Direction Sense Test — Part 1 MCQs with Explanations

Man's Movement : The last position of the man is P and OEP is a Right angled triangle in which EP = 3 km and OE = 4 km Thus, OP = √(3 2 +4 2 ) OP = √25 OP = 5 km

Movements are as follows : Now, I am going in North-East Direction.

Man's Movement : Finally he is towards the South-East from his starting Point.

If South-east becomes North and North East becomes West, therefore, the whole figure moves through 135 0 . Hence, West will be South-East. See, Actual figure is rotating 135 0 anticlockwise. So, When West will be rotated by same degree anticlockwise. It will hold the place of south-East.

Rahim's Movement Therefore, the distance of Rahim from his starting point, = 20 + 25 = 45 meters

Mohan's Movement : If Mohan turned back from final position he must be facing in the direction of East .

Cyclist's Movement : Distance of the Cyclist from his starting Point O to end point D = 30 - 20 = 10 km

Movement of A : Finally A is facing in the direction of North-West.

As East becomes South, therefore, the pole has turned through 90 0 in anticlockwise direction. hence, the West will be North.

Movement of the man is O to E. And The distance between final and initial position is, EO = AB - DC = 10 - 5 = 5 m

From the figure, we get OC which is the required distance, OC = √(OC 2 + BC 2 ) OC = √(4 2 + 3 2 ) Oc = 5 km (North-East)

From figure, it is clear that OD is required distance which is 1 km.

let's break down this direction problem! The key to solving this is understanding how shadows form in the morning. In the morning, the sun rises in the East . This means that shadows will generally be cast towards the West . Now, the question says Vishal's shadow was to the left of Udai . Since the shadow is cast towards the West, and it's to Udai's left, this means Udai must be facing North . Think of it like this: If Udai is facing North, his left side would be towards the West, where Vishal's shadow is. Therefore, the answer is: North . So the correct option is (C).

P is in South-West of Y.

It is clear from the diagrams that new name of West will become South-East.

Hence required direction is South-West.

At 9.15 P.M., the minute hand will point towards west.

Required distance = AF = 30 + 15 = 45 m From the above diagram, F is in East direction from A. Hence the required answer is '45 m East'

Required Distance = DF = 150 - (25 + 25 + 35) = 150 - 85 = 65 km

Required Distance = 20 + 12 = 32 m in south direction

In the evening sun sets in West. Hence then any shadow falls in the East. Since Hema's shadow was to the right of Hema. Hence Rekha was facing towards South.

The boy rode 2 km. Northward.

Hence M is in the East of K.

Required Distance = AE = √(5 2 + 12 2 ) = 13 km

Required Distance = 8 + 6 + 8 + 6 + √(8 2 + 6 2 ) = 28 + √100 = 28 + 10 = 38 m

Hence finally Sujata will face towards North.

Q is in South-East of R.

Sun rises in the east. So the shadow of a man will always falls towards the west. Since the shadow of Stephen is to the right of Vimal. Hence Vimal is facing towards South.

Required Distance = AC = √(8 2 + 6 2 ) = √(64 + 36) = 10 km

Hence he should go in the South-West direction.

Hence X will face in the end towards South.

Therefore university is in North.

The journey was started from the South.

Required Distance = AE = 5 + 10 = 15 km

Required Distance = AD = √{3 2 + (14 - 10) 2 } = √(9 + 16) = 5 ft

In the morning sun rises in the East. Hence then any shadow falls in the West. Since Nikharia's shadow was exactly to the right of Nivedita. Hence Nikharia is facing towards North.

According to P % Q + R - S S is in the South-East of Q.

Sun rises in the east in the morning. Since the shadow of Suresh falls to his right. So he is facing South.

Required Distance = AE = √(AG 2 + EG 2 ) = √{(90 - 30) 2 + (100 - 20) 2 } = √{(60) 2 + (80) 2 } = √(3600 + 6400) = √10000 = 100 m

Therefore, D's house is in the South-East direction of A.