Table Chart — Part 2 MCQs with Explanations

Number of candidates not clearing the exam from state A in 2007 $$\eqalign{ & = \left\{1.98\times\left(100 - 41\right)\%\right\}\text{lakhs} \cr & = \left(1.98\times\frac{59}{100}\right)\text{lakhs} \cr & = \left(\frac{116.82}{100}\times100000\right) \cr & = 116820 \cr} $$

Average number of candidates appearing from state D in 2007, 2008, 2009 $$\eqalign{ & = \frac{1.88+1.83+2.01}{3}\text{ lakhs} \cr & = \frac{5.72}{3}\text{ lakhs} \cr & = \frac{5.72\times100000}{3} \cr & = \frac{572000}{3} \cr & = 190666\frac{2}{3} \cr} $$

$$\eqalign{ & \text{Required ratio} \cr & = \frac{1.04\text{ lakhs}\times51\%}{1.11\text{ lakhs}\times32\%} \cr & = \frac{1.04\times51}{1.11\times32} \cr & = \frac{104\times51}{111\times32} \cr & = \frac{13\times17}{37\times4} \cr & = \frac{221}{148} \cr & = 221:148 \cr} $$

Number of candidates clearing the exam from states E and F together in 2006. $$\eqalign{ & = \left(1.42\text{ lakhs}\times\frac{49}{100}\right)+\left(1.58\text{ lakhs}\times\frac{26}{100}\right) \cr & = \frac{\left(1.42\times49\right)+\left(1.58\times26\right)}{100}\text{ lakhs} \cr & = \frac{69.58+41.08}{100}\text{ lakhs} \cr & = \frac{110.66}{100}\times100000 \cr & = 110660 \cr} $$

Number of candidates clearing the exam from state D in $$\eqalign{ & 2008 → \left(1.83\times\frac{60}{100}\right)\text{lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{1.83\times3}{5}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{5.49}{5}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = 1.10\text{ lakhs} \cr & 2009 → \left(2.01\times\frac{56}{100}\right)\text{lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{2.01\times14}{25}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = \frac{28.14}{25}\text{ lakhs} \cr & \,\,\,\,\,\,\,\,\,\,\, = 1.12\text{ lakhs} \cr} $$ In rest of the years it is clearly less. So, it is maximum in the year 2009

Average number of female athletes from B over all the years. $$\eqalign{ & = \frac{\left(4.2+6.2+4.8+8.4+5.2+7.2\right)\times100}{6} \cr & = \frac{3600}{6} \cr & = 600 \cr} $$

Number of female athletes from E in 2009 = 9.2 × 100 = 920 Total number of athletes from B in 2008 = (11.4 + 8.4) × 100 = 19.8 × 100 = 1980 Let 920 = x% of 1980 Then, $$\eqalign{ & \Rightarrow \frac{x}{100}\times1980 = 920 \cr & \Rightarrow x = \frac{920 × 100}{1980} \cr & \,\,\,\,\,\,\,\,\, = \frac{4600}{99}\% \cr & \,\,\,\,\,\,\,\,\, = 46.46\% \cr & \,\,\,\,\,\,\,\,\, \approx 46\% \cr} $$

Total number of athletes from C in various years: 2005 → (4.5 + 3.1) × 100 = 7.6 × 100 = 760 2006 → (6.9 + 3.3) × 100 = 10.2 ×100 = 1020 2007 → (4.8 + 2.8) × 100 = 7.6 × 100 = 760 2008 → (6.6 + 4.2) × 100 = 10.8 × 100 = 1080 2009 → (7.9 + 6.3) × 100 = 14.2 × 100 = 1420 2010 → (10.8 + 6.9) × 100 = 17.7 × 100 = 1770 It was second highest in 2009. So, the correct answer is (E).

Number of male athletes in 2006 from C = 6.9 × 100 = 690 Number of male athletes in 2007 from C = 4.8 ×100 = 480 $$\eqalign{ & \therefore \text{Decrease }\% \cr & = \left(\frac{690-480}{690}\times100\right)\% \cr & = \left(\frac{210}{690}\times100\right)\% \cr & = \frac{700}{23} \% \cr & = 30.4\% \cr & \approx 30\% \cr} $$

In 2006, the difference between males and females in various countries was A → (6.6 - 4.2) × 100 = 2.4 × 100 = 240 B → (8.4 - 6.2) × 100 = 2.2 × 100 = 220 C → (6.9 - 3.3) × 100 = 3.6 × 100 = 360 D → (8.4 - 6.3) × 100 = 2.1 × 100 = 210 E → (7.8 - 5.2) × 100 = 2.6 × 100 = 260 It was second highest in E.

