Classical Mechanics — Part 1 MCQs with Explanations
Practice high-yield Physics & Applied Physics MCQs on Classical Mechanics — Part 1 with worked academic solutions for MDCAT, CSS, PMS, PPSC, FPSC.
Questions
40
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MDCAT, CSS, PMS...
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Exam-Level MDCAT CSS PMS PPSC FPSC
Verified for Commission Syllabus • Oct 14, 2026
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Question 1 of 40
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A planet moves around the sun in an elliptical orbit with semi-major axis a and time period T. T is proportional to
Correct Answer: Option D — $${{\text{a}}^{\frac{3}{2}}}$$
Detailed Academic Explanation:
According to Kepler's third law , the square of the period of revolution (T) of a planet around the sun is proportional to the cube of the semi-major axis (a) of its elliptical orbit. Thus, T 2 ∝a 3 Taking the square root on both sides, we get: $$T∝ {{\text{a}}^{\frac{3}{2}}}$$ Hence, the time period (T) is proportional to $${{\text{a}}^{\frac{3}{2}}}$$ which corresponds to Option D .
💡Key Conceptual Anchor:Classical Mechanics
Question 2 of 40
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A mass m is constrained to move on a horizontal frictionless surface. It is set in circular motion with radius r 0 and angular speed ω 0 by an applied force $$\overrightarrow {\bf{F}} $$ communicated through an inextensible thread that passesthrough a hole on the surface as shown in figure given below. Then, this force is suddenly doubled. The magnitude of the radial velocity of the mass
Correct Answer: Option D — becomes zero at radius r1, where 0 < r1 < r0
Detailed Academic Explanation:
becomes zero at radius r1, where 0 < r1 < r0 is the correct answer to “A mass m is constrained to move on a horizontal frictionless surface. It is set in circular motion with radius r 0 and angular speed ω 0 by an applied force $$\overrightarrow {\bf{F}} $$ communicated through an inextensible thread that passesthrough a hole on the surface as shown in figure given below. Then, this force is suddenly doubled. The magnitude of the radial velocity of the mass”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 3 of 40
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The speed of a particle whose kinetic energy is equal to its rest mass energy, is given by (c is the speed of light in vacuum)
Correct Answer: Option D — $$\frac{{\sqrt 3 }}{2}c$$
Detailed Academic Explanation:
$$\frac{{\sqrt 3 }}{2}c$$ is the correct answer to “The speed of a particle whose kinetic energy is equal to its rest mass energy, is given by (c is the speed of light in vacuum)”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 4 of 40
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The Hamiltonian corresponding to the Lagrangian $$L = a{{\dot x}^2} + b{{\dot y}^2} - kxy$$ is
Correct Answer: Option C — $$\frac{{{p_x}^2}}{{4a}} + \frac{{{p_y}^2}}{{4b}} + kxy$$
Detailed Academic Explanation:
$$\frac{{{p_x}^2}}{{4a}} + \frac{{{p_y}^2}}{{4b}} + kxy$$ is the correct answer to “The Hamiltonian corresponding to the Lagrangian $$L = a{{\dot x}^2} + b{{\dot y}^2} - kxy$$ is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 5 of 40
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A particle is moving in an inverse square field. If the total energy of the particle is positive, then trajectory of particle is
Correct Answer: Option C — parabolic
Detailed Academic Explanation:
parabolic is the correct answer to “A particle is moving in an inverse square field. If the total energy of the particle is positive, then trajectory of particle is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 6 of 40
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An object of mass m rests on a surface with coefficient of static friction μ. Which of the following is not correct?
