Practice high-yield Electronics & Communications Engineering MCQs on Signal Processing — Part 1 with worked academic solutions for FPSC, PPSC, PTA, PAEC, NTS.
Questions
40
Difficulty Level
Exam-Level
Target Exams
FPSC, PPSC, PTA...
Estimated Time
48 mins
Exam-Level FPSC PPSC PTA PAEC NTS
Verified for Commission Syllabus • Oct 14, 2026
40
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Question 1 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A signal x(t) has a Fourier transform X(ω). If x(t) is a real and odd function of t, then X(ω) is
Correct Answer: Option A — A real and even function of ω
Detailed Academic Explanation:
Here's the explanation for the given Fourier Transform question: The question asks about the properties of the Fourier Transform, X(ω), of a signal x(t) when x(t) is both real and odd. Here's a breakdown to understand the answer: Key Concepts: * Fourier Transform: A mathematical tool that decomposes a signal into its constituent frequencies. * Real Function: A function whose values are real numbers for all real inputs. * Odd Function: A function x(t) is odd if x(-t) = -x(t). Odd functions are symmetrical about the origin. * Even Function: A function x(t) is even if x(-t) = x(t). Even functions are symmetrical about the y-axis. Properties of Fourier Transform with Symmetry: * If x(t) is real, then X(ω) has Hermitian symmetry, meaning X(-ω) = X * (ω) where * denotes complex conjugate. In simpler terms, the real part of X(ω) is even, and the imaginary part is odd. * If x(t) is odd, the Fourier transform X(ω) is imaginary. This means it only contains imaginary components and no real components. Applying to the question: Since x(t) is both real and odd: 1. Because x(t) is real, we know X(ω) has Hermitian symmetry. 2. Because x(t) is odd, we know X(ω) is purely imaginary. Combining these two properties, if X(ω) is purely imaginary (say, X(ω) = j*Y(ω), where Y(ω) is a real-valued function) and has Hermitian symmetry, it means: X(-ω) = X * (ω) j*Y(-ω) = (j*Y(ω)) * j*Y(-ω) = -j*Y(ω) (because the conjugate of j is -j) Y(-ω) = -Y(ω) This means Y(ω) is an odd function. Since X(ω) = j*Y(ω), and Y(ω) is odd, then X(ω) itself is an imaginary and odd function. Therefore, the correct answer is Option B: An imaginary and odd function of ω
💡Key Conceptual Anchor:Signal Processing
Question 2 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
If G(f) represents the Fourier transform of a signal g(t) which is real and odd symmetric in time, then
Correct Answer: Option B — G(f) is imaginary
Detailed Academic Explanation:
Okay, let's break down this Fourier Transform question for beginners! The question is asking what happens to the Fourier Transform (G(f)) of a signal g(t) , when that signal is both real and odd-symmetric . Let's define each part: * Fourier Transform: Think of it as a way to see what frequencies make up a signal. It transforms a signal from the time domain (how it changes over time) to the frequency domain (how much of each frequency is present). * Real Signal: A signal is real if its values are real numbers (no imaginary part). Most signals we deal with in the real world are real (e.g., sound waves, voltage). * Odd Symmetry: A signal g(t) is odd-symmetric if g(-t) = -g(t). This means if you flip the signal around the y-axis and then flip it around the x-axis, you get the same signal back. A simple example is g(t) = t. Now, here's the key concept: The Fourier Transform has some properties related to symmetry. Important Relationship: When g(t) is real and odd , its Fourier Transform G(f) will be purely imaginary . Let's look at why the other options are incorrect. * Option A: G(f) is complex: While *any* Fourier Transform *can* be complex, the combination of real and odd symmetry *simplifies* it. * Option C: G(f) is real: A real and even signal in the time domain would give a real fourier transform. * Option D: G(f) is real and non-negative: A real and non-negative time-domain signal doesn't guarantee the same characteristics in the frequency domain. Therefore, the answer is Option B: G(f) is imaginary .
