Basic Syntax And Data Types In C Sharp — Part 1 MCQs with Explanations

The correct answer is C: 5 Here's why: Let's break down the code step by step: int i; declares an integer variable named 'i'. for (i = 0; i < 5; i++) is a for loop . Let's see how it works: i = 0; This is the initialization part. 'i' starts at 0. i < 5; This is the condition. The loop continues as long as 'i' is less than 5. i++; This is the increment. After each loop iteration, 'i' increases by 1. The loop runs as follows: i = 0 (0 < 5 is true) i = 1 (1 < 5 is true) i = 2 (2 < 5 is true) i = 3 (3 < 5 is true) i = 4 (4 < 5 is true) i = 5 (5 < 5 is false ) The loop stops here. Console.WriteLine(i); This line prints the final value of 'i', which is 5. Console.ReadLine(); This line just waits for you to press Enter before the program closes (it keeps the console window open so you can see the output).

Understanding the Code: This C# code uses a for loop to repeat a block of code five times. Inside the loop, a variable j is declared and initialized to 0 in each iteration. Then, j is updated by adding the current value of i to it ( j += i; ). The value of j is printed to the console in each iteration. After the loop finishes, the code tries to print i * j . However, this is tricky! The scope of j is only inside the loop. Once the loop finishes, j no longer exists. Therefore, you will get a compile-time error because j is not accessible outside the loop. Why other options are incorrect: Options A, B, and D show possible outputs if the code were to run without error. Since j is out of scope, these outputs are impossible. The Correct Answer: The correct answer is C: Compile time error because the variable j is not accessible outside the for loop.

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