Correct Answer: Option B — The maximum force of friction is μmg
Detailed Academic Explanation:
The maximum force of friction is μmg is the correct answer to “An object of mass m rests on a surface with coefficient of static friction μ. Which of the following is not correct”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 7 of 40
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Two solid spheres of radius R and mass M each are connected by a thin rigid rod of negligible mass. The distance between the centre is 4R. The moment of inertia about an axis passing through the centre of symmetry and perpendicular to the line joining the sphere is
Correct Answer: Option C — $$\frac{{44}}{5}M{R^2}$$
Detailed Academic Explanation:
$$\frac{{44}}{5}M{R^2}$$ is the correct answer to “Two solid spheres of radius R and mass M each are connected by a thin rigid rod of negligible mass. The distance between the centre is 4R. The moment of inertia about an axis passing through the centre of symmetry and perpendicular to the line joining the sphere is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 8 of 40
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A circular hoop of mass M and radius a rolls without slipping with constant angular speed ω along the horizontal X-axis in the X-Y plane. When the hoop is at a distance d = $$\sqrt 2 $$ a from the origin, the magnitude of the total angular momentum of the hoop about the origin is
Correct Answer: Option C — 2Ma2ω
Detailed Academic Explanation:
2Ma2ω is the correct answer to “A circular hoop of mass M and radius a rolls without slipping with constant angular speed ω along the horizontal X-axis in the X-Y plane. When the hoop is at a distance d = $$\sqrt 2 $$ a from the origin, the magnitude of the total angular momentum of the hoop about the origin is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 9 of 40
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Hamiltonian canonical equations of motion for a conservation system are
Correct Answer: Option D — $$\frac{{d{q_i}}}{{dt}} = \frac{{\partial H}}{{\partial {P_i}}}{\text{ and }}\frac{{ - d{P_i}}}{{dt}} = \frac{{\partial H}}{{\partial {q_i}}}$$
Detailed Academic Explanation:
$$\frac{{d{q_i}}}{{dt}} = \frac{{\partial H}}{{\partial {P_i}}}{\text{ and }}\frac{{ - d{P_i}}}{{dt}} = \frac{{\partial H}}{{\partial {q_i}}}$$ is the correct answer to “Hamiltonian canonical equations of motion for a conservation system are”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 10 of 40
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A cylinder of mass M and radius R is rolling down without slipping on an inclined plane of angle of inclination θ. The number of generalised coordinate required to describe the motion of the system is
Correct Answer: Option B — 2
Detailed Academic Explanation:
2 is the correct answer to “A cylinder of mass M and radius R is rolling down without slipping on an inclined plane of angle of inclination θ. The number of generalised coordinate required to describe the motion of the system is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 11 of 40
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A particle moves in a central force field $$\overrightarrow {\bf{F}} = k{r^n}{\bf{\hat r}},$$ where k is constant, r is distance of the particle from the origin and $${{\bf{\hat r}}}$$ is the unit vector in the direction of $$\overrightarrow {\bf{r}} $$. Closed stable orbits are possible for
Correct Answer: Option D — n = 1 and n = -2
Detailed Academic Explanation:
n = 1 and n = -2 is the correct answer to “A particle moves in a central force field $$\overrightarrow {\bf{F}} = k{r^n}{\bf{\hat r}},$$ where k is constant, r is distance of the particle from the origin and $${{\bf{\hat r}}}$$ is the unit vector in the direction of $$\overrightarrow {\bf{r}} $$. Closed stable orbits are possible for”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 12 of 40
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The moment of inertia of a uniform sphere of radius, r about an axis passing through its centre is given by $$\frac{2}{5}\left( {\frac{{4\pi }}{3}{r^5}\rho } \right).$$ A rigid sphere of uniform mass density $$\rho $$ and radius R has two smaller spheres of radii $$\frac{R}{2}$$ hollowed out of it as shown in the figure given below. The moment of inertia of the resulting body about Y-axis is
Correct Answer: Option B — $$\frac{{5\pi \rho {R^5}}}{{12}}$$
Detailed Academic Explanation:
$$\frac{{5\pi \rho {R^5}}}{{12}}$$ is the correct answer to “The moment of inertia of a uniform sphere of radius, r about an axis passing through its centre is given by $$\frac{2}{5}\left( {\frac{{4\pi }}{3}{r^5}\rho } \right).$$ A rigid sphere of uniform mass density $$\rho $$ and radius R has two smaller spheres of radii $$\frac{R}{2}$$ hollowed out of it as shown in the figure given below. The moment of inertia of the resulting body about Y-axis is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 13 of 40
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The mass m of a moving particle is $$\frac{{2{m_0}}}{{\sqrt 3 }},$$ where m 0 is rest mass. The linear momentum of the particle is
Correct Answer: Option D — $$\frac{{{m_0}c}}{{\sqrt 3 }}$$
Detailed Academic Explanation:
$$\frac{{{m_0}c}}{{\sqrt 3 }}$$ is the correct answer to “The mass m of a moving particle is $$\frac{{2{m_0}}}{{\sqrt 3 }},$$ where m 0 is rest mass. The linear momentum of the particle is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 14 of 40
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A space station moving in a circular orbit around the earth goes into a new bound orbit by fixing its engine radially outwards. This orbit is
Correct Answer: Option C — an ellipse
Detailed Academic Explanation:
an ellipse is the correct answer to “A space station moving in a circular orbit around the earth goes into a new bound orbit by fixing its engine radially outwards. This orbit is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 15 of 40
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A particle of mass m is attached to a thin uniform rod of length a and mass 4m. The distance of the particle from the centre of mass of the rod is $$\frac{a}{2}.$$ The moment of inertia of the combination about an axis passing through a normal to the rod is
Correct Answer: Option B — $$\frac{{91}}{{48}}m{a^2}$$
Detailed Academic Explanation:
$$\frac{{91}}{{48}}m{a^2}$$ is the correct answer to “A particle of mass m is attached to a thin uniform rod of length a and mass 4m. The distance of the particle from the centre of mass of the rod is $$\frac{a}{2}.$$ The moment of inertia of the combination about an axis passing through a normal to the rod is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 16 of 40
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The Poisson bracket between $$\theta $$ and $${\dot \theta }$$ is
$$\left\{ {\theta ,\,\dot \theta } \right\} = 1$$ is the correct answer to “The Poisson bracket between $$\theta $$ and $${\dot \theta }$$ is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 17 of 40
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If p and q are the position and momentum variables, which one of the following is not canonical transformation?
