Chemical Kinetics MCQs with Explanations
Practice high-yield Chemistry & Applied Chemical Sciences MCQs on Chemical Kinetics with worked academic solutions for MDCAT, CSS, PMS, PPSC, FPSC.
Questions
19
Difficulty Level
Exam-Level
Target Exams
MDCAT, CSS, PMS...
Estimated Time
23 mins
Exam-Level MDCAT CSS PMS PPSC FPSC
Verified for Commission Syllabus • Oct 14, 2026
19
Verified Practice Questions
Interactive test mode with detailed academic worked solutions
Live Progress | 0/19 answered
✓ 0 correct
✗ 0 wrong
0% score
🎉 Set complete! All 19 questions answered.
Question 1 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
Question 2 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
At T = 300 K, the thermal energy [k B T] in cm -1 is approximately
Question 3 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The half-life of a first order reaction varies with temperature according to
Question 4 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
For a given first order reaction, the reactant reduces to $${\frac{1}{4}^{{\text{th}}}}$$ its initial value in 10 min. The rate constant of the reaction is
Question 5 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
For the reaction, 2X 3 $$ \rightleftharpoons $$ 3X 2 , the rate of formation of X 2 is
Question 6 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The half-life time for a reaction at initial concentrations of 0.1 and 0.4 mol -1 are 200 s and 50 s respectively. The order of the reaction is
Question 7 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
For the reaction shown below, the value of k 1 is 1 × 10 -4 s -1 . If the reaction starts from X, the ratio of the concentrations of Y and Z at any given time during the course of the reaction is found to be $$\frac{{\left[ {\text{Y}} \right]}}{{\left[ {\text{Z}} \right]}} = \frac{1}{4}.$$ The value of k 2 is
Question 8 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
Consider an exothermic reaction, $$A\mathop {\mathop \rightleftharpoons \limits_{{k_{ - 1}}} }\limits^{{k_1}} I$$ As the temperature increases
Question 9 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
1 g of 90 Sr gets converted to 0.953 g after 2 yr. The half-life of 90 Sr, and the amount of 90 Sr remaining after 5 yr are
Question 10 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The reaction, 2NO(g) + O 2 (g) → 2NO 2 (g) proceeds via the following steps: NO + NO \[\xrightarrow{{{{\text{K}}_{\text{a}}}}}\] N 2 O 2 N 2 O 2 \[\xrightarrow{{{{\text{K}}_{{\text{a'}}}}}}\] NO + NO N 2 O 2 + O 2 \[\xrightarrow[{\left( {{\text{slow}}} \right)}]{{{{\text{k}}_{\text{b}}}}}\] NO 2 + NO 2 The rate of this reaction is equal to
Question 11 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
A reaction proceeds through the formation of an intermediate B in a unimolecular reaction \[A\xrightarrow{{{k_a}}}B\xrightarrow{{{k_b}}}C\] The integrated rate law for this reaction is
Question 12 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
In a homogeneous catalytic reaction, 1.0 M of a substrate band 1.0 μM of a catalyst yields 1.0 mM of a product in 10 s. The turnover frequency (TOF) of the reaction (S -1 ) is
Question 13 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
For the reaction, P + Q + R → S, experimental data for the measured initial rates is given below: Expt. Initial conc. P (M) Initial conc. Q (M) Initial conc. R (M) Initial rate (m/s) 1 0.2 0.5 0.4 8.0 × 10 -5 2 0.4 0.5 0.4 3.2 × 10 -4 3 0.4 2.0 0.4 1.28 × 10 -3 4 0.1 0.25 1.6 4.0 × 10 -5 The order of the reaction with respect to P, Q and R respectively, is
Question 14 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
A reaction follows second order rate law, $$\frac{{ - d\left[ A \right]}}{{dt}} = k{\left[ A \right]^2},$$ if
Question 15 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The half-life (t 1/2 ) for the hydrolysis of an ester varies with the initial concentration of the reactant ([E] 0 ) as follows: [E] 0 /10 mol/L 5.0 4.0 3.0 t 1/2 /s 240 300 400 The order of the reaction is
Question 16 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The specific rate constant of decomposition of a compound is represented by $$\ln k = 5.0 - \frac{{12000}}{T}$$ The activation energy of decomposition foe this compound at 300 K is
Question 17 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
In a consecutive first order reaction, (where k 1 and k 2 are the respective rate constants) species B has transient existence. Therefore,
Question 18 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The fluorescence life time of a molecule in solution is 10 ns. If the fluorescence quantum yield is 0.1, the rate constant of fluorescence decay is
Question 19 of 19
★ MDCAT
★ CSS
★ MDCAT
★ CSS
The value of the rate constant for the gas phase reaction, 2NO 2 + F 2 → 2NO 2 F is 38 dm 3 mol -1 s -1 at 300K. The order of the reaction is
✓ Link copied to clipboard
Continue Your Practice
Next Practice Set → Acid_ Base And Salts — Part 1
Master the next curriculum module with 40 exam-standard MCQs.
💡 Examiner's Advisory for Chemistry & Applied Chemical Sciences
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.
More Modules in Chemistry & Applied Chemical Sciences
View All → Acid_ Base And Salts — Part 1
40 MCQs
Practice →
Acid_ Base And Salts — Part 2
40 MCQs
Practice →
Atomic Structure & Periodicity — Part 1
40 MCQs
Practice →
Atomic Structure & Periodicity — Part 2
40 MCQs
Practice →
Atomic Structure & Periodicity — Part 3
35 MCQs
Practice →
Atomic Structure
20 MCQs
Practice →