Control Structures_Loop In Php — Part 1 MCQs with Explanations

Uninitialized x is set to 0, thus if condition fails.

x is incremented after if which evaluates to false.

else condition without brackets performs the following statements only.

The nested for loop is not entered if outer condition is false.

Due to post increment and post decrement only the first condition is satisfied.

echo does not return anything so if condition is empty.

print returns 1 if it prints anything.

Hanging else statement.

No else statement to end the if statement.

Empty string is evaluated to 0.

The value of a is evaluated to 1 as it has a value.

Expression evaluates to true.

Expression evaluates to true.

Expression evaluates to true.

Expression evaluates to false.

Expression evaluates to true as print returns 1.

Enters if else as first condition is false and thus x is set to 2.

x&0 is 0,thus evaluated to false.

break is not defined for a if else ladder.

In php division returns a float that is a non zero value thus evaluates to true.

Print returns true and thus the first if statement also is not executed.

print returns true and when 1 is subtracted it is syntax error.

The if statement has no brackets and it expects a else/else if after a if.

The operator precedence of ++ is higher than <,thus the incremenrt happens first and then compared.

Computing the expression in the if clause,it sums upto to 2 which is a positive value.

The . operator appends a string and returns true.

The function strlen($a) gives the length of the string,5, which is considered true.

The expression is evaluated with values contained in the string, even without typecasting.

As break is not provided it executes all the cases.

As hello is provided after case2 it breaks the loop.

As break is provided before print statement in case 2 it breaks the loop before printing.

It checks the first case, when it finds it equal it will perform it breaks out.

Downcasting does not happen in case,it compares only with its data type.

Upcasting does happen in case,it compares it with 1.0 and thus prints hi and exits.

Constants cannot be used in switch cases.

Print returns 1,thus it gives case 1.

If that case does not exist then it searches for default and on not finding it does nothing.

Case cannot be defined by a variable.

The while loop cannot be defined without a condition.

The do while loop executes atleast once as the condition is in the while loop.