Data Sufficiency — Part 1 MCQs with Explanations

From both I and II, we find that Rahul is (35 - 25) = 10 years older than his brother, who was born in 1964. So, Rahul was born in 1954.

From I, we conclude that weight of each pole = (4x5) kg = 20 kg. So, total weight of 10 poles = (20 x 10) kg = 200 kg. From II, we conclude that: Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg. So, total weight of 10 pojes = (20 x 10) kg = 200 kg.

From I, we conclude that H is the only daughter of M. But this does not indicate that M has no son. The information given in II is immaterial.

From I, total sale of product A = Rs. (8000 x 25) = Rs. 200000. From II, we know that the company deals only in product A. This implies that sale of product A is the total sale of the company, which is Rs. 200000.

From I, we conclude that 5th, 12th, 19th and 26th of March, 2006 were Sundays. So, the last Sunday fell on 26th. From II, we conclude that 31st March, 2006 was Friday. Thus, 26th March, 2006 was the last Sunday of the month.

The only word common to I and II is 'clear' and as such, only the code for 'clear' can be ascertained from the given information.

From II, Q being in the middle, there are 10 children to his right as well as to his left. So, Q is 11th from the left. From I, P is 15th from the left. Thus, from both I and II, we conclude that there are 3 children between P and Q.

From I, we know that L is T's brother and J's husband. Since L is the only son of his parents, T is L's sister. From II, we know that K is L's daughter. Thus, from I and II, we conclude that T is the sister of K's father i.e. T is K's aunt.

From II, we know that P's mother is married to J's husband, which means that J is P's mother.

From I, we conclude that Y is the child of D who is wife of X i.e. X is Y's father. From II, X is married to Y's father. This implies that X is Y's mother.

From I, we have the order: R, -, P, Q. From II, we have the order: P, Q, T. Clearly, each one of the above two orders indicates that Q is to the immediate right of P.

From I and II, we conclude that Anjali was born in February 2004 on a date which is an even prime number. Since the only even prime number is 2, so Anjali was born on 2nd February, 2004.

The statements in I and II do not provide any clue regarding relation between X and Y.

From I and II, we conclude that P is M's brother and so M's father is P's father. So, F is the child of the sister of P's father i.e. F's mother is P's aunt or F is P's cousin.

B is A's brother means A is either brother or sister of B. Now, each one of I and II individually indicates that A is a female, which means that A is B's sister.

Since 8th to the left of 12th from the right is 20th from the right, so from I, we know that Vishakha is 5th from left and 20th from right i.e. there are 4 children to the left and 19 to the right of Vishakha. So, there are (4 + 1 + 19) i.e. 24 children in the row. From II, Nisha is 7th from right and 18th from left end of the row. So, there are (6 + 1 + 17) = 24 children in the row.

From I, total number of doctors in town = (1/700 x N) , where N = total number of residents in town. But, the value of N is not known. From II, total number of doctors in town = (Number of wards in town) x (Number of doctors in each ward) = 16 x 16 = 256.

I does not mention the day of the week on the birthday of either Arun or Sahil. According to II, Sahil's sister was born on Wednesday and Sahil was born two days before Wednesday i.e. on Monday.

From I and II, we find that Robert read (300 x 2/3) i.e. 200 pages before Sunday and the last 40 pages on Monday. This means that he read [300 - (200 + 40)] i.e. 60 pages on Sunday.

From I, we conclude that the man is the only son of Tanya's grandfather i.e. he is Tanya's father or Tanya is the man's daughter. From II, we conclude that the man's father is Tanya's grandfather. Since the man has no brothers or sisters, so he is Tanya's father or Tanya is the man's daughter.

From I, we have: B > T, B > C, V > B. Thus, V is heavier than each one of B, T and C. But V is not the heaviest. So, E is the heaviest. Thus, we have the order. E>V>B>T>C or E>V>B>C>T. Clearly, B is third from the top.

From the two statements given in I, the code for the only common word 'beautiful' can be determined. From the two statements given in II, the code for the only common word 'red' can be determined. In I and II, the common words are 'rose and 'flower' and the common code words are 'de' and 'la'. So, the code for 'flower' is either 'de' or 'la'.

From I: “Only boys play football” tells us that if anyone plays, they must be boys, but it does not state how many boys actually play (could be anywhere from 0 to all boys). Hence, not sufficient. From II: “There are 40 boys and 30 girls” only gives class composition; it provides no information about who plays football. Hence, not sufficient. Together (I + II): We know only boys can play and there are 40 boys, but we still don’t know how many of those boys actually play (could be any number from 0 to 40). Still not sufficient. Therefore: The exact number of students who play football cannot be determined from the given statements.