Let the total population of state R be x million. Then, population of state R above poverty line = [(100 - 24)% of x] million = $$\left(\frac{76}{100}\times x\right)$$ million And so, male population of state R above poverty line $$\left\{ \frac{2}{5}\times\left(\frac{76}{100}\times x\right)\right\}$$ million But, it is given that male population of state R above poverty line = 1.9 million $$\eqalign{ & \therefore \frac{2}{5}\times\left(\frac{76}{100}\times x\right) = 1.9 \cr & \Rightarrow x = \frac{5\times100\times1.9}{76\times2} \cr & \Rightarrow x = 6.25 \cr} $$ ∴ Total population of state R = 6.25 million

For state Q: Male population below poverty line = 2.4 million Let the female population below poverty line be $$x$$ million Then, $$\eqalign{ & 3 : 5 = 2.4 : x \cr & \Rightarrow x = \frac{5 \times 2.4}{3} \cr & \Rightarrow x = 4 \cr} $$ ∴ Total population below poverty line = (2.4 + 4) million = 6.4 million Let the total population of Q be $$p$$ Then, $$\eqalign{ & 25\% \text{ of }p = 6.4 \text{ million} \cr & \Rightarrow \frac{25}{100}\times p = 6.4 \cr & \Rightarrow p = 6.4\times4 \cr & \Rightarrow p = 25.6 \text{ million} \cr} $$ For state T: Male population below poverty line = 6 million Let the female population below poverty line be $$y$$ million Then, $$\eqalign{ & 5 : 3 = 6 : y \cr & \Rightarrow y = \frac{3\times6}{5} \cr & \Rightarrow y = 3.6 \cr} $$ ∴ Total population below poverty line = (6 + 3.6) million = 9.6 million Let the total population of state T be $$q$$ Then, $$\eqalign{ & 15\% \text{ of } q = 9.6 \text{ million} \cr & \Rightarrow \frac{15}{100} \times q = 9.6 \cr & \Rightarrow q = 9.6\times \frac{20}{3} \cr & \Rightarrow q = 64 \text{ million} \cr & \therefore \text{Required ratio} \cr & = \frac{p}{q} \cr & = \frac{25.6}{64} \cr & = 0.4 \cr & = \frac{4}{10} \cr & = \frac{2}{5} \cr & = 2 : 5 \cr & \text{So, the ratio of } \text{Q}:\text{T} = 2:5 \cr} $$

Total population of state S = 7 million ∴ Population above poverty line = {(100 - 19)% of 7} million = (81% of 7) million = 5.67 million And so, the number of females above poverty line in state S $$\eqalign{ & = \left(\frac{3}{7}\times5.67\right) \text{million} \cr & = 2.43 \text{ million} \cr} $$

Female population below poverty line for state P = 2.1 million. Let the male population below poverty line for state P be x million. Then, $$\eqalign{ & 5:6 = x:2.1 \cr & \Rightarrow \frac{x}{2.1} = \frac{5}{6} \cr & \Rightarrow x = \frac{2.1\times5}{6} \cr & \Rightarrow x = 1.75 \cr} $$ ∴ Population below poverty line for state P = (2.1 + 1.75) million = 3.85 million Let the population above poverty line for state P be y million. Since, 35% of the total population of state P is below poverty line, therefore 65% of the total population of state P is above poverty line. So, the ratio of population below poverty line to that above poverty line for state P is 35 : 65. $$\eqalign{ & \therefore 35 : 65 = 3.85 : y \cr & \Rightarrow y = \frac{65\times3.85}{35} \cr & \Rightarrow y = 7.15 \cr} $$ ∴ Population above poverty line for state P = 7.15 million and so, male population above poverty line for state P $$\eqalign{ & = \left(\frac{6}{13}\times 7.15\right) \text{million} \cr & = 3.3 \text{ million} \cr} $$