💡Key Conceptual Anchor:Signal Processing
Question 3 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
The Fourier transform of a real valued time signal has
Correct Answer: Option C — Conjugate symmetry
Detailed Academic Explanation:
Conjugate symmetry is the correct answer to “The Fourier transform of a real valued time signal has”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 4 of 40
★ FPSC
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★ FPSC
★ PPSC
The RMS value of a rectangular wave of period T, having a value of +V for a duration, T 1 (< T) and -V for the duration, T - T 1 = T 2 equals
Correct Answer: Option A — $$V$$
Detailed Academic Explanation:
$$V$$ is the correct answer to “The RMS value of a rectangular wave of period T, having a value of +V for a duration, T 1 (< T) and -V for the duration, T - T 1 = T 2 equals”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 5 of 40
★ FPSC
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★ FPSC
★ PPSC
A continuous time function x(t) is periodic with period T. The function is sampled uniformly with a sampling period T s . In which one of the following cases is the sampled signal periodic?
Correct Answer: Option B — T = 1.2Ts
Detailed Academic Explanation:
T = 1.2Ts is the correct answer to “A continuous time function x(t) is periodic with period T. The function is sampled uniformly with a sampling period T s . In which one of the following cases is the sampled signal periodic”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 6 of 40
★ FPSC
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The phase response of a passband waveform at the receiver is given by $$\varphi \left( f \right) = - 2\pi \alpha \left( {f - {f_c}} \right) - 2\alpha \beta {f_c},$$ where f c is the centre frequency, and α and β are positive constants. The actual signal propagation delay from the transmittance to receiver is
Correct Answer: Option C — α
Detailed Academic Explanation:
α is the correct answer to “The phase response of a passband waveform at the receiver is given by $$\varphi \left( f \right) = - 2\pi \alpha \left( {f - {f_c}} \right) - 2\alpha \beta {f_c},$$ where f c is the centre frequency, and α and β are positive constants. The actual signal propagation delay from the transmittance to receiver is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 7 of 40
★ FPSC
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★ FPSC
★ PPSC
For a given sample-and-hold circuit, if the value of the hold capacitor is increased, then
Correct Answer: Option B — Drop rate decreases and acquisition time increases
Detailed Academic Explanation:
Drop rate decreases and acquisition time increases is the correct answer to “For a given sample-and-hold circuit, if the value of the hold capacitor is increased, then”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 8 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A continuous time LTI system is described by $${{{d^2}y\left( t \right)} \over {d{t^2}}} + 4{{dy\left( t \right)} \over {dt}} + 3y\left( t \right) = 2{{dx\left( t \right)} \over {dt}} + 4x\left( t \right)$$ Assuming zero initial conditions, the response y(t) of the above system for the input x(t) = e -2t u(t) is given by
Correct Answer: Option B — (e-t - e-3t)u(t)
Detailed Academic Explanation:
(e-t - e-3t)u(t) is the correct answer to “A continuous time LTI system is described by $${{{d^2}y\left( t \right)} \over {d{t^2}}} + 4{{dy\left( t \right)} \over {dt}} + 3y\left( t \right) = 2{{dx\left( t \right)} \over {dt}} + 4x\left( t \right)$$ Assuming zero initial conditions, the response y(t) of the above system for the input x(t) = e -2t u(t) is given by”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 9 of 40
★ FPSC
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★ PPSC
A rectangular pulse train s(t) as shown in the figure is convolved with the signal cos 2 (4π × 10 3 t). The convolved signal will be a
Correct Answer: Option A — DC
Detailed Academic Explanation:
DC is the correct answer to “A rectangular pulse train s(t) as shown in the figure is convolved with the signal cos 2 (4π × 10 3 t). The convolved signal will be a”. This question is standard in competitive examination syllabi for Signal Processing.
