Coding And Decoding — Part 1 MCQs with Explanations

D is used for F. G is used for I. P is used for R. and C is used for E. Thus, it is clear that each letter of the word FIRE stands for each corresponding letter of the coded word DGPC two places ahead. By applying the same principle, the letters QFMR will stand for SHOT. Hence, the last letter of the coded word is R.

By, comparing letters and digit, we get T = 1 O = 2 U = 3 R = 4 C = 5 L = 6 E = 7 A = 8 S = 9 and P = 0 As the 5 th letter is SCULPTURE is P and '0' is used for P, therefore, 5th digit is the required code which is '0'.

In the given code PROSE = PPOQE The first, third and fifth letters are same but in the place of second and fourth letters previous two letters are used. So, LIGHT = LGGFT.

Let's break down this Coding and Decoding question step by step. The question gives us a coded word: SUMMER is coded as RUNNER . We need to find the code for WINTER using the same rule. Let's compare SUMMER and RUNNER letter by letter to find the pattern: S U M M E R R U N N E R 1. Look at the first letter : In SUMMER, the first letter is S . In RUNNER, the first letter is R . If you go one letter back in the alphabet from S, you get R. (S - 1 = R) 2. Look at the second letter : In SUMMER, the second letter is U . In RUNNER, the second letter is U . The letter U remains unchanged . 3. Look at the third letter : In SUMMER, the third letter is M . In RUNNER, the third letter is N . If you go one letter forward in the alphabet from M, you get N. (M + 1 = N) 4. Look at the fourth letter : In SUMMER, the fourth letter is M . In RUNNER, the fourth letter is N . Again, the letter M changes to N . (M + 1 = N) 5. Look at the fifth letter : In SUMMER, the fifth letter is E . In RUNNER, the fifth letter is E . The letter E remains unchanged . 6. Look at the sixth letter : In SUMMER, the sixth letter is R . In RUNNER, the sixth letter is R . The letter R remains unchanged . So, the rule for coding is: 1st letter: -1 (go one letter back) 2nd letter: No change 3rd letter: +1 (go one letter forward) 4th letter: +1 (go one letter forward) 5th letter: No change 6th letter: No change Now let's apply this same rule to the word WINTER : 1. W (1st letter): Apply -1 rule. W - 1 = V 2. I (2nd letter): Apply no change rule. I = I 3. N (3rd letter): Apply +1 rule. N + 1 = O 4. T (4th letter): Apply +1 rule. T + 1 = U 5. E (5th letter): Apply no change rule. E = E 6. R (6th letter): Apply no change rule. R = R Combining these letters, the code for WINTER is VIOUER . Let's check the options: Option A: SUITER Option B: VIOUER Option C: WALKER Option D: SUFFER Our calculated code VIOUER matches Option B . Therefore, the correct answer is Option B: VIOUER .

MIND = KGLB Each letter in the word is moved two steps backward to obtain the corresponding letter of the code. So, DIAGRAM = BGYEPYK.

PRACTICE = PICCTRAE. First and last letters are same but second and third letters and third last and second last letters have been interchanged. So, FLAMES = FMELAS.

First, let's figure out the rule for how KNIFE becomes MPKHG . We compare each letter from the first word to the second word: K is changed to M (If you count in the alphabet: K, L, M . So, K + 2 letters = M) N is changed to P (N, O, P . So, N + 2 letters = P) I is changed to K (I, J, K . So, I + 2 letters = K) F is changed to H (F, G, H . So, F + 2 letters = H) E is changed to G (E, F, G . So, E + 2 letters = G) So, the secret rule (code) is: Each letter is shifted forward by 2 positions in the alphabet. Now, we need to find what the letters DTGCF stand for. Since DTGCF is the coded word, to find the original word, we need to do the opposite of the coding rule. If coding was "+2", then decoding will be "-2" (shifting each letter backward by 2 positions). Let's apply this rule to DTGCF : D - 2 letters = B (Counting backward: D, C, B ) T - 2 letters = R (Counting backward: T, S, R ) G - 2 letters = E (Counting backward: G, F, E ) C - 2 letters = A (Counting backward: C, B, A ) F - 2 letters = D (Counting backward: F, E, D ) Putting these decoded letters together, we get BREAD . Therefore, the letters DTGCF stand for BREAD . Looking at the options, Option B: BREAD is the correct answer.

