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Digital Communication — Part 1 MCQs with Explanations

Practice high-yield Electronics & Communications Engineering MCQs on Digital Communication — Part 1 with worked academic solutions for FPSC, PPSC, PTA, PAEC, NTS.

Questions
40
Difficulty Level
Exam-Level
Target Exams
FPSC, PPSC, PTA...
Estimated Time
48 mins
Exam-Level FPSC PPSC PTA PAEC NTS
Verified for Commission Syllabus • Oct 14, 2026
40

Verified Practice Questions

Interactive test mode with detailed academic worked solutions

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Question 1 of 40
★ FPSC ★ PPSC

A 4 GHz carrier is DSB-SC modulated by a low pass message signal with maximum frequency of 2 MHz. The resultant signal is to be ideally sampled. The minimum frequency of the sampling impulse train should be

Question 2 of 40
★ FPSC ★ PPSC

A video transmission system transmits 625 picture frames per second. Each frame consists of a 400 × 400 pixel grid with 64 intensity levels per pixel. The data rate of the system is

Question 3 of 40
★ FPSC ★ PPSC

The raised cosine pulse p(t) is used for zero ISI in digital communications. The expression for p(t) with unity roll-off factor is given by $$p\left( t \right) = \frac{{\sin 4\pi \omega t}}{{4\pi \omega t\left( {1 - 16{\omega ^2}{t^2}} \right)}}.$$ The value of p(t) at $$t = \frac{1}{{4\omega }}$$ is

Question 4 of 40
★ FPSC ★ PPSC

A sinusoidal signal of 2 kHz frequency is applied to a delta modulator. The sampling rate and step-size Δ of the delta modulator are 20,000 samples per second and 0.1 V, respectively. To prevent slope overload, the maximum amplitude of the sinusoidal signal (in Volts) is

Question 5 of 40
★ FPSC ★ PPSC

Coherent orthogonal binary FSK modulation is used to transmit two equiprobable symbol waveforms s 1 (t) = αcos2πf 1 t & s 2 (t) = αcos2πf 2 t 1 where α = 4 mV. Assume an AWGN channel with two-sided noise power spectral density $$\frac{{{N_0}}}{2} = 0.5 \times {10^{ - 12}}W/Hz.$$ Using an optimal receiver and the relation $$Q\left( v \right) = \frac{1}{{\sqrt {2\pi } }}\int\limits_v^\infty {{\theta ^{\frac{{{u^2}}}{2}}}du,} $$ the bit error probability for a data rate of 500 kbps is

Question 6 of 40
★ FPSC ★ PPSC

During transmission over a certain binary communication channel, bit errors occur independently with probability p. The probability of AT MOST one bit in error in a block of n bits is given by

Question 7 of 40
★ FPSC ★ PPSC

The message bit sequence to a DPSK modulator is 1, 1, 0, 0, 1, 1. The carrier phase during the reception of the first two message bits is π, π. The carrier phase for the remaining four message bits is

Question 8 of 40
★ FPSC ★ PPSC

A deterministic signal has the power spectrum given in figure. The minimum sampling rate needed to completely represent signal is

Question 9 of 40
★ FPSC ★ PPSC

During transmission over a communication channel, bit errors occur independently with probability p. If a block of n bits is transmitted, the probability of at most one bit error is equal to

Question 10 of 40
★ FPSC ★ PPSC

A signal having uniformly distributed amplitude in the interval (-V to + V), is to be encoded using PCM with uniform quantization. The signal to quantizing noise ratio is determined by the

Question 11 of 40
★ FPSC ★ PPSC

Companding in PCM systems lead to improved signal to quantization noise ratio. This improvement is for

Question 12 of 40
★ FPSC ★ PPSC

Consider a binary digital communication system with equally likely 0's and 1's. When binary 0 is transmitted the detector input can lie between the levels -0.25V and +0.25V with equal probability: when binary 1 is transmitted, the voltage at the detector can have any value between 0 and 1 V with equal probability. If the detector has a threshold of 0.2 V (i.e., if the received signal is greater than 0.2 V, the bit is taken as 1), the average bit error probability is

