Circuit Theorems And Conversions MCQs with Explanations

The load current is determined by analyzing the circuit and applying Ohm's law and the voltage-divider principle. Given: Load resistance, R L = 680 Ω Internal source resistance, R S = 12 kΩ = 12,000 Ω Constant current source, I S = 1.2 A Step 1: Determine the total voltage of the circuit The total voltage generated by the current source is: V total = I S × R S = 1.2 A × 12,000 Ω = 14,400 V Step 2: Calculate the equivalent resistance The load resistor and internal source resistance form a voltage divider. The voltage across R L is calculated as: V L = V total × (R L / (R L + R S )) V L = 14,400 × (680 / (680 + 12,000)) V L = 14,400 × (680 / 12,680) = 774 V Step 3: Find the load current The load current is: I L = V L / R L = 774 / 680 = 1.14 A

False is the correct answer to “Transistors act basically as voltage sources.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

154 Ω is the correct answer to “Find RN for the circuit given.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

6.4 V, 422 Ω is the correct answer to “What is the Thevenin equivalent (V TH and R TH ) for the circuit given”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

245 mA is the correct answer to “Determine $${I_{\text{N}}}$$ for the circuit consisting of VS, R1, R2 and R3 shown in the given circuit.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

1.8 mA is the correct answer to “Find the total current through R3 in the given circuit.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

134 mA is the correct answer to “Find the current through R2 of the given circuit.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

0.16 A is the correct answer to “Find the current through R1 in the given circuit.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

4.50 V, 4.5 mA is the correct answer to “Referring to the given circuit, the voltage and current for the load resistor, RL, is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

8.5 V is the correct answer to “A 2 Ω RL is connected across a voltage source, VS, of 110 V. The source's internal resistance is 24 Ω. What is the output voltage across the load”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

117 V is the correct answer to “A 470 Ω RL is connected across a voltage source, VS, of 120 V. The source's internal resistance, RS, is 12 Ω. What is the output voltage across the load”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

True is the correct answer to “Conversions between delta-type and wye-type circuit arrangements are useful in certain specialized applications.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

478 mA, 12.8 Ω is the correct answer to “Find the Norton circuit, that is, I IN and R N , for the circuit given below.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

41.67 V, 70 Ω is the correct answer to “Find the Thevenin equivalent (VTH and RTH) between terminals A and B of the circuit given below.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

0.16 A is the correct answer to “Referring to circuit given, if R1 is changed to a 68 Ω resistor, what will be the current through it”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

12 V is the correct answer to “A 120 Ω load is connected across an ideal voltage source with VS = 12 V. The voltage across the load is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

11.25 V is the correct answer to “A 120 Ω load is connected across a voltage source with VS = 12 V and RS = 8 Ω. The voltage across the load is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

238 mW is the correct answer to “A 12 V source has an internal resistance of 90 Ω. If a load resistance of 20 Ω is connected to the voltage source, the load power, PL, is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

1 W is the correct answer to “An 18 V source has an internal resistance of 70 Ω. If a load resistance of 33 Ω is connected to the voltage source, the load power, PL, is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

True is the correct answer to “Some circuits require more than one voltage or current source.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

3.3 V, 148 Ω is the correct answer to “Referring to the given circuit, determine V TH and R TH if a 68 Ω resistor is connected in parallel across R2 and R3.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

5.62 V, 167 Ω is the correct answer to “Find the Thevenin equivalent (V TH and R TH ) between terminals A and B of the circuit given.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

2 mA is the correct answer to “In a two-source circuit, one source acting alone produces 12 mA through a given branch. The other source acting alone produces 10 mA in the opposite direction through the same branch. The actual current through the branch is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

False is the correct answer to “An ideal current source has zero internal resistance.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

True is the correct answer to “A practical voltage source has a nonzero internal resistance.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

True is the correct answer to “An ideal voltage source has zero internal resistance.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

True is the correct answer to “A practical current source has a finite internal resistance.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

False is the correct answer to “The Thevenin equivalent voltage (V TH ) is the short-circuit voltage between two terminals in a circuit.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

2 A is the correct answer to “A 120 V voltage source has a source resistance, RS, of 60 Ω. The equivalent current source is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

14.4 V is the correct answer to “A 12 mA current source has an internal resistance, RS, of 1.2 kΩ. The equivalent voltage source is”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

50 mA is the correct answer to “Find the current in R2 of the given circuit, using the superposition theorem.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

False is the correct answer to “Norton's equivalent current (IN) is an open-circuit current between two points in a circuit.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

5 A, 6 Ω is the correct answer to “A certain voltage source has the values VS = 30 V and RS = 6 Ω. The values for an equivalent current source are”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

4.8 V, 1.2 MΩ is the correct answer to “A certain current source has the values IS = 4 µA and RS = 1.2 MΩ. The values for an equivalent voltage source are”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.

False is the correct answer to “You cannot convert a voltage source to an equivalent current source, or vice versa.”. This question is standard in competitive examination syllabi for Circuit Theorems And Conversions.