First, let's analyze the given coding: We are told that GBOQX stands for HAPPY . This implies that GBOQX is the coded form of the original word HAPPY . Let's find the rule by comparing each letter from the Coded Word (GBOQX) to its corresponding letter in the Original Word (HAPPY) : 1. For the first letter: G (from GBOQX) corresponds to H (from HAPPY) This transformation is G + 1 = H (moving one step forward in the alphabet). 2. For the second letter: B (from GBOQX) corresponds to A (from HAPPY) This transformation is B - 1 = A (moving one step backward in the alphabet). 3. For the third letter: O (from GBOQX) corresponds to P (from HAPPY) This transformation is O + 1 = P (moving one step forward). 4. For the fourth letter: Q (from GBOQX) corresponds to P (from HAPPY) This transformation is Q - 1 = P (moving one step backward). 5. For the fifth letter: X (from GBOQX) corresponds to Y (from HAPPY) This transformation is X + 1 = Y (moving one step forward). So, the consistent pattern for transforming a Coded Word to its Original Word is: +1, -1, +1, -1, +1 . Now, the question asks: "for which word the letters CROSS stand for ?" This means we need to find the coded form of the original word CROSS . To do this, we need to apply the inverse rule of what we found (Coded to Original). If the rule for Coded to Original is (+1, -1, +1, -1, +1), then the rule for Original Word to Coded Word will be the exact opposite operations for each position. The inverse rule for Original Word to Coded Word is: -1, +1, -1, +1, -1 . Let's apply this inverse rule to the original word CROSS : 1. For the first letter C : C - 1 = B 2. For the second letter R : R + 1 = S 3. For the third letter O : O - 1 = N 4. For the fourth letter S : S + 1 = T 5. For the fifth letter S : S - 1 = R Combining these transformed letters, the coded word for CROSS is BSNTR . Comparing this result with the given options: Option A: BSPTR Option B: BSNTR Option C: BNSTR Option D: BSNRT The correct answer is Option B: BSNTR .

we have, S = 5 I = 3 T = 3 E = 0 R = 1 U = 8 N = 4 C = 6 L = 7 B = 1 O = 2 Y = 9. So, SON = 524.

H = 1 A = 3 R = 5 D = 7 S = 2 O = 4 F = 6 T = 8 . Hence, 21448 = SHOOT.

T = 1 O = 2 U = 3 R = 4 C = 5 L = 6 E = 7 A = 8 S = 9 P = 0. Hence, SCULPTURE = 953601347

Last two letters of the word CDPQYZ are next two letters of the word BOX. In the same way, the last two letters of HERO if coded will be P, Q.

In the right side of the question there is a gap of 7 letters between B and J and 6 numbers between 6 and 14. Similarly, there is a gap of 3 letters between J and N. Therefore 3 numbers gap after 14 is 18. In the left side of the question there is a gap of 8 letters between D and M and 6 numbers between 8 and 17. Similarly, there is a gap of 5 letters between M and S. Therefore 5 numbers gap after 17 is 23.

Generally, Fishes lives in Water and Water is called Colour in the code. So Fishes live in Colour.

A child writes with the Pencil and Pencil is called Sharpener. So the child writes with Sharpener.

We sleep at Night and Night is called Sunshine. So, we sleep in Sunshine.

BUTLER serves in the restaurant and BUTLER is called ROGUE. So, ROGUE will be served in restaurant.

By comparing the given codes, we get QUO means IS and CUI means GOOD, therefore, HEER means BOY.

CHIP DIN CHUNK = STUDENT ATTENDS CLASS. DIN SHUNK DINK = ARJUN IS STUDENT. Hence, DIN = STUDENT. DINK MUP CHIMP = TEACHER IS TEACHING. Hence, DINK = IS. Therefore, ARJUN = SHUNK.

