Number Series Completion — Part 1 MCQs with Explanations

1 2 = 1. 3 2 = 9. 5 2 = 25. 7 2 = 49. 9 2 = 81. 11 2 = 121.

First term : 4 Second term: 4+3 = 7 Third term : 7+5 = 12 Fourth term : 12+7 = 19. Fifth term : 19+9 = 28. Therefore, Next Terms : 28+11 = 39

6 (+5)→ 11 (+10)→ 21 (+15)→ 36 (+20)→ 56 (+25) → 81.

1st term : 10 2nd term : 100 = 10+90 3rd term : 200 = 100+100 4th term : 310 = 200+110 5th Term: 430 = 310+120 Therefore, the answer is 430.

(8 *3) + 4 = 28 (28 *4) + 4 = 116 (116 *5) + 4 = 584 (584 *6) + 4 = 3508.

1st number = 3 2nd number = 3 x 2 +1 = 7 3rd number = 7 x 3 + 2 = 23 4th number = 23 x 4 + 3 = 95 5th number = 95 x 5 + 4 = 479

The terms are given in a series (2 3 -1) = 7 (3 3 -1) = 26 (4 3 -1) = 63 (5 3 -1) = 124 (6 3 -1) = 215 (7 3 -1) = 342 So, the missing term is, (8 3 -1) = 511.

Solution 1: Each number of given series is 15 multiplied by a prime number . 15*11, 15*13, 15*17, 15*19, 15*23. So, Missing number is 15*29 = 435. Solution 2: This pattern is +30 and then +60 also follow for the give series. 165+30=195, 195+60=255, 255+30=285, 285+60=345, 345+30=375

34(+11) → 45(+11) → 56(+11) →67 (+11) → 78.

2 nd number is less by 1 than the 1 st number and 3 rd number is more by 5 than the 2 nd number. The same rule follows in other numbers of the series.

By adding 300 to each term, we get the next term. 1060 is wrong term. It should be 1050.

By subtracting 569, we get the next term. Required number, = 2845-569 = 2276.

First term → 6 Second term → (6*2+1) = 13 Third term → (13*2+2) = 28 Fourth term → (28*2+3) = 59 Fifth term → (59*2+4) = 122 Sixth term → (122*2+5) = 249 So, the required term = 122.

Above series contains two sub-series in it. 4, 10, 16, 22 8, 14, 20 Each of both term there is difference of 6 i.e. next term is 6 greater than previous term.

First term → 9 Second term → (9 *2 -1) = 17 Third term → (17 *2 -1) = 33 Fourth term → (33 *2 -1) = 65 Fifth term → (65 *2 -1) = 129

First term → 2 Second term → (2 *3 -3) = 3 Third term → (3 *3 -3) = 6 Fourth term → (6 *3 - 3) = 15 Fifth term → (15 *3 - 3) = 42 Sixth term → (42 *3 - 3) = 123

The given pattern is, 2 nd term → 1*2+1 = 3 3 rd term → 3*3+1 = 10 4 th term → 10*2+1 = 21 5 th term → 21*3+1 = 64 6 th term → 64*2+1 = 129 7 th term → 129*3+1= 388 So, 7 th term 356 is wrong and must be replaced by 388 .

Given pattern is, 2 nd term → 9*3 = 27 3 rd term → 27+4 = 31 4 th term → 31*5 = 155 5 th term → 155+6 = 161. 6 th term → 161*7 = 1127 Missing term → 1127+8 = 1135.

The pattern is, 2 nd term → 2 +(5 *1 2 ) = 7 3 rd term → 7 +(5 *2 2 ) = 27 4 th term → 27 +(5 *4 2 ) = 107 5 th term → 107 +(5 *8 2 ) = 427 Missing term → 427 +(5 *16 2 ) = 1707

Sunday to Monday = no gap Monday to Wednesday = One day gap. Wednesday to Saturday = Two days gap. Saturday to Wednesday = Three days gap. Wednesday to Monday = Four days gap. In the next term there must be five days and six days gap. So, Next term would be Sunday, Sunday. Details Explanations The sequence follows a pattern based on the increasing gap of days between consecutive terms. From Sunday to Monday , there is no day gap . From Monday to Wednesday , there is a one-day gap . From Wednesday to Saturday , there is a two-day gap . From Saturday to Wednesday , there is a three-day gap (counting forward cyclically through the week). From Wednesday to Monday , there is a four-day gap . Following this logical progression, the next gaps should be five days and then six days . A five-day gap from Monday leads to Sunday , and a six-day gap from Sunday again leads to Sunday . Hence, the next two terms are Sunday, Sunday , making Option A the correct answer.