Question 13 of 40
★ FPSC ★ PPSC

A source produces binary data at the rate of 10 kbps. The binary symbols are represented as shown in the figure. The source output is transmitted using two modulation schemes, namely Binary PSK (BPSK) and Quadrature PSK (QPSK). Let and B2 be the bandwidth requirements of BPSK and QPSK respectively. Assuming that the bandwidth of the above rectangular pulses is 10 kHz, B 1 and B 2 are

Question 14 of 40
★ FPSC ★ PPSC

The modulation scheme commonly used for transmission from GSM mobile terminals is

Question 15 of 40
★ FPSC ★ PPSC

Consider a Binary Symmetric Channel (BSC) with probability of error being p. To transmit a bit, say 1, we transmit a sequence of three 1 s. The receiver will interpret the received sequence to represent 1 if at least two bits are 1. The probability that the transmitted bit will be received in error is

Question 16 of 40
★ FPSC ★ PPSC

The signal to quantization noise ratio in an n-bit PCM system

Question 17 of 40
★ FPSC ★ PPSC

Which one of the following statements about differential pulse code modulation (DPCM) is true?

Question 18 of 40
★ FPSC ★ PPSC

In delta modulation, the slope overload distortion can be reduced by

Question 19 of 40
★ FPSC ★ PPSC

Let x(t) = 2cos(800πt) + cos(1400πt).x(t) is sampled with the rectangular pulse train shown in the figure. The only spectral components (in kHz) present in the sampled signal in the frequency range 2.5 kHz to 3.5 kHz are

Question 20 of 40
★ FPSC ★ PPSC

If E b , the energy per bit of a binary digital signal, is 10 -5 Watt-sec and the one-sided power spectral density of the white noise, N 0 = 10 -6 W/Hz, then the output SNR of the matched filter is

Question 21 of 40
★ FPSC ★ PPSC

In a digital communication system employing Frequency Shift Keying (FSK), the 0 and 1 bit are represented by sine waves of 10 kHz and 25 kHz respectively. These waveforms will be orthogonal for a bit interval of

Question 22 of 40
★ FPSC ★ PPSC

If the number of bits per sample in a PCM system is increased from a n to n + 1, the improvement in signal to quantization nose ratio will be

Question 23 of 40
★ FPSC ★ PPSC

Flat top sampling of low pass signals

Question 24 of 40
★ FPSC ★ PPSC

The input to a matched filter is given by \[s\left( t \right) = \left\{ {\begin{array}{*{20}{c}} {10\sin \left( {2\pi \times {{10}^6}} \right)}&{0 < t < {{10}^{ - 4}}\sec } \\ 0&{{\text{Otherwise}}} \end{array}} \right.\] The peak amplitude of the filter output is

Question 25 of 40
★ FPSC ★ PPSC

At a given probability of error, binary coherent FSK is inferior to binary coherent PSK by

Question 26 of 40
★ FPSC ★ PPSC

For a bit-rate of 8 Kbps, the best possible values of the transmitted frequencies in a coherent binary FSK system are

Question 27 of 40
★ FPSC ★ PPSC

In the following figure the minimum value of the constant "C", which is to be added to y 1 (t) such that y 1 (t) and y 2 (t) are different, is

Question 28 of 40
★ FPSC ★ PPSC

A signal x(t) = 100cos(24π × 10 3 )t is ideally sampled with a sampling period of 50 psec and then passed through an ideal lowpass filter with cutoff frequency of 15 kHz. Which of the following frequencies is/are present at the filter output?

