups of four terms , where each group contains three letters and one number . Each group consists of two consecutive letters , and the number represents the alphabetical position of one of those letters. In the first group XWC _ , the consecutive letters are W and X , whose alphabetical positions are 23 and 24 respectively. From the given options, the only valid number that matches this rule is 23 , which corresponds to W . Applying the same logic to the remaining groups, the sequence of missing letters must maintain the consecutive-letter pattern along with correct alphabetical position representation . Only Option D satisfies this condition consistently across all five groups. Hence, the correct answer is Option D – 23, H, K, O, H .

From the alternatives, it is clear that the series can be divided in to 4 groups of four terms each - each group comprising of three letters and a number at the third place. D _ 6E/GP _ H/J _ 12K/MB15 _ Studying the pairs 6E and 12K, we find in each group the number is one more than the number represents the position of the letter at the forth place, in the English alphabet. Thus, putting A = 1, B = 2, ......y = 25, Z = 26, We have, 2nd missing tertm = H + 1 = 8 + 1 = 9; 4th missing term = 15 - 1= 14th letter = N Thus , the 2nd and 4th missing terms are 9 and N respectively, which are given only in (4).

From the alternatives, it is clear that the series can be divided in to 4 terms each - each group comprising of two numbers followed by two letters, as shown below 23 B _ / 6 _ F G/_ 5 D _ / 8 _ H I Clearly, the first number in each group represents the position of the letter at the third place, in the English alphabet. Thus, the third missing term is the number corresponding to the position of D in English alphabet i.e., 4, which is given in (1). Substituting other terms of (1) into the series, wer get: 23B C /6 7 FG/ 4 5DE/ 8 9 HI Observe that the second number in each group represents the position of the letter at the fourth place, in the English alphabet.

From the alternatives, it is clear that the series can be divided in to 4 groups of four terms each - each group comprising of two letters and two numbers, occurring alternately.. F _ U6/ _ 9I _ / T7 _ 20 / _ 4D23 4D indicates that in a group, the number at the second place denotes the position of the letter at the third place, in the English alphabet. T7 _ 20 indicates that in a group, the number at the fourth place denotes the position of the letter at the first place, in the English alphabet. Thus, putting A = 1, B = 2......Y = 25, Z = 26. we have , 1st missing term = U = 21; 3rd missing term = 7th letter = G 5th missing term = 23 letter = W.

From the alternatives, it is clear that the series can be divided in to 5 groups of three terms each - each group comprising of two letters followed by a number. Z _ _ 25/ YB23 / XC _ _ / W _ 19 / _ E 17 Observing the group Y B 23, we find that in a group, the number is the difference of the numbers representing the positions of the two letters in the English alphabet. Thus, putting A = 1, B = 2, ......Y = 25, Z = 26, we have Y - B = 25 - 2 = 23. Similarly, missing term in 1st group = Z - 25 = 26 - 25 = 1 = A So, the first and second missing terms are A and 21 respectively, which are given only in (A).

a c bd/ba c d/bcad/ d c da/ b a cd So, option (A) is correct.

BR O W N / B R O W N / B So, option (A) is the answer .

ip/i g /up/og/ i p/ig/ u p/og/i p / i g So, option (D) is the correct answer .

b a /ab/ a b/ b a/ab/ b b

a bc / ab b / cab / c c a / bca / a b