$${{1 - \exp \left( { - {T_s}} \right)} \over s}$$ is the correct answer to “The transfer function of a zero-order hold is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 11 of 40
★ FPSC
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★ FPSC
★ PPSC
The 3-dB bandwidth of the low-pass signal e -t u(t), where u(t) is the unit step function, is given by
Correct Answer: Option A — $${1 \over {2\pi }}Hz$$
Detailed Academic Explanation:
$${1 \over {2\pi }}Hz$$ is the correct answer to “The 3-dB bandwidth of the low-pass signal e -t u(t), where u(t) is the unit step function, is given by”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 12 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A system is described by the differential equation $${{{d^2}y} \over {d{t^2}}} + 5{{dy} \over {dt}} + 6y\left( t \right) = x\left( t \right).$$ Let x(t) be a rectangular pulse given by $$x\left( t \right) = \left\{ {\matrix{ {1,} & {0 < t < 2} \cr {0,} & {{\rm{otherwise}}} \cr } } \right.$$ Assuming that y(0) = 0 and $${{dy} \over {dt}} = 0$$ at t = 0, the Laplace transform of y(t) is
$${{1 - {e^{ - 2s}}} \over {s\left( {s + 2} \right)\left( {s + 3} \right)}}$$ is the correct answer to “A system is described by the differential equation $${{{d^2}y} \over {d{t^2}}} + 5{{dy} \over {dt}} + 6y\left( t \right) = x\left( t \right).$$ Let x(t) be a rectangular pulse given by $$x\left( t \right) = \left\{ {\matrix{ {1,} & {0 < t < 2} \cr {0,} & {{\rm{otherwise}}} \cr } } \right.$$ Assuming that y(0) = 0 and $${{dy} \over {dt}} = 0$$ at t = 0, the Laplace transform of y(t) is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 13 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A signal containing only two frequency components (3 kHz and 6 kHz) is sampled at the rate of 8 kHz, and then passed through a low pass filter with a cut-off frequency of 8 kHz. The filter output
Correct Answer: Option D — Contains both the components of the original signal and two spurious components of 2 kHz and 5 kHz
Detailed Academic Explanation:
Contains both the components of the original signal and two spurious components of 2 kHz and 5 kHz is the correct answer to “A signal containing only two frequency components (3 kHz and 6 kHz) is sampled at the rate of 8 kHz, and then passed through a low pass filter with a cut-off frequency of 8 kHz. The filter output”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 14 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
If the signal $$x\left( t \right) = {{\sin \left( t \right)} \over {\pi t}} * {{\sin \left( t \right)} \over {\pi t}}$$ with $$ * $$ denoting the convolution operation, then x(t) is equal to
Correct Answer: Option A — $${{\sin \left( t \right)} \over {\pi t}}$$
Detailed Academic Explanation:
$${{\sin \left( t \right)} \over {\pi t}}$$ is the correct answer to “If the signal $$x\left( t \right) = {{\sin \left( t \right)} \over {\pi t}} * {{\sin \left( t \right)} \over {\pi t}}$$ with $$ * $$ denoting the convolution operation, then x(t) is equal to”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 15 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A sequence x(n) with the z-transform X(z) = z 4 + z 2 - 2z + 2 - 3z -4 is applied as an input to a linear, time-invariant system with the impulse response h(n) = 2δ(n - 3) where $$\delta \left( n \right) = \left\{ {\matrix{ {1,} & {n = 0} \cr {0,} & {{\rm{otherwise}}} \cr } } \right.$$ The output at n = 4 is
Correct Answer: Option B — Zero
Detailed Academic Explanation:
Zero is the correct answer to “A sequence x(n) with the z-transform X(z) = z 4 + z 2 - 2z + 2 - 3z -4 is applied as an input to a linear, time-invariant system with the impulse response h(n) = 2δ(n - 3) where $$\delta \left( n \right) = \left\{ {\matrix{ {1,} & {n = 0} \cr {0,} & {{\rm{otherwise}}} \cr } } \right.$$ The output at n = 4 is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 16 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
The Laplace transform of i(t) is given by $$I\left( s \right) = {2 \over {s\left( {1 + s} \right)}}$$ As t → ∞, the value of i(t) tends to
Correct Answer: Option C — 2
Detailed Academic Explanation:
