Practice high-yield Mathematics & Quantitative Ability MCQs on Calculus — Part 1 with worked academic solutions for CSS, NTS, PPSC, FPSC, PMS.
Questions
40
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CSS, NTS, PPSC...
Estimated Time
48 mins
Exam-Level CSS NTS PPSC FPSC PMS
Verified for Commission Syllabus • Oct 14, 2026
40
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Question 1 of 40
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What is the value of \[\mathop {\mathop {\lim }\limits_{{\text{x}} \to 0} }\limits_{{\text{y}} \to 0} \frac{{{\text{xy}}}}{{{{\text{x}}^2} + {{\text{y}}^2}}}?\]
Correct Answer: Option D — Limit does not exit
Detailed Academic Explanation:
Limit does not exit is the correct answer to “What is the value of \[\mathop {\mathop {\lim }\limits_{{\text{x}} \to 0} }\limits_{{\text{y}} \to 0} \frac{{{\text{xy}}}}{{{{\text{x}}^2} + {{\text{y}}^2}}}?\]”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 2 of 40
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The Taylor series expansion of 3 sinx + 2 cosx is . . . . . . . .
2 + 3x - x2 - \[\frac{{{{\text{x}}^3}}}{2}\] + ... is the correct answer to “The Taylor series expansion of 3 sinx + 2 cosx is . . . . . . . .”. This question is standard in competitive examination syllabi for Calculus.
\[\frac{1}{2}\] is the correct answer to “\[\mathop {\lim }\limits_{{\text{x}} \to \infty } \sqrt {{{\text{x}}^2} + {\text{x}} - 1} - {\text{x is}}\]”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 4 of 40
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The Taylor series expansion of \[\frac{{\sin {\text{x}}}}{{{\text{x}} - \pi }}\] at \[{\text{x}} = \pi \] is given by
\[ - 1 - \frac{{{{\left( {{\text{x}} - \pi } \right)}^2}}}{{3!}} + ...\] is the correct answer to “The Taylor series expansion of \[\frac{{\sin {\text{x}}}}{{{\text{x}} - \pi }}\] at \[{\text{x}} = \pi \] is given by”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 5 of 40
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If x = a (θ + sin θ) and y = a (1 - cos θ), then \[\frac{{{\text{dy}}}}{{{\text{dx}}}}\] will be equal to
Correct Answer: Option C — tan\[\left( {\frac{\theta }{2}} \right)\]
Detailed Academic Explanation:
tan\[\left( {\frac{\theta }{2}} \right)\] is the correct answer to “If x = a (θ + sin θ) and y = a (1 - cos θ), then \[\frac{{{\text{dy}}}}{{{\text{dx}}}}\] will be equal to”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 6 of 40
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Consider the line integral \[\int\limits_{\text{C}} {\left( {{\text{xdy}} - {\text{ydx}}} \right)} \] the integral being taken in a counterclockwise direction over the closed curve C that forms the boundary of the region R shown in the figure below. The region R is the area enclosed by the union of a 2 × 3 rectangle and a semi-circle of radius 1. The line integral evaluates to
Correct Answer: Option A — \[12 + \pi \]
Detailed Academic Explanation:
\[12 + \pi \] is the correct answer to “Consider the line integral \[\int\limits_{\text{C}} {\left( {{\text{xdy}} - {\text{ydx}}} \right)} \] the integral being taken in a counterclockwise direction over the closed curve C that forms the boundary of the region R shown in the figure below. The region R is the area enclosed by the union of a 2 × 3 rectangle and a semi-circle of radius 1. The line integral evaluates to”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 7 of 40
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Consider the shaded triangular region P shown in the figure. What is If $$\iint\limits_{\text{P}} {{\text{xydxdy}}\,?}$$
Correct Answer: Option A — \[\frac{1}{6}\]
Detailed Academic Explanation:
\[\frac{1}{6}\] is the correct answer to “Consider the shaded triangular region P shown in the figure. What is If $$\iint\limits_{\text{P}} {{\text{xydxdy}}\,?}$$”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 8 of 40
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Let \[\phi \] be an arbitrary smooth real valued scalar function and V be an arbitrary smooth vector valued function in a three-dimensional space. Which one of the following is an identity?
\[{\text{Div Curl }}\overrightarrow {\text{V}} = 0\] is the correct answer to “Let \[\phi \] be an arbitrary smooth real valued scalar function and V be an arbitrary smooth vector valued function in a three-dimensional space. Which one of the following is an identity”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 9 of 40
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The magnitude of the directional derivative of the function f(x, y) = x 2 + 3y 2 in a direction normal to the circle x 2 + y 2 = 2, at the point (1, 1), is
Correct Answer: Option A — 4√2
Detailed Academic Explanation:
4√2 is the correct answer to “The magnitude of the directional derivative of the function f(x, y) = x 2 + 3y 2 in a direction normal to the circle x 2 + y 2 = 2, at the point (1, 1), is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 10 of 40
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If $${\text{S}} = \int\limits_1^\infty {{{\text{x}}^{ - 3}}{\text{dx,}}} $$ then S has the value
Correct Answer: Option C — $$\frac{1}{2}$$
Detailed Academic Explanation:
$$\frac{1}{2}$$ is the correct answer to “If $${\text{S}} = \int\limits_1^\infty {{{\text{x}}^{ - 3}}{\text{dx,}}} $$ then S has the value”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 11 of 40
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The function f(x) = 2x 3 - 3x 2 - 36x + 2 has its maxima at
Correct Answer: Option A — x = -2 only
Detailed Academic Explanation:
x = -2 only is the correct answer to “The function f(x) = 2x 3 - 3x 2 - 36x + 2 has its maxima at”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 12 of 40
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The minimum value of the function $${\text{f}}\left( {\text{x}} \right) = \left( {\frac{{{{\text{x}}^3}}}{3}} \right) - {\text{x}}$$ occurs at
Correct Answer: Option A — x = 1
Detailed Academic Explanation:
x = 1 is the correct answer to “The minimum value of the function $${\text{f}}\left( {\text{x}} \right) = \left( {\frac{{{{\text{x}}^3}}}{3}} \right) - {\text{x}}$$ occurs at”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 13 of 40
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The function f(x) = 2x - x 2 + 3 has
Correct Answer: Option C — only a maxima at x = 1
Detailed Academic Explanation:
only a maxima at x = 1 is the correct answer to “The function f(x) = 2x - x 2 + 3 has”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 14 of 40
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The function y = |2 - 3x|
Correct Answer: Option C — is continuous $$\forall {\text{x}} \in {\text{R}}$$ and differentiable $$\forall {\text{x}} \in {\text{R}}$$ except at x = $$\frac{2}{3}$$
Detailed Academic Explanation:
is continuous $$\forall {\text{x}} \in {\text{R}}$$ and differentiable $$\forall {\text{x}} \in {\text{R}}$$ except at x = $$\frac{2}{3}$$ is the correct answer to “The function y = |2 - 3x|”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 15 of 40
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The double integral $$\int\limits_0^{\text{a}} {\int\limits_0^{\text{y}} {{\text{f}}\left( {{\text{x, y}}} \right){\text{dx dy}}} } $$ is equivalent to
$$\int\limits_0^{\text{a}} {\int\limits_{\text{x}}^{\text{a}} {{\text{f}}\left( {{\text{x, y}}} \right){\text{dy dx}}} } $$ is the correct answer to “The double integral $$\int\limits_0^{\text{a}} {\int\limits_0^{\text{y}} {{\text{f}}\left( {{\text{x, y}}} \right){\text{dx dy}}} } $$ is equivalent to”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 16 of 40
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The values of x for which the function $${\text{f}}\left( {\text{x}} \right) = \frac{{{{\text{x}}^2} - 3{\text{x}} - 4}}{{{{\text{x}}^2} + 3{\text{x}} - 4}}$$ is NOT continuous are
Correct Answer: Option C — -4 and 1
Detailed Academic Explanation:
-4 and 1 is the correct answer to “The values of x for which the function $${\text{f}}\left( {\text{x}} \right) = \frac{{{{\text{x}}^2} - 3{\text{x}} - 4}}{{{{\text{x}}^2} + 3{\text{x}} - 4}}$$ is NOT continuous are”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 17 of 40
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The expression $${\text{V}} = \int_0^{\text{H}} {\pi {{\text{R}}^2}{{\left( {1 - \frac{{\text{h}}}{{\text{H}}}} \right)}^2}} {\text{dh}}$$ for the volume of a cone is equal to
$$4\int_0^{\text{R}} {\pi {\text{rH}}{{\left( {1 - \frac{{\text{r}}}{{\text{R}}}} \right)}^2}} {\text{dr}}$$ is the correct answer to “The expression $${\text{V}} = \int_0^{\text{H}} {\pi {{\text{R}}^2}{{\left( {1 - \frac{{\text{h}}}{{\text{H}}}} \right)}^2}} {\text{dh}}$$ for the volume of a cone is equal to”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 18 of 40
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Consider the function f(x) = |x| in the interval -1 < x ≤ 1. At the point x = 0, f(x) is
Correct Answer: Option C — continuous and non-differentiable
Detailed Academic Explanation:
continuous and non-differentiable is the correct answer to “Consider the function f(x) = |x| in the interval -1 < x ≤ 1. At the point x = 0, f(x) is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 19 of 40
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For a scalar function f(x, y, z) = x 2 + 3y 2 + 2z 2 , the gradient at the point P(1, 2, -1) is
$$2\overrightarrow {\text{i}} + 12\overrightarrow {\text{j}} - 4\overrightarrow {\text{k}} $$ is the correct answer to “For a scalar function f(x, y, z) = x 2 + 3y 2 + 2z 2 , the gradient at the point P(1, 2, -1) is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 20 of 40
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The value of the quantity P, where $${\text{P}} = \int\limits_0^1 {{\text{x}}{{\text{e}}^{\text{x}}}{\text{dx,}}} $$ is equal to
Correct Answer: Option B — 1
Detailed Academic Explanation:
1 is the correct answer to “The value of the quantity P, where $${\text{P}} = \int\limits_0^1 {{\text{x}}{{\text{e}}^{\text{x}}}{\text{dx,}}} $$ is equal to”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 21 of 40
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What is the value of $$\mathop {\lim }\limits_{{\text{x}} \to \frac{\pi }{4}} \frac{{\cos {\text{x}} - \sin {\text{x}}}}{{{\text{x}} - \frac{\pi }{4}}}$$
Correct Answer: Option C — -√2
Detailed Academic Explanation:
-√2 is the correct answer to “What is the value of $$\mathop {\lim }\limits_{{\text{x}} \to \frac{\pi }{4}} \frac{{\cos {\text{x}} - \sin {\text{x}}}}{{{\text{x}} - \frac{\pi }{4}}}$$”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 22 of 40
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The value of $$\mathop {\lim }\limits_{{\text{x}} \to \infty } {\left( {1 + {{\text{x}}^2}} \right)^{{{\text{e}}^{ - {\text{x}}}}}}$$ is
Correct Answer: Option C — 1
Detailed Academic Explanation:
1 is the correct answer to “The value of $$\mathop {\lim }\limits_{{\text{x}} \to \infty } {\left( {1 + {{\text{x}}^2}} \right)^{{{\text{e}}^{ - {\text{x}}}}}}$$ is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 23 of 40
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For a right angled triangle, if the sum of the lengths of the hypotenuse and a side is kept constant, in order to have maximum area of the triangle, the angle between the hypotenuse and the side is
Correct Answer: Option C — 60°
Detailed Academic Explanation:
60° is the correct answer to “For a right angled triangle, if the sum of the lengths of the hypotenuse and a side is kept constant, in order to have maximum area of the triangle, the angle between the hypotenuse and the side is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 24 of 40
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The value of $$\mathop {\lim }\limits_{{\text{x}} \to 8} \frac{{{{\text{x}}^{\frac{1}{3}}} - 2}}{{\left( {{\text{x}} - 8} \right)}}$$
Correct Answer: Option B — $$\frac{1}{{12}}$$
Detailed Academic Explanation:
$$\frac{1}{{12}}$$ is the correct answer to “The value of $$\mathop {\lim }\limits_{{\text{x}} \to 8} \frac{{{{\text{x}}^{\frac{1}{3}}} - 2}}{{\left( {{\text{x}} - 8} \right)}}$$”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 25 of 40
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The vector that is NOT perpendicular to the vectors (i + j + k) and (i + 2j + 3k) is . . . . . . . .
Correct Answer: Option D — (4i + 3j + 5k)
Detailed Academic Explanation:
(4i + 3j + 5k) is the correct answer to “The vector that is NOT perpendicular to the vectors (i + j + k) and (i + 2j + 3k) is . . . . . . . .”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 26 of 40
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Given $${\text{i}} = \sqrt { - 1} ,$$ what will be the evaluation of the definite integral $$\int_0^{\frac{\pi }{2}} {\frac{{\cos {\text{x}} + {\text{i}}\sin {\text{x}}}}{{\cos {\text{x}} - {\text{i}}\sin {\text{x}}}}} {\text{dx}}\,?$$
Correct Answer: Option D — i
Detailed Academic Explanation:
i is the correct answer to “Given $${\text{i}} = \sqrt { - 1} ,$$ what will be the evaluation of the definite integral $$\int_0^{\frac{\pi }{2}} {\frac{{\cos {\text{x}} + {\text{i}}\sin {\text{x}}}}{{\cos {\text{x}} - {\text{i}}\sin {\text{x}}}}} {\text{dx}}\,?$$”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 27 of 40
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At x = 0, the function $${\text{f}}\left( {\text{x}} \right) = \left| {\sin \frac{{2\pi {\text{x}}}}{{\text{L}}}} \right|$$ , (-$$\infty $$ < x < $$\infty $$, L > 0) is
Correct Answer: Option D — Continuous but not differentiable
Detailed Academic Explanation:
Continuous but not differentiable is the correct answer to “At x = 0, the function $${\text{f}}\left( {\text{x}} \right) = \left| {\sin \frac{{2\pi {\text{x}}}}{{\text{L}}}} \right|$$ , (-$$\infty $$ < x < $$\infty $$, L > 0) is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 28 of 40
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The value of $$\int_0^\infty {\frac{1}{{1 + {{\text{x}}^2}}}} {\text{dx}} + \int_0^\infty {\frac{{\sin {\text{x}}}}{{\text{x}}}} {\text{dx}}$$ is
Correct Answer: Option B — $$\pi $$
Detailed Academic Explanation:
$$\pi $$ is the correct answer to “The value of $$\int_0^\infty {\frac{1}{{1 + {{\text{x}}^2}}}} {\text{dx}} + \int_0^\infty {\frac{{\sin {\text{x}}}}{{\text{x}}}} {\text{dx}}$$ is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 29 of 40
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The values of the integrals $$\int\limits_0^1 {\left( {\int\limits_0^1 {\frac{{{\text{x}} - {\text{y}}}}{{{{\left( {{\text{x}} + {\text{y}}} \right)}^3}}}{\text{dy}}} } \right){\text{dx}}} $$ and $$\int\limits_0^1 {\left( {\int\limits_0^1 {\frac{{{\text{x}} - {\text{y}}}}{{{{\left( {{\text{x}} + {\text{y}}} \right)}^3}}}{\text{dx}}} } \right){\text{dy}}} $$ are
Correct Answer: Option C — 0.5 and -0.5 respectively
Detailed Academic Explanation:
0.5 and -0.5 respectively is the correct answer to “The values of the integrals $$\int\limits_0^1 {\left( {\int\limits_0^1 {\frac{{{\text{x}} - {\text{y}}}}{{{{\left( {{\text{x}} + {\text{y}}} \right)}^3}}}{\text{dy}}} } \right){\text{dx}}} $$ and $$\int\limits_0^1 {\left( {\int\limits_0^1 {\frac{{{\text{x}} - {\text{y}}}}{{{{\left( {{\text{x}} + {\text{y}}} \right)}^3}}}{\text{dx}}} } \right){\text{dy}}} $$ are”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 30 of 40
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$$\overrightarrow {\text{a}} ,\,\overrightarrow {\text{b}} ,\,\overrightarrow {\text{c}} $$ are three orthogonal vectors, Given that \[\overrightarrow {\rm{a}} = {\rm{\hat i}} + 2{\rm{\hat j}} + 5{\rm{\hat k}}\] and \[\overrightarrow {\rm{b}} = {\rm{\hat i}} + 2{\rm{\hat j}} - {\rm{\hat k}}\] , the vector $$\,\overrightarrow {\text{c}} $$ is parallel to
Correct Answer: Option C — \[{\rm{2\hat i}} - {\rm{\hat j}}\]
Detailed Academic Explanation:
\[{\rm{2\hat i}} - {\rm{\hat j}}\] is the correct answer to “$$\overrightarrow {\text{a}} ,\,\overrightarrow {\text{b}} ,\,\overrightarrow {\text{c}} $$ are three orthogonal vectors, Given that \[\overrightarrow {\rm{a}} = {\rm{\hat i}} + 2{\rm{\hat j}} + 5{\rm{\hat k}}\] and \[\overrightarrow {\rm{b}} = {\rm{\hat i}} + 2{\rm{\hat j}} - {\rm{\hat k}}\] , the vector $$\,\overrightarrow {\text{c}} $$ is parallel to”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 31 of 40
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Given $$\overrightarrow {\text{F}} = \left( {{{\text{x}}^2} - 2{\text{y}}} \right)\overrightarrow {\text{i}} - 4{\text{yz}}\overrightarrow {\text{j}} + 4{\text{x}}{{\text{z}}^2}\overrightarrow {\text{k}} ,$$ the value of the line integral $$\int\limits_{\text{c}} {\overrightarrow {\text{F}} \cdot d\overrightarrow l } $$ along the straight line c from (0, 0, 0) to (1,1,1) is
Correct Answer: Option D — -1
Detailed Academic Explanation:
-1 is the correct answer to “Given $$\overrightarrow {\text{F}} = \left( {{{\text{x}}^2} - 2{\text{y}}} \right)\overrightarrow {\text{i}} - 4{\text{yz}}\overrightarrow {\text{j}} + 4{\text{x}}{{\text{z}}^2}\overrightarrow {\text{k}} ,$$ the value of the line integral $$\int\limits_{\text{c}} {\overrightarrow {\text{F}} \cdot d\overrightarrow l } $$ along the straight line c from (0, 0, 0) to (1,1,1) is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 32 of 40
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At x = 0, the function f(x) = |x| has
Correct Answer: Option A — a minimum
Detailed Academic Explanation:
a minimum is the correct answer to “At x = 0, the function f(x) = |x| has”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 33 of 40
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A parabola x = y 2 with 0 ≤ x ≤ 1 is shown in the figure. The volume of the solid of rotation obtained by rotating the shaded area by 360° around the x-axis is
Correct Answer: Option C — $$\frac{\pi }{2}$$
Detailed Academic Explanation:
$$\frac{\pi }{2}$$ is the correct answer to “A parabola x = y 2 with 0 ≤ x ≤ 1 is shown in the figure. The volume of the solid of rotation obtained by rotating the shaded area by 360° around the x-axis is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 34 of 40
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The line integral $$\int\limits_{{{\text{P}}_1}}^{{{\text{P}}_2}} {\left( {{\text{ydx}} + {\text{xdy}}} \right)} $$ for P 1 (x 1 , y 1 ) to P 2 (x 2 , y 2 ) along the semicircle P 1 , P 2 shown in the figure is
Correct Answer: Option A — x2y2 - x1y1
Detailed Academic Explanation:
x2y2 - x1y1 is the correct answer to “The line integral $$\int\limits_{{{\text{P}}_1}}^{{{\text{P}}_2}} {\left( {{\text{ydx}} + {\text{xdy}}} \right)} $$ for P 1 (x 1 , y 1 ) to P 2 (x 2 , y 2 ) along the semicircle P 1 , P 2 shown in the figure is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 35 of 40
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The angle between two unit-magnitude coplanar vectors P(0.866, 0.500, 0) and Q(0.259, 0.966, 0) will be
Correct Answer: Option C — 45°
Detailed Academic Explanation:
45° is the correct answer to “The angle between two unit-magnitude coplanar vectors P(0.866, 0.500, 0) and Q(0.259, 0.966, 0) will be”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 36 of 40
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The following surface integral is to be evaluated over a sphere for the given steady velocity vector field F = xi + yj + zk defined with respect to a Cartesian coordinate system having i, j and k as unit base vectors. $$\iint\limits_{\text{S}} {\frac{1}{4}\left( {{\text{F}} \cdot {\text{n}}} \right){\text{dA}}}$$ where S is the sphere, x 2 + y 2 + z 2 = 1 and n is the outward unit normal vector to the sphere. The value of the surface integral is
Correct Answer: Option A — $$\pi $$
Detailed Academic Explanation:
$$\pi $$ is the correct answer to “The following surface integral is to be evaluated over a sphere for the given steady velocity vector field F = xi + yj + zk defined with respect to a Cartesian coordinate system having i, j and k as unit base vectors. $$\iint\limits_{\text{S}} {\frac{1}{4}\left( {{\text{F}} \cdot {\text{n}}} \right){\text{dA}}}$$ where S is the sphere, x 2 + y 2 + z 2 = 1 and n is the outward unit normal vector to the sphere. The value of the surface integral is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 37 of 40
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If a function is continuous at a point,
Correct Answer: Option D — the limit must exist at the point and the value of limit should be same as the value of the function at that point
Detailed Academic Explanation:
the limit must exist at the point and the value of limit should be same as the value of the function at that point is the correct answer to “If a function is continuous at a point,”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 38 of 40
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The vector that is normal to the surface 2xz 2 - 3xy - 4x = 7 at the point (1, -1, 2) is
Correct Answer: Option C — 7i - 3j + 8k
Detailed Academic Explanation:
7i - 3j + 8k is the correct answer to “The vector that is normal to the surface 2xz 2 - 3xy - 4x = 7 at the point (1, -1, 2) is”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 39 of 40
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The polynomial p(x) = x 5 + x + 2 has
Correct Answer: Option C — 1 real and 4 complex roots
Detailed Academic Explanation:
1 real and 4 complex roots is the correct answer to “The polynomial p(x) = x 5 + x + 2 has”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
Question 40 of 40
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A function y = 5x 2 + 10x is defined over an open interval x = (1, 2). At least at one point in this interval, $$\frac{{{\text{dy}}}}{{{\text{dx}}}}$$ is exactly
Correct Answer: Option B — 25
Detailed Academic Explanation:
25 is the correct answer to “A function y = 5x 2 + 10x is defined over an open interval x = (1, 2). At least at one point in this interval, $$\frac{{{\text{dy}}}}{{{\text{dx}}}}$$ is exactly”. This question is standard in competitive examination syllabi for Calculus.
💡Key Conceptual Anchor:Calculus
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Algebra — Part 1
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💡Examiner's Advisory for Mathematics & Quantitative Ability
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.