Control Structures_Loop In Php — Part 2 MCQs with Explanations

The increment happens and then the check happens.

The increment happens and then the check happens.

As it is a post increment, it checks and then does not enter the loop, thus prints only 1.

While accept does not accept anything other than a 0 or any other number as false and true.

The while loop ends only when a } is encountered.

While condition always gives 1.

While condition always gives 1.

i is decremented in the first while execution and then continuously incremented back.

As it is && operator it is being incremented and decremented continuously.

As it is || operator the second expression is not evaluated and i is always incremented, in the first case to 1.

The first condition itself fails thus the loop exists.

(–$i > ++$i) evaluates to 0 but -1 makes it enters the loop and prints i.

The loop ends when i becomes 0.

Wrong syntax for for loop.

The value of x is incremented and printed twice before checking,thus last loop it prints 11 and 12.

Loop runs from 1 to 9 i.e 9 times.

The value of x is decremented thus making it an infinite loop.

The loop is not even entered as x is initially 0.

The loop runs only once as value of x is incremented.

The loop does not run as i initialized in check statement will be zero.

The loop never exits as the condition ++X == X is always satisfied,evaluated from right to left.

9*4 times is printed.

Condition always fails as count takes only odd numbers.

The for loop has no body,it just runs till condition is satisfied.

When continue is encountered it skips to the next iteration

When break is encountered it leaves the loop.

The order of execution is initialization, check, increment/decrement, check, increment/decrement, check, increment/decrement….so on.

The order of execution is initialization, check, increment/decrement, check, increment/decrement, check, increment/decrement….so on .

There is no check condition to stop the execution of the loop.

The break statement after breaks the loop after i=3,does not print anymore.

The condition of the loop is always false 0.

In the second loop j value is not being changed.

The second loop does not execute as the check condition is always false.

Only Bale is printed as $x++ is done before printing and then checked.

Loop condition is true as i%(i+1) is a float non zero value in php.

The i value is changed in the inner loop and reaches five, thus does not execute the second outer loop.

As count($a) returns 3 the condition is always false.

As count($a) returns 3 the condition is always true, thus it prints $a, which returns its data type.

hi is the correct answer to “What will be the output of the following PHP code ? <?php if (- 100 ) print "hi" ; else print "how are u" ; ?>”. This question is standard in competitive examination syllabi for Control Structures_Loop In Php.