2 is the correct answer to “The Laplace transform of i(t) is given by $$I\left( s \right) = {2 \over {s\left( {1 + s} \right)}}$$ As t → ∞, the value of i(t) tends to”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 17 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A real-valued signal x(t) limited to the frequency band $$\left| f \right| \le {W \over 2}$$ is passed through a linear time invariant system whose frequency response is $$H\left( f \right) = \left\{ {\matrix{ {{e^{ - j4\pi f,}}} & {\left| f \right| \le {W \over 2}} \cr {0,} & {\left| f \right| > {W \over 2}} \cr } } \right.$$ The output of the system is
Correct Answer: Option D — x(t - 2)
Detailed Academic Explanation:
x(t - 2) is the correct answer to “A real-valued signal x(t) limited to the frequency band $$\left| f \right| \le {W \over 2}$$ is passed through a linear time invariant system whose frequency response is $$H\left( f \right) = \left\{ {\matrix{ {{e^{ - j4\pi f,}}} & {\left| f \right| \le {W \over 2}} \cr {0,} & {\left| f \right| > {W \over 2}} \cr } } \right.$$ The output of the system is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 18 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
The signal x(t) = sin(14000πt), where t is in seconds is sampled at a rate of 9000 samples per second. The sampled signal is the input to an ideal lowpass filter with frequency response H(t) as follows: \[H\left( f \right) = \left\{ {\begin{array}{*{20}{c}} {1,}&{\left| f \right| \leqslant 12kHz} \\ {0,}&{\left| f \right| > 12kHz} \end{array}} \right.\] What is the number of sinusoids in the output and their frequencies in kHz?
Correct Answer: Option B — Number = 3, frequencies = 2, 7, 11
Detailed Academic Explanation:
Number = 3, frequencies = 2, 7, 11 is the correct answer to “The signal x(t) = sin(14000πt), where t is in seconds is sampled at a rate of 9000 samples per second. The sampled signal is the input to an ideal lowpass filter with frequency response H(t) as follows: \[H\left( f \right) = \left\{ {\begin{array}{*{20}{c}} {1,}&{\left| f \right| \leqslant 12kHz} \\ {0,}&{\left| f \right| > 12kHz} \end{array}} \right.\] What is the number of sinusoids in the output and their frequencies in kHz”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 19 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A signal $$2\cos \left( {{{2\pi } \over 3}t} \right) - \cos \left( {\pi t} \right)$$ is the input to an LTI system with the transfer function $$H\left( s \right) = {e^s} + {e^{ - s}}$$ If C k denote the k th coefficient in the exponential Fourier series of the output signal, then C 3 is equal to
Correct Answer: Option B — 1
Detailed Academic Explanation:
1 is the correct answer to “A signal $$2\cos \left( {{{2\pi } \over 3}t} \right) - \cos \left( {\pi t} \right)$$ is the input to an LTI system with the transfer function $$H\left( s \right) = {e^s} + {e^{ - s}}$$ If C k denote the k th coefficient in the exponential Fourier series of the output signal, then C 3 is equal to”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 20 of 40
★ FPSC
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★ PPSC
Let $$g\left( t \right) = {e^{ - \pi {t^2}}}$$ and h(t) is a filter matched to g(t). If g(t) is applied as input to h(t), then the Fourier transform of the output is
Correct Answer: Option D — $${e^{ - 2\pi {t^2}}}$$
Detailed Academic Explanation:
$${e^{ - 2\pi {t^2}}}$$ is the correct answer to “Let $$g\left( t \right) = {e^{ - \pi {t^2}}}$$ and h(t) is a filter matched to g(t). If g(t) is applied as input to h(t), then the Fourier transform of the output is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 21 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A band-limited signal with a maximum frequency of 5 kHz is to be sampled. According to the sampling theorem, the sampling frequency which is not valid is
Correct Answer: Option A — 5 kHz
Detailed Academic Explanation:
5 kHz is the correct answer to “A band-limited signal with a maximum frequency of 5 kHz is to be sampled. According to the sampling theorem, the sampling frequency which is not valid is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 22 of 40
★ FPSC
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★ FPSC