Question 29 of 40
★ FPSC ★ PPSC

In the output of a DM speech encoder, the consecutive pulses are of opposite polarity during time interval t 1 ≤ t ≤ t 2 . This indicates that during this interval

Question 30 of 40
★ FPSC ★ PPSC

A BPSK scheme operating over an AWGN channel with noise power spectral density of $$\frac{{{N_0}}}{2},$$ uses equiprobable signals $${s_1}\left( t \right) = \sqrt {\frac{{2E}}{T}} \sin \left( {{\omega _c}t} \right)$$ and $${s_2}\left( t \right) = \sqrt {\frac{{2E}}{T}} \sin \left( {{\omega _c}t} \right)$$ over the symbol internal (0, T). If the local oscillator in a coherent receiver is ahead in phase by 45° with respect to the received signal, the probability of error in the resulting system is

Question 31 of 40
★ FPSC ★ PPSC

Consider a sample signal \[y\left( t \right) = 5 \times {10^{ - 6}}x\left( t \right)\sum\nolimits_{ - \infty }^{ + \infty } {\delta \left( {t - n{T_s}} \right)} \] where x(t) = 10cos(8π × 10 3 )t and T s =100 μsec. When y(t) is passed through an ideal lowpass filter with a cutoff frequency of 5 kHz, the output of the filter is

Question 32 of 40
★ FPSC ★ PPSC

The Nyquist sampling frequency (in Hz) of a signal given by 6 × 10 4 sinC 3 (400t) ∗ 10 6 sinC 3 (100t) is

Question 33 of 40
★ FPSC ★ PPSC

In a PCM system, if the code word length is increased from 6 to 8 bits, the signal to quantization noise ratio improves by the factor

Question 34 of 40
★ FPSC ★ PPSC

Three analog signals, having bandwidths 1200 Hz, 600 Hz and 600 Hz, are sampled at their respective Nyquist rates, encoded with 12-bit words, and time division multiplexed. The bit rate for the multiplexed signal is

Question 35 of 40
★ FPSC ★ PPSC

The peak-to-peak input to an 8-bit PCM coder is 2 Volts. The signal power-to-quantization noise power ratio (in dB) for an input of 0.5cos(ω m t) is

Question 36 of 40
★ FPSC ★ PPSC

The Nyquist sampling rate for the signal $$s\left( t \right) = \frac{{\sin \left( {500\pi t} \right)}}{{\pi t}} \times \frac{{\sin \left( {700\pi t} \right)}}{{\pi t}}$$ is given by

Question 37 of 40
★ FPSC ★ PPSC

The bit rate of digital communication system is R kbits/s. The modulation used is 32-QAM. The minimum bandwidth required for |S| free transmission is

Question 38 of 40
★ FPSC ★ PPSC

A binary symmetric channel (BSC) has a transition probability of $$\frac{1}{8}.$$ If the binary transmit symbol X is such that $$P\left( {X = 0} \right) = \frac{9}{{10}},$$ then the probability of error for an optimum receiver will be

Question 39 of 40
★ FPSC ★ PPSC

Choose the correct one from among the alternatives a, b, c, dafter matching an item from Group 1 with the most appropriate item in Group 2 . Group 1 Group 2 1. FM P. Slope overload 2. DM Q. H-law 3. PSK R. Envelope detector 4. PCM S. Capture effect T. Hilbert transform U. Matched filter

Question 40 of 40
★ FPSC ★ PPSC

A source emits bit 0 with probability $$\frac{1}{3}$$ and bit 1 with probability $$\frac{2}{3}.$$ The emitted bits are communicated to the receiver. The receiver decides for either 0 or 1 based on the received value R. It is given that the conditional density functions of R as \[\begin{gathered} {f_{R|0}}\left( r \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{1}{4},}&{ - 3 \leqslant r \leqslant 1} \\ {0,}&{{\text{otherwise;}}} \end{array}} \right. \hfill \\ {f_{R|1}}\left( r \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{1}{6},}&{ - 1 \leqslant r \leqslant 5} \\ {0,}&{{\text{otherwise;}}} \end{array}} \right. \hfill \\ \end{gathered} \] The minimum decision error probability is

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