Correct Answer: Option C — Q = p and P = q
Detailed Academic Explanation:
Q = p and P = q is the correct answer to “If p and q are the position and momentum variables, which one of the following is not canonical transformation”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 18 of 40
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A rigid body is rotating about its centre of mass; fixed at origin with an angular velocity $$\overrightarrow \omega $$ and angular acceleration $$\overrightarrow \alpha $$. If the torque acting on it is $$\overrightarrow \tau $$ and its angular momentum is $$\overrightarrow {\bf{L}} $$, then the rate of change of its kinetic energy is
$$\frac{1}{2}\left( {\overrightarrow \tau \cdot \overrightarrow \omega + \overrightarrow {\bf{L}} \cdot \overrightarrow \alpha } \right)$$ is the correct answer to “A rigid body is rotating about its centre of mass; fixed at origin with an angular velocity $$\overrightarrow \omega $$ and angular acceleration $$\overrightarrow \alpha $$. If the torque acting on it is $$\overrightarrow \tau $$ and its angular momentum is $$\overrightarrow {\bf{L}} $$, then the rate of change of its kinetic energy is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 19 of 40
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The homogeneity of time leads to the law of conservation of (a)
Correct Answer: Option C — energy
Detailed Academic Explanation:
energy is the correct answer to “The homogeneity of time leads to the law of conservation of (a)”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 20 of 40
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A rigid frictionless rod rotates anticlockwise in a vertical plane with angular velocity $$\overrightarrow \omega $$. A bead of mass m moves outward along the rod with constant velocity $$\overrightarrow {{u_0}} $$ . The bead will experience a coriolis force
$$ - 2m{u_0}\omega \hat \theta $$ is the correct answer to “A rigid frictionless rod rotates anticlockwise in a vertical plane with angular velocity $$\overrightarrow \omega $$. A bead of mass m moves outward along the rod with constant velocity $$\overrightarrow {{u_0}} $$ . The bead will experience a coriolis force”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 21 of 40
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The Lagrangian for a three-particle system is given by $$L = \frac{1}{2}\left( {\dot n_1^2 + \dot n_2^2 + \dot n_3^2} \right) - {a^2}\left( {n_1^2 + n_2^2 + n_3^2 - {n_1}{n_3}} \right)$$ where, a is real, then one of the normal coordinates has a frequency $$\omega $$ given by
Correct Answer: Option C — $${\omega ^2} = 2{a^2}$$
Detailed Academic Explanation:
$${\omega ^2} = 2{a^2}$$ is the correct answer to “The Lagrangian for a three-particle system is given by $$L = \frac{1}{2}\left( {\dot n_1^2 + \dot n_2^2 + \dot n_3^2} \right) - {a^2}\left( {n_1^2 + n_2^2 + n_3^2 - {n_1}{n_3}} \right)$$ where, a is real, then one of the normal coordinates has a frequency $$\omega $$ given by”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 22 of 40
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For the given transformation 1. Q = p and P = -q 2. P = q and Q = p where p, q are canonically conjugate variables, which one of the following statements is true?