Clearly, each of the given statements shows that B is sitting opposite to C or B is the partner of C.

From I, we know that the serials were screened on 23rd, 24th, 25th and 26th. Clearly, D was screened second i.e. on 24th, Wednesday. From II, we know that one serial was screened between A and B. So, A and B were screened first and third, i.e. on 23rd and 25th. But, A was not screened on 25th. So, A was screened on 23rd and B on 25th. Thus, C was screened on 26th, Friday.

From I, we conclude that Sulekha is the wife of Nandini's mother's only son i.e. Nandini's brother. Thus, Sulekha is Nandini's sister-in-law. From II, we conclude that Sulekha is the cousin of Nandini's husband, which implies that Sulekha is Nandini's sister-in-law.

Clearly, the facts given in I and II contain two conditions to be fulfilled to get retirement and also indicate that Ritesh fulfills only one condition out of them.

I. In 'right or wrong' and 'he is right', the common word is 'right' and the common code word is 'nik'. So 'nik' means 'right'. In 'right or wrong' and 'that is wrong', the common word is 'wrong' and the common code word is 'te'. So, 'te' means 'wrong'. Thus, in 'right or wrong', 'sa' is the code for 'or'. II. In 'that right man' and 'this or that', the common word is 'that' and the common code word is 'pa'. So, 'pa' means 'that'. In 'this or that' and 'tell this there', the common word is 'this' and the common code word is 'ne'. So, 'ne' means 'this'. Thus, in 'this or that', 'sa' is the code for 'or'.

As given, we have: M > K, A > S. From II, K > A. Thus, we have: M > K > A > S. So, Sharad is the youngest. From I, M > S. Thus, we have: M>K>A>S or M>A>K>S or M>A>S>K.

From I, we conclude that Kapil was born on any one of the dates among 16th, 17th and 18th. From II, we conclude that Kapil was born on any one of the dates among 13th, 14th, 15th and 16th. Thus, from both I and II, we conclude that Kapil was born on 16th August.

As given in I and II, we have: G = V = K, V + K + A = 32 and A = V + K. Putting V + K = A in V + K + A = 32, we have: 2A = 32 or A = 16. Thus, V + K = 16 and V = K. So, V = K = 8. Thus, G = 8.

'59' means 'injurious habit' and '157' means 'stop bad habit' (from I). Thus, the common code number '5' stands for common word 'habit'. So, '9' represents 'injurious'. Hence, I is sufficient. Also, '59' means 'injurious habit' and '839' means 'smoking is injurious'. Thus, the common code number '9' stands for common word 'injurious'. So, '5' represents 'habit'. Thus, II is also sufficient.,

From I, we have: S = T - 20. From II, we have: V = T + 30. Thus, from both I and II, we have: V + S = (T + 30) + (T - 20) = (2 T + 10). So, to get the required amount, we need to know the amount that Tarun has.

From I, we have the order : A, M, T. From II, we have the order: T, R, S. Combining the above two, we get the order: A, M, T, R, S. Thus, Sonal came last for the programme.

From I, we have: R>Q, R>T, S>R i.e. S>R>Q>T or S>R>T>Q. From II, S is not the heaviest. So, P is the heaviest. Thus, we have: P > S > R > Q > T or P > S > R > T > Q. Hence, either T or Q is the lightest.

From II, we know that T's mother has only two sons, A and B. This implies that T is the sister of both A and B. But, from I, A is also K's son. So, T is the daughter of K.

Clearly, the distance of each village from Rampur is given in I and II. But nothing about their relative positions is mentioned. So, the distance between the two villages cannot be calculated.

From I and II, we conclude that A is either son or daughter of D.

From I, we have: P > M, P > K, A > P. Thus, A > P > M > K or A > P > K > M. So, Akash is the heaviest. From II, we have: P > M, A > M, M > K. Thus, A > P > M > K or P > A > M > K. So, either Akash or Prabhakar is the heaviest.

Statement I is merely an interpretation of the information contained in the question. However, Vinod's salary can be ascertained from II as follows : Let Vinod's and Javed's salaries be 4x and 3x respectively. Then, 3x = 4500 or x = 1500. Therefore Vinod's salary = 4x = Rs. 6000.