Control Flow Statements In C Plus Plus — Part 1 MCQs with Explanations

The given code is a for loop in C++: for (int i = 5; i >= 0; --i) { cout << i << " "; if (i == 3) break; } This loop initializes i to 5 and decrements it in each iteration until i becomes less than 0. On each iteration, it prints the current value of i followed by a space. When i becomes 3, the if condition becomes true and the break statement terminates the loop. Therefore, the values printed are: 5 4 3 No further values (like 2, 1, 0) are printed because the loop exits when i == 3. Hence, the correct output is: 5 4 3

Solution: The code contains a nested for loop structure. The outer loop iterates with variable i from 0 to 2 (inclusive), and the inner loop iterates with variable j from 0 to 1 (inclusive). For each iteration of the outer loop (each value of i ), the inner loop runs completely, iterating through both values of j . The output is printed as follows: When i = 0 : j = 0 → output is 00 j = 1 → output is 01 When i = 1 : j = 0 → output is 10 j = 1 → output is 11 When i = 2 : j = 0 → output is 20 j = 1 → output is 21 Combining all outputs, the final result is: 00 01 10 11 20 21

Explanation: Let's break down this C++ code step by step: 1. Variable Initialization: int x = 10; This line creates an integer variable named 'x' and assigns it the value 10. 2. `if` Statement: if (x < 5) This checks if the value of 'x' (which is 10) is less than 5. Since 10 is not less than 5, this condition is false. 3. `else if` Statement: else if (x == 5) Because the first `if` condition was false, the program moves to the `else if` condition. This checks if 'x' is equal to 5. Since 10 is not equal to 5, this condition is also false. 4. `else` Statement: else cout << "More"; Since both the `if` and `else if` conditions were false, the program executes the code within the `else` block. This line prints "More" to the console. Therefore, the output of the code will be "More". Correct Answer: A) More

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