Total expenditure during 2009 = Rs. (324 + 101 + 3.84 + 41.6 + 74) lakh = Rs. 544.44 lakh

Total amount of bonus paid = Rs. (3 + 2.52 + 3.84 + 3.68 + 3.96) lakh = Rs. 17 lakh Total Amount of salary paid = Rs. (288 + 342 + 324 + 336 + 420) lakh = Rs. 1710 lakh ∴ Required % $$\eqalign{ & = \left(\frac{17}{1710}\times100\right)\% \cr & = \frac{170}{171}\% \cr & = 0.99\% \cr & \approx 1\% \cr} $$

Total amount of interest paid during the period = Rs. (23.4 + 32.5 + 41.6 + 36.4 + 49.4) lakh = Rs. 183.3 lakh Average amount of interest paid per year = $$\frac{183.3}{5}$$ lakh = Rs. 36.66 lakh

Total expenditure on Taxes = Rs. (83 + 108 + 74 + 88 + 98) lakh = Rs. 451 lakh Total expenditure of Fuel and Transport = Rs. (98 + 112 + 101 + 133 + 142) lakh = Rs. 586 lakh ∴ Required ratio $$\eqalign{ & = \frac{451}{586} \cr & = \frac{1}{1.3} \cr & = \frac{10}{13} \cr & = 10:13 \cr} $$

Total expenditure in 2007 = Rs. (288 + 98 + 3.00 + 23.4 + 83) lakh = Rs. 495.4 lakh Total expenditure in 2011 = Rs. (420 + 142 + 3.96 + 49.4 + 98) lakh = Rs. 713.36 lakh Let 495.4 = x % of 713.36 Then, $$\eqalign{ & \Rightarrow \frac{x}{100}\times713.36 = 495.4 \cr & \Rightarrow x = \frac{495.40}{713.36}\times100 \cr & \,\,\,\,\,\,\,\,\, = \frac{12385}{17834}\times100 \cr & \,\,\,\,\,\,\,\,\, = 69.4\% \cr & \,\,\,\,\,\,\,\,\, \approx 69\% \cr} $$

Number of girls in School B in 2009 = 5.9 × 100 = 590 Total Number of students in School E in 2006 = (5.5 + 3.6) × 100 = 9.1 × 100 = 910 $$\eqalign{ & \text{Required }\% \cr & = \left(\frac{590}{910}\times100\right)\% \cr & = \frac{5900}{91}\% \cr & = 64.8\% \cr & \approx 65\% \cr} $$

Total number of students in School E in various years: 2005 → (6.5 + 6.6) × 100 = 1310 2006 → (5.5 + 3.6) × 100 = 910 2007 → (2.7 + 2.4) × 100 = 510 2008 → (5.4 + 5.7) × 100 = 1110 2009 → (6.8 + 6.5) × 100 = 1330 2010 → (10.8 + 12.7) × 100 = 2350 It is highest in 2010, 2 nd highest in 2009 and 3 rd highest in 2005.

Average number of girls in School A over the years $$\eqalign{ & = \frac{\left(3.6+4.2+6.9+9.6+12.9+14.4\right)\times100}{6} \cr & = \frac{51.6\times100}{6} \cr & = \frac{5160}{6} \cr & = 860 \cr} $$

Number of boys in School D in 2007 = 6.4 × 100 = 640 Number of boys in School D in 2008 = 5.3 ×100 = 530 $$\eqalign{ & \text{Decrease }\% \cr & = \left(\frac{110}{640}\times100\right)\% \cr & = \frac{275}{16}\% \cr & = 17.1\% \cr & \approx 17\% \cr} $$

(Number of boys in C in 2009) : (Number of girls in A in 2009) $$\eqalign{ & = \left(8.7\times100\right) : \left(12.9\times100\right) \cr & = \frac{870}{1290} \cr & = \frac{29}{43} \cr & = 29 : 43 \cr} $$

Total import of all countries together in 2002 = Rs. 385 crore Now, in 2002 total export of all companies together = 90 + 100 + 65 + 25 + 110 + 120 = 510 crore ∴ Total profit in 2002 = 510 - 385 = 125 crore