★ PPSC
The result of the convolution x(- t) ∗ δ(- t - t 0 ) is
Correct Answer: Option D — x(- t - t0)
Detailed Academic Explanation:
x(- t - t0) is the correct answer to “The result of the convolution x(- t) ∗ δ(- t - t 0 ) is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 23 of 40
★ FPSC
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Two discrete time systems with impulse responses h 1 [n] = δ[n - 1] and h 2 [n] = δ[n - 2] are connected in cascade. The overall impulse response of the cascaded system is
Correct Answer: Option C — δ[n - 3]
Detailed Academic Explanation:
δ[n - 3] is the correct answer to “Two discrete time systems with impulse responses h 1 [n] = δ[n - 1] and h 2 [n] = δ[n - 2] are connected in cascade. The overall impulse response of the cascaded system is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 24 of 40
★ FPSC
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★ PPSC
The ACF of a rectangular pulse of duration T is
Correct Answer: Option D — A triangular pulse of duration 2T
Detailed Academic Explanation:
A triangular pulse of duration 2T is the correct answer to “The ACF of a rectangular pulse of duration T is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 25 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
Assuming zero initial condition, the response y(t) of the system given below to a unit step input u(t) is \[\xrightarrow{{U\left( s \right)}}\boxed{\frac{1}{s}}\xrightarrow{{Y\left( s \right)}}\]
Correct Answer: Option B — tu(t)
Detailed Academic Explanation:
tu(t) is the correct answer to “Assuming zero initial condition, the response y(t) of the system given below to a unit step input u(t) is \[\xrightarrow{{U\left( s \right)}}\boxed{\frac{1}{s}}\xrightarrow{{Y\left( s \right)}}\]”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 26 of 40
★ FPSC
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★ FPSC
★ PPSC
Let x(t) ↔ X(jω) be Fourier Transform pair. The Fourier Transform of the signal x(5t - 3) in terms of X(jω) is given as
$${1 \over 5}{e^{-{{j3\omega } \over 5}}}X\left( {{{j\omega } \over 5}} \right)$$ is the correct answer to “Let x(t) ↔ X(jω) be Fourier Transform pair. The Fourier Transform of the signal x(5t - 3) in terms of X(jω) is given as”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 27 of 40
★ FPSC
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★ PPSC
A 1.0 kHz signal is flat-top sampled at the rate of 1800 samples/sec and the samples are applied to an ideal rectangular LPF with cut-off frequency of 1100 Hz, then the output of the filter contains
Correct Answer: Option B — 800 Hz and 900 Hz components
Detailed Academic Explanation:
800 Hz and 900 Hz components is the correct answer to “A 1.0 kHz signal is flat-top sampled at the rate of 1800 samples/sec and the samples are applied to an ideal rectangular LPF with cut-off frequency of 1100 Hz, then the output of the filter contains”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 28 of 40
★ FPSC
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The input and output of a continuous time system are respectively denoted by x(t) and y(t). Which of the following descriptions corresponds to a casual system?
Correct Answer: Option C — y(t) = (t + 4)x(t - 1)
Detailed Academic Explanation:
y(t) = (t + 4)x(t - 1) is the correct answer to “The input and output of a continuous time system are respectively denoted by x(t) and y(t). Which of the following descriptions corresponds to a casual system”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 29 of 40
★ FPSC
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The impulse response of a continuous time system is given by h(t) = δ(t - 1) + δ(t - 3). The value of the step response at t = 2 is
Correct Answer: Option B — 1
Detailed Academic Explanation:
1 is the correct answer to “The impulse response of a continuous time system is given by h(t) = δ(t - 1) + δ(t - 3). The value of the step response at t = 2 is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 30 of 40
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Choose the function f(t), -∞ < t < ∞, for which a Fourier series cannot be defined?