Correct Answer: Option B — Only 1 is canonical
Detailed Academic Explanation:
Only 1 is canonical is the correct answer to “For the given transformation 1. Q = p and P = -q 2. P = q and Q = p where p, q are canonically conjugate variables, which one of the following statements is true”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 23 of 40
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The Lagrangian for a simple pendulum is given by $$L = \frac{1}{2}m{L^2}{{\dot \theta }^2} - mgL\left( {1 - \cos \theta } \right)$$ Hamiltonian equations are given by
$${{\dot p}_\theta } = - mgL\,\sin \theta ,\,\dot \theta = \frac{{{p_\theta }}}{{m{L^2}}}$$ is the correct answer to “The Lagrangian for a simple pendulum is given by $$L = \frac{1}{2}m{L^2}{{\dot \theta }^2} - mgL\left( {1 - \cos \theta } \right)$$ Hamiltonian equations are given by”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 24 of 40
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Two events are separated by a distance of 6 × 10 5 km and the first event occurs 1 s before the second event. The interval between two events is
Correct Answer: Option D — Cannot be determined from the information given
Detailed Academic Explanation:
Cannot be determined from the information given is the correct answer to “Two events are separated by a distance of 6 × 10 5 km and the first event occurs 1 s before the second event. The interval between two events is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 25 of 40
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The lagrangian of a particle of mass m moving in one dimension is $$L = \exp \left[ {\left( {\alpha t} \right)\frac{{M{{\dot x}^2}}}{2} - k{x^2}} \right]$$ where, $$\alpha $$ and k are positive constants. The equation of motion of the particle is
Correct Answer: Option D — $$\ddot x + \alpha \dot x + \frac{k}{m}x = 0$$
Detailed Academic Explanation:
$$\ddot x + \alpha \dot x + \frac{k}{m}x = 0$$ is the correct answer to “The lagrangian of a particle of mass m moving in one dimension is $$L = \exp \left[ {\left( {\alpha t} \right)\frac{{M{{\dot x}^2}}}{2} - k{x^2}} \right]$$ where, $$\alpha $$ and k are positive constants. The equation of motion of the particle is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 26 of 40
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Although mass energy equivalence of special relativity allows conversion of a photon to an electron-positron pair, such a process cannot occur in free space because
Correct Answer: Option B — energy is not conserved
Detailed Academic Explanation:
energy is not conserved is the correct answer to “Although mass energy equivalence of special relativity allows conversion of a photon to an electron-positron pair, such a process cannot occur in free space because”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 27 of 40
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The Lagrangian forthe Kepler problem is given by $$L = \frac{1}{2}\left[ {{{\dot r}^2} + {r^2}{{\dot \theta }^2}} \right] + \frac{\mu }{r}\,\,\,\,\,\,\,\left( {\mu > 0} \right)$$ where, $$\left( {r,\,\theta } \right)$$ denotes the polar coordinates and mass of the particle is unity, then
Correct Answer: Option C — the angular momentum of the particle about the centre of attraction is a constant
Detailed Academic Explanation:
the angular momentum of the particle about the centre of attraction is a constant is the correct answer to “The Lagrangian forthe Kepler problem is given by $$L = \frac{1}{2}\left[ {{{\dot r}^2} + {r^2}{{\dot \theta }^2}} \right] + \frac{\mu }{r}\,\,\,\,\,\,\,\left( {\mu > 0} \right)$$ where, $$\left( {r,\,\theta } \right)$$ denotes the polar coordinates and mass of the particle is unity, then”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 28 of 40
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For a simple harmonic oscillator, the Lagrangian is $$L = \frac{1}{2}{{\dot q}^2} - \frac{1}{2}{q^2},\,{\text{if }}A\left( {p,\,q} \right) = \frac{{p + iq}}{2}$$ and H(p, q) is the Hamiltonian of the system, the Poisson bracket, {A(p, q), H(p, q)} is given by
Correct Answer: Option A — iA (p, q)
Detailed Academic Explanation:
iA (p, q) is the correct answer to “For a simple harmonic oscillator, the Lagrangian is $$L = \frac{1}{2}{{\dot q}^2} - \frac{1}{2}{q^2},\,{\text{if }}A\left( {p,\,q} \right) = \frac{{p + iq}}{2}$$ and H(p, q) is the Hamiltonian of the system, the Poisson bracket, {A(p, q), H(p, q)} is given by”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 29 of 40
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A bead of mass m slides along a straight frictionless rigid wire rotating in a horizontal plane with a constant angular speed ω. The axis of rotation is perpendicular to the wire and passes through one end of the wire. If r is the distance of the mass from the axis of rotation and v is its speed, then the magnitude of the Coriolis force is
Correct Answer: Option D — 2mvω
Detailed Academic Explanation:
2mvω is the correct answer to “A bead of mass m slides along a straight frictionless rigid wire rotating in a horizontal plane with a constant angular speed ω. The axis of rotation is perpendicular to the wire and passes through one end of the wire. If r is the distance of the mass from the axis of rotation and v is its speed, then the magnitude of the Coriolis force is”. This question is standard in competitive examination syllabi for Classical Mechanics.