Total export of country Q in 2001 = Rs. 50 crore Total export of country T in 2000 = Rs. 55 crore Total export = 50 + 55 = Rs. 105 crore Now, total export of country P in 2003 = $$\frac{105\times120}{100}$$ = Rs. 126 crore Total import of country P in 2003 = Rs. 92 crore Profit = 126 - 92 = Rs. 34 crore

Total export of all countries together in 1999 = 40 + 25 + 55 + 60 + 50 + 40 = Rs. 270 crore Total export of all countries together in 2001 = 45 + 50 + 90 + 15 + 100 + 75 = Rs. 375 crore $$\eqalign{ & \therefore \text{Required % increase} \cr & = \frac{375 - 270}{270}\times100 \cr & = \frac{105}{270}\times100 \cr & = \frac{350}{9}\% \cr & = 38.88\% \cr & \approx 38.89\% \cr} $$

Import of company S in the year 1998 = $$\frac{45\times2}{1}$$ = Rs. 90 crore Import of company U in the year 1998 = 24 × $$\frac{1}{4}$$ = Rs. 6 crore Total import of company U and S together in 1998 = Rs. (90 + 6) = Rs. 96 crore

Total export of country T = 60 + 50 + 55 + 100 + 110 = 375 Average export of country T = $$\frac{375}{5}$$ = Rs. 75 crore Total export of country R = 50 + 55 + 70 + 90 + 65 = 330 Average export of country R = $$\frac{330}{5}$$ = Rs. 66 crore $$\eqalign{ & \therefore \text{ Required } \% \cr & = \frac{75 - 66}{66}\times100 \cr & = \frac{9}{66}\times100 \cr & = \frac{150}{11}\% \cr & = 13\frac{7}{11}\% \cr} $$

Amount collected for commission in March = 31200 Amount collected for commission in July = 40000 ∴ Required percentage = $$\frac{8800}{40000}$$ × 100 = 22%

In May, ratio of amount allocated for commission and amount allocated for discount = 4 : 3 In May, amount allocated for commission = 4 × 12000 and 3 × 12000 Amount allocated for discount = 48000 and 36000 ∵ Gross revenue in May net revenue + amount allocated for commission = 336000 + 84000 = Rs. 420000

Gross revenue of July collected from advertisement = 362000 + 28000 + 40000 = 390000 + 40000 = 430000 Gross revenue collected from advertisement = 430000 × $$\frac{40}{100} $$ = 4300 × 40 = Rs. 172000

Net revenue in April = 320000 - 44000 = Rs. 276000 Gross revenue in June = 330000 + 72000 = Rs. 402000 ∴ Required difference = 402000 - 276000 = Rs. 126000

In march, Net revenue = 360000 × $$\frac{85}{100}$$ = 306000 ∴ Amount allocated for discount and others = 360000 - 306000 - 31200 = 54000 - 31200 = Rs. 22800

Total number of pages printed by printer C and D together on Tuesday = 164 + 189 = 353 Total number of pages printed by printer A and E together on Thursday = 89 + 113 = 202 ∴ Required difference = 353 - 202 = 151

Number of pages printed by printer E on Monday = 184 Number of pages printed by printer C on Thursday = 120 ∴ Required Percentage $$\eqalign{ & = \frac{184 - 120}{120}\times100 \cr & = \frac{6400}{120} \cr & = \frac{160}{3} \cr & = 53\frac{1}{3}\% \cr} $$

number of pages printed by printer A on Wednesday = 115 Number of pages printed by printer D on Friday = 160 ∴ Required percentage $$\eqalign{ & = \frac{115}{160}\times100 \cr & = \frac{575}{8} \cr & = 71\frac{7}{8} \cr} $$

Total number of pages printed by printer B on Wednesday and Thursday = 141 + 223 = 364 Total number of pages printed by printer C on Monday and Friday = 211 + 257 = 468 ∴ Required ratio = 364 : 468 = 7 : 9

Total number of pages printed by printer B on Monday, Tuesday and Friday = 147 + 189 + 93 = 429 ∴ Required average = $$\frac{429}{3}$$ = 143

Percentage of people below 36 years = (20 + 18.25 + 16.75)% = 55% 55% = 22 millions $$\eqalign{ & 1\% = \frac{22}{55} \cr & 12.5\% = \frac{22}{55} \times 12.5 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = 5 \text{ millions} \cr}$$