Puzzle MCQs with Explanations

The steps are labelled using alphabets from A to J. TO MAKE IT EASY, WE HAVE ASSIGNED NUMBERS TO THE STEPS AS FOLLOWS: Labelled with alphabets : A B C D E F G H I J Labelled with numbers : 1 2 3 4 5 6 7 8 9 10 The frog takes total 60 minutes and takes 4 step length jumps every time. Thus, 1st minute : 1 + 4 = 5th step (E) 2nd minute : 5 + 4 = 9th step (I) 3rd minute : 9 + 4 = 3rd step (C) 4th minute : 3 + 4 = 7th step (G) 5th minute : 7 + 4 = 11 = 10+1 = 1st step (A) The same process is repeated 12 x 5 times. Then, the jumping positions are 1 5 9 3 7 1 5 9 3 7 1 5 9 3 7 and so on. After 15 cycles, frog will be in the 1st position i.e., at 5th minute, 10th minute, 15minutes....60th minute frog will be in the 1st position. i.e., at 60t

Let B be the number of brothers and S be the number of sisters in the family. Step 1: Understanding the condition for the boys If we pick any 2 boys, they will have (B - 2) other brothers (excluding themselves). According to the question, this number is equal to the number of sisters they have. So, we get: B - 2 = S Rewriting this: B - S = 2 ............(1) Step 2: Understanding the condition for the girls Each girl has (S - 1) sisters (excluding herself). Twice the number of sisters = 2(S - 1) Each girl has 2 brothers less than that: So, number of brothers B = 2(S - 1) - 2 Simplifying: B = 2S - 4 ............(2) Step 3: Solving the equations Now, substitute equation (2) into equation (1): (2S - 4) - S = 2 2S - 4 - S = 2 S = 6 Now substitute S = 6 back into equation (1): B - 6 = 2 B = 8 Final Answer: There are 8 boys and 6 girls in the family. Correct Option: A) 8 , 6

Total number of trees, = 7+14-1 = 20

Let, A = x Then, B = 2x and, F = 4x C = x/2 and D = x/4 Thus, The second oldest is B.

1 2 3 4 5 6 7 8 9 10 11 12 Ramesh 14 ... ... ... ... ... ... ... ... ... ... Suresh 5 4 3 2 1 Total Number of Student = 33 Number of student in between Ramesh and Suresh is,= 33 - (13+6) = 14 .

Age of Shan = 55 years Age of Sathian = 55-5 = 50 years Age of Balan = 50-6 = 44 years Age of Deven = 44-7 = 37 years Thus, difference between Devan and Shan, = 55 -37 = 18.

Let X be the rupees he initially had. He gave for the cancer fund one rupee more than half of what he had. i.e.,[1 +(X/2)]. Remaining money = X-(1+X/2) = [(X/2) - 1. he gave for poor people's, rupee 2 more than half what he remain with, = [2+{1/2*(X/2-1)}] = [2+{(X-2)/4}] = (6+X)/4 Now, remaining money = ((X/2)-1) - ((6+X)/4) = (X-10)/4. Again he gave 3 rupees more than half of what he had for orphanage, [3+(1/2*((X-10)/4))] = 3+[(X-10)/8] = (14+X)/8 now left money,[{(X-10)/4]-[(14+X)/8]} = [(2X-X-20-14)/8] = (X-34)/8 As given, finally he had one rupee remaining so (X-34)/8 = 1 So,X-34 = 8 X = 8+34 = 42 Hence, Rohit had Rs. 42 initially in his pocket.

Badminton is played without any ball and in the question Badminton is called Volleyball.

The ascending order of the number is 123456789. Required difference, 6-3 = 3.

G → F L → K A → B D → C I → J O → P L → K U → V S → R Thus, GLADIOLUS = FKBCJPKVR.

Only Three such pairs, I (N) G D (IN) G and S (ENDI) N

Option Checking : Considering option 3, 2 *(14) 2 - 25*14 = 3*14. Alternatively : Let the age of the lad be x then, 2x 2 -25x = 42. 2x 2 -25x-42 = 0. Either solve the quadratic equation or put the options to get the value. Option 3 is correct.

Total number of Vehicles = 160There are 70 red vehicles thus rest 90 are green vehicles, out of which 18 are green trucks then we get, Green cars = 90 - 18 = 72. Given, Number of cars = 120. Then, number of red cars,= 120 - 72 = 48 Red cars.

Let initially X grass was present there,and it is increasing by Y grass per day, then for the first condition We get,X+24*y = 24*70 ----(1)For the 2nd condition, we have,X+60*Y = 60*30----(2) Now, On solving equation (1) and (2), we get X = 1600 and Y = 10 /3 Third Condition,X+96*Y = 96 *N -----(3) [ N = Number of Cows required ] Putting the values of X and Y in equation (3), We get N = 20.

Mohan is older than Prabir. Prabir < Mohan Suresh is younger than Prabir means Prabir is older than Suresh. Suresh < Prabir < Mohan Mihir is older than Suresh but younger than Prabir. Suresh < Mihir < Prabir < Mohan Suresh is the youngest.

Total days of rainfall = 13. 11 Mornings enjoyed and 12 Afternoons enjoyed, so it means there was rain on 6 mornings and 7 afternoons. So, extra days without rain are 5 days (11-6 or 12-7). Total no of day they live, = No. of days of rain + Days without rain, Or, 13 + 5 = 18days.

M scores more run than N.(M > N) M scores less than P. (P >M >N) Q scores more than N but less than M. So, Sequence of scoring run is P >M>Q>N. So, N is the lowest scorer.

Sequence of seating from right to left is: Harish, Manish, Satish and Girish. So, Girish sits farthest to right.

The alphabet starting with C, so 1 st Hour = C 2 nd Hour = D 3 rd Hour = E, and So on. Then we get, 16 th Hour = R. 16 hour is represented by letter R .

January was unfortunate for Tejas, means Tejas was stolen in January. Vayu was stolen in March. So, Agni was stolen in February. He robs Printer from Vayu, uses Pliers. Hook was not used for Tejas for Screwdriver was used to rob Tejas.