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Question 30 of 40
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If for a system of N particles of different masses m 1 , m 2 , . . . m N with position vectors $${\overrightarrow {\bf{r}} _1},\,{\overrightarrow {\bf{r}} _2},\,.\,.\,.\,{\overrightarrow {\bf{r}} _N}$$ and corresponding velocities $${\overrightarrow {\bf{v}} _1},\,{\overrightarrow {\bf{v}} _2},\,.\,.\,.\,{\overrightarrow {\bf{v}} _N}$$ respectively such that $$\sum\limits_i {\overrightarrow {{{\bf{v}}_i}} = 0,} $$ then
Correct Answer: Option C — the total force on the system must be zero
Detailed Academic Explanation:
the total force on the system must be zero is the correct answer to “If for a system of N particles of different masses m 1 , m 2 , . . . m N with position vectors $${\overrightarrow {\bf{r}} _1},\,{\overrightarrow {\bf{r}} _2},\,.\,.\,.\,{\overrightarrow {\bf{r}} _N}$$ and corresponding velocities $${\overrightarrow {\bf{v}} _1},\,{\overrightarrow {\bf{v}} _2},\,.\,.\,.\,{\overrightarrow {\bf{v}} _N}$$ respectively such that $$\sum\limits_i {\overrightarrow {{{\bf{v}}_i}} = 0,} $$ then”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 31 of 40
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The Lagrangian of a free particle in spherical polar coordinates is given by $$L = \frac{1}{2}m\left[ {{{\dot r}^2} + r{{\dot \theta }^2} + {r^2}{{\dot \phi }^2}{{\sin }^2}\theta } \right]$$ The quantity that conserved is
Correct Answer: Option C — $$\frac{{\partial L}}{{\partial \dot \phi }}$$
Detailed Academic Explanation:
$$\frac{{\partial L}}{{\partial \dot \phi }}$$ is the correct answer to “The Lagrangian of a free particle in spherical polar coordinates is given by $$L = \frac{1}{2}m\left[ {{{\dot r}^2} + r{{\dot \theta }^2} + {r^2}{{\dot \phi }^2}{{\sin }^2}\theta } \right]$$ The quantity that conserved is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 32 of 40
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Two particles of equal masses are connected by an inextensible string of length L. One of the masses is constrained to moves on the surface of a horizontal table. The string passes through a small hole in the table and the other mass is hanging below the table. The only constraint is that the first mass moves on the surface of the table. The number of degree of freedom of the masses string system is
Correct Answer: Option C — two
Detailed Academic Explanation:
two is the correct answer to “Two particles of equal masses are connected by an inextensible string of length L. One of the masses is constrained to moves on the surface of a horizontal table. The string passes through a small hole in the table and the other mass is hanging below the table. The only constraint is that the first mass moves on the surface of the table. The number of degree of freedom of the masses string system is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 33 of 40
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Assuming the mean life, of a muon (in its rest frame) to be 2 × 10 -6 s, its life time in the laboratory frame, when it is moving with a velocity 0.95 c is
Correct Answer: Option A — 6.4 × 10-6 s
Detailed Academic Explanation:
6.4 × 10-6 s is the correct answer to “Assuming the mean life, of a muon (in its rest frame) to be 2 × 10 -6 s, its life time in the laboratory frame, when it is moving with a velocity 0.95 c is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 34 of 40
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A particle is moving under the action of a generalised potential $$V\left( {q,\,\dot q} \right) = \frac{{\left( {1 + \dot q} \right)}}{{{q^2}}}$$ The magnitude of generalised force is
$$\frac{{2\left( {1 + \dot q} \right)}}{{{q^3}}}$$ is the correct answer to “A particle is moving under the action of a generalised potential $$V\left( {q,\,\dot q} \right) = \frac{{\left( {1 + \dot q} \right)}}{{{q^2}}}$$ The magnitude of generalised force is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 35 of 40