Logic: Next term = Previous term /4 2816 /4 = 704 704 /4 = 176. 176 /4 = 44. 44 /4 = 11.

113 113 * 2 = 226 -1 = 225 225 * 2 = 450 -1 = 449 449 * 2 = 898 - 1 = 897 897 * 2 = 1794 -1 = 1793

P RODUCTIVIT Y = RODUCTIVIT.(First and last letters are removed.) R ODUCTIVI T = ODUCTIVI. O DUCTIV I = DUCTIV.

First Number = 1 *2 *3 = 6 Second Number = 2*3*4 = 24 Third Number = 3*4*5 = 60 Fourth Number = 4*5*6 = 120 Fifth Number = 5*6*7 = 210 Sixth Number = 6*7*8 = 336. Alternatively , 2*2*2-2=6 3*3*3-3=24 4*4*4-4=60 5*5*5-5=120 6*6*6-6=210 7*7*7-7=336.

Logic: First Term = 6. Second term = 6*2 -1 = 11. Third term = 11* 3 - 2 = 31. Fourth term = 31 *4 - 3 = 124 -3 = 121. Fifth term = 121*5 - 4 = 601. Sixth term = 601 *6 = 3606 - 5 = 3601 .

Logic: Last Term *2 - 3 = Next Term. First Term = 7 Second Term = 7 * 2 -3 = 11 Third Term = 11 * 2 - 3 = 19 Fourth Term = 19 * 2 - 3 = 35 Fifth Term = 35 * 2 - 3 = 67 Sixth Term = 67 * 2 -3 = 131 Alternative Solution : Last term + 2 n = Next Term First Term = 7 Second Term = 7 + 2 2 = 11 Third Term = 11 + 2 3 = 19 Fourth Term = 19 + 2 4 = 35 Fifth Term = 35 + 2 5 = 67 Sixth Term = 67 + 2 6 = 131

Logic: Previous Term * 3 - 2 = Next term. First Term = 8 Second term = 8 * 3 - 2 = 24 - 2 = 22 Third term = 22 * 3 - 2 = 64 Fourth term = 64 * 3 - 2 = 190 Fifth Term = 190 * 3 - 2 = 568 Sixth Term = 568 * 3 - 2 = 1704 - 2 = 1702

First Term = 5760. Second term = 5760 /2 = 2880. Third Term = 2880/3 = 960. Fourth term = 960/4 = 240. Fifth term = 240/5 = 48. So, Required term = 48/6 = 8.

This is a simple division series; each number is one-half of the previous number. In other terms to say, the number is divided by 2 successively to get the next result. 4 / 2 = 2 2 / 2 = 1 1 / 2 = 1 / 2 1/2 / 2 = 1 / 4 1/4 / 2 = 1 / 8 and so on.

This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted. Alternate Solution : Above Series contains two sub series in it Series 1 st = 7, 8, 9, 10 Series 2 nd = 10, 11, 12 Note : Both sub series is in ascending order. Next number is greater by 1 from the previous one.

This is an alternating number subtraction series. First, 2 is subtracted, then 4, then 2, and so on.

In this simple alternating subtraction and addition series; 1 is subtracted, then 2 is added, and so on.

In this series, each number is repeated, then 13 is subtracted to arrive at the next number.

In this alternating repetition series, the random number 21 is interpolated every other number into an otherwise simple addition series that increases by 2, beginning with the number 9.

This is a simple subtraction series. Each number is 6 less than the previous number.

This alternating addition series begins with 3; then 1 is added to give 4; then 3 is added to give 7; then 1 is added, and so on.

This is a simple addition series with a random number, 8, interpolated as every other number. In the series, 6 is added to each number except 8, to arrive at the next number.

This is a simple alternating subtraction series, which subtracts 2, then 5.

In this simple addition series, each number increases by 0.8.

This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.