Correct Answer: Option C — exp (-|t|)sin (25t)
Detailed Academic Explanation:
exp (-|t|)sin (25t) is the correct answer to “Choose the function f(t), -∞ < t < ∞, for which a Fourier series cannot be defined”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 31 of 40
★ FPSC
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★ PPSC
The Laplace transform of a function f(t) u(t), where f(t) is periodic with period T, is A(s) times the Laplace transform of its first period. Then
$$A\left( s \right) = {1 \over {\left( {1 - \exp \left( { - {T_s}} \right)} \right)}}$$ is the correct answer to “The Laplace transform of a function f(t) u(t), where f(t) is periodic with period T, is A(s) times the Laplace transform of its first period. Then”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 32 of 40
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The DFT of a vector [a b c d] is the vector [α β γ δ]. Consider the product \[\left[ {p\,q\,r\,s} \right] = \left[ {a\,b\,c\,d} \right]\left[ {\begin{array}{*{20}{c}} a&b&c&d \\ d&a&b&c \\ c&d&a&b \\ b&c&d&a \end{array}} \right]\] The DFT of the vector [p q r s] is a scaled version of
Correct Answer: Option A — [α2 β2 γ2 δ2]
Detailed Academic Explanation:
[α2 β2 γ2 δ2] is the correct answer to “The DFT of a vector [a b c d] is the vector [α β γ δ]. Consider the product \[\left[ {p\,q\,r\,s} \right] = \left[ {a\,b\,c\,d} \right]\left[ {\begin{array}{*{20}{c}} a&b&c&d \\ d&a&b&c \\ c&d&a&b \\ b&c&d&a \end{array}} \right]\] The DFT of the vector [p q r s] is a scaled version of”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 33 of 40
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The Laplace transform of a continuous-time signal x(t) is $$X\left( s \right) = {{5 - s} \over {{s^2} - s - 2}}.$$ If the Fourier transform of this signal exists, then x(t) is
Correct Answer: Option C — -e2tu(-t) - 2e-tu(t)
Detailed Academic Explanation:
-e2tu(-t) - 2e-tu(t) is the correct answer to “The Laplace transform of a continuous-time signal x(t) is $$X\left( s \right) = {{5 - s} \over {{s^2} - s - 2}}.$$ If the Fourier transform of this signal exists, then x(t) is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 34 of 40
★ FPSC
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★ PPSC
A network consisting of a finite number of linear resistor (R), inducer (L), and capacitor (C) elements, connected all in series or all in parallel, is excited with a source of the form $$\sum\limits_{k = 1}^3 {{a_x}\,\cos \left( {k{\omega _0}t} \right),{\rm{were}}\,{a_k} \ne 0,} \,{\omega _0} \ne 0.$$ The source has nonzero impedance. Which one of the following is a possible form of the output measured across a resistor in the network?
$$\sum\limits_{k = 1}^3 {{a_x}\,\cos \left( {k{\omega _0}t + {\phi _k}} \right)} $$ is the correct answer to “A network consisting of a finite number of linear resistor (R), inducer (L), and capacitor (C) elements, connected all in series or all in parallel, is excited with a source of the form $$\sum\limits_{k = 1}^3 {{a_x}\,\cos \left( {k{\omega _0}t} \right),{\rm{were}}\,{a_k} \ne 0,} \,{\omega _0} \ne 0.$$ The source has nonzero impedance. Which one of the following is a possible form of the output measured across a resistor in the network”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 35 of 40
★ FPSC
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★ PPSC
The complex envelope of the bandpass signal $$x\left( t \right) = \sqrt 2 \left( {{{\sin \left( {{{\pi t} \over 5}} \right)} \over {{{\pi t} \over 5}}}} \right)\sin \left( {\pi t - {\pi \over 4}} \right),$$ centered about $$f = {1 \over 2}Hz,$$ is
$$\sqrt 2 \left( {{{\sin \left( {{{\pi t} \over 5}} \right)} \over {{{\pi t} \over 5}}}{e^{j{\pi \over 4}}}} \right)$$ is the correct answer to “The complex envelope of the bandpass signal $$x\left( t \right) = \sqrt 2 \left( {{{\sin \left( {{{\pi t} \over 5}} \right)} \over {{{\pi t} \over 5}}}} \right)\sin \left( {\pi t - {\pi \over 4}} \right),$$ centered about $$f = {1 \over 2}Hz,$$ is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 36 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
The power in the signal $$s\left( t \right) = 8\cos \left( {20\pi t - {\pi \over 2}} \right) + 4\,\sin \left( {15\pi t} \right)$$ is
Correct Answer: Option A — 40
Detailed Academic Explanation:
40 is the correct answer to “The power in the signal $$s\left( t \right) = 8\cos \left( {20\pi t - {\pi \over 2}