1 3 4 = GOOD AND TASTY. 4 7 8 = SEE GOOD PICTURES. Hence, 4 = GOOD. (by comparing I and II.) 7 2 9 = PICTURES ARE FAINT. and 7 = PICTURES. Therefore, 8 = SEE.

Comparing, the first two sentence, we get, A LEAP = MO KI. Comparing, the first and third sentence, we get code for, FROG'S = JA. SO from the first sentence, we will get the code of AT = PE.

W → 9 E → % A → 2 K → $ S → # I → 7 T → @ So, WAIT = 927@

T (+2) → V H (+2) → F E (+2) → G N (+2) → L So, W (+2) → Y O (+2) → M R (+2) → T D (+2) → B

Given, A = 4, K = 3, N = 2, P = 1. Sum of first Set, = K + A + N + P +K = 3 + 4 + 2 + 1 + 3 = 13. Sum of the second set, N + P + A + K +N = 2 + 1 + 4 + 3 + 2 = 12. Sum of the third set, P + K + A + N + A = 1 + 3 + 4 + 2 + 3 = 13. Sum of the fourth set, N + A + K + N + A = 2 + 4 + 3 + 2 + 4 = 15.

Look at the given example: ORCHESTRA → ARTSEORCH . Compare letters by position (original → code): O R C H E S T R A → A R T S E O R C H So the code takes the part after the first four letters (that is, from the 5th letter to the end), reverses that part , and then appends the first four letters unchanged . In other words: code = reverse(original[5..end]) + original[1..4] . Apply this rule to DREAMLAND : First four letters = DREA Remaining part = MLAND Reverse the remaining part: DNALM Append the first four letters: DNALM + DREA = DNALMDREA Thus the coded form of DREAMLAND is DNALMDREA (Option C).

Since every alternative letter starting from B of the English alphabet is written in small letter, the letters written in small letter are b, d, f, h and so on. And Capital letters are C, E, G so on. In option first, third and fourth e is written in small letter, so it cannot be the answer And In second option second e is written in small. Therefore, none of above options are satisfy the condition. .

The first letter of the word is moved one step forward to obtain the first letter of the code, while the other letters remain unaltered.

The first, third and fifth letters are each moved one step backward, while the second, fourth and sixth letters are each moved one step forward to obtain the corresponding letters of the code.

The first, second, third, fourth, fifth, sixth and seventh letters in the word are moved one, two, three, four, five, six and seven steps forward respectively to obtain the corresponding letters of the code.

The first, second, third, fourth, . . . . . letters of the word are moved one, two, three, four, . . . . . steps backward respectively to obtain the corresponding letters of the code.

The code is formed by first writing the last three letters of the word in a reverse order, followed by the first three letters in the same order. So, the code for STUPID should be DIPSTU.

The first four letters, the middle two letters and the last four letters of the word are written in a reverse order to form the code.

The letters of the word are written in a reverse order and then each letter is moved one step forward to obtain the code.

The letters in the first half and second half of the word are written in the reverse order and in the group of letters so obtained, each letter in the first half is moved two steps forward while that in the second half is moved one step forward, to get the code. Thus, we have: PERIODICAL => PERIO/DICAL => OIREP/LACID => QKTGR/MBDJE.

All the letters of the word, except the last letters, are written in the reverse order and in the group of letters so obtained, each letter is moved two steps forward to get the code. Thus, we have : AVOID => IOVAD => KQXCF

Each letter in the word is replaced by the letter which occupies the same position from the other end of the alphabet, to obtain the code. Thus, A is replaced by Z, B by Y, C by X, D by W and so on.

Each letter in the word is moved one step forward to obtain the corresponding letter of the code.

The first, third and sixth letters of the word are each moved two steps forward; the second, fifth and seventh letters are each moved two steps backward, while the fourth letter is moved one step forward to obtain the corresponding letters of the code.

The letters of the word are written in a reverse order to obtain the code.

The word is divided into groups of two letters each and then the letters of each group are written in a reverse order.