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The moment of inertia tensor of a rigid body is given by \[I = \left[ {\begin{array}{*{20}{c}} 8&0&{ - 4} \\ 0&4&0 \\ { - 4}&0&8 \end{array}} \right]\] Moment of inertia a out an axis $${\bf{\hat n}} = \left( {\frac{1}{2},\,\frac{{\sqrt 3 }}{2},\,0} \right)$$ is
Correct Answer: Option B — 5
Detailed Academic Explanation:
5 is the correct answer to “The moment of inertia tensor of a rigid body is given by \[I = \left[ {\begin{array}{*{20}{c}} 8&0&{ - 4} \\ 0&4&0 \\ { - 4}&0&8 \end{array}} \right]\] Moment of inertia a out an axis $${\bf{\hat n}} = \left( {\frac{1}{2},\,\frac{{\sqrt 3 }}{2},\,0} \right)$$ is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 36 of 40
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A closed tall jar containing air and a fly placed on a sensitive weighing machine when the fly is stationary, the reading of the weighing machine is ω. If the fly starts with some upward acceleration, the reading of the machine will be
Correct Answer: Option A — ω
Detailed Academic Explanation:
ω is the correct answer to “A closed tall jar containing air and a fly placed on a sensitive weighing machine when the fly is stationary, the reading of the weighing machine is ω. If the fly starts with some upward acceleration, the reading of the machine will be”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 37 of 40
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Consider a comet of mass m moving in a parabolic orbit around the sun. The closets distance between the comet and the sun is b, the mass of the sun is M and universal gravitation constant is G. The angular momentum of the comet is
Correct Answer: Option D — $$m\sqrt {2GMb} $$
Detailed Academic Explanation:
$$m\sqrt {2GMb} $$ is the correct answer to “Consider a comet of mass m moving in a parabolic orbit around the sun. The closets distance between the comet and the sun is b, the mass of the sun is M and universal gravitation constant is G. The angular momentum of the comet is”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 38 of 40
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The Lagrangian of two coupled oscillators of mass m each is $$L = \frac{1}{2}\left( {{{\dot x}_1}^2 + {{\dot x}_2}^2} \right) - \frac{1}{2}m{\omega _0}^2\left( {{x_1}^2 + {x_2}^2} \right) + m{\omega _0}^2\mu {x_1}{x_2}$$ The equations of motion are
$${{\ddot x}_1} + {\omega _0}^2{x_1} = {\omega _0}^2\mu {x_2},\,{{\ddot x}_2} + {\omega _0}^2{x_2} = {\omega _0}^2\mu {x_1}$$ is the correct answer to “The Lagrangian of two coupled oscillators of mass m each is $$L = \frac{1}{2}\left( {{{\dot x}_1}^2 + {{\dot x}_2}^2} \right) - \frac{1}{2}m{\omega _0}^2\left( {{x_1}^2 + {x_2}^2} \right) + m{\omega _0}^2\mu {x_1}{x_2}$$ The equations of motion are”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 39 of 40
★ MDCAT
★ CSS
★ MDCAT
★ CSS
Which one of the following is true for the above system?
Correct Answer: Option A — The acceleration of the comet is maximum when it is closest to the sun
Detailed Academic Explanation:
The acceleration of the comet is maximum when it is closest to the sun is the correct answer to “Which one of the following is true for the above system”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
Question 40 of 40
★ MDCAT
★ CSS
★ MDCAT
★ CSS
A particle of mass m is moving in a potential of the form V(x, y, z) = $$\frac{1}{2}$$ mω 2 (3x 2 + 3y 2 + 2z 2 + 2xy). The oscillation frequencies of the three normal modes of the particle are given by
Correct Answer: Option A — ω, $$\sqrt 3 $$ ω and $$\sqrt 3 $$ ω
Detailed Academic Explanation:
ω, $$\sqrt 3 $$ ω and $$\sqrt 3 $$ ω is the correct answer to “A particle of mass m is moving in a potential of the form V(x, y, z) = $$\frac{1}{2}$$ mω 2 (3x 2 + 3y 2 + 2z 2 + 2xy). The oscillation frequencies of the three normal modes of the particle are given by”. This question is standard in competitive examination syllabi for Classical Mechanics.
💡Key Conceptual Anchor:Classical Mechanics
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💡Examiner's Advisory for Physics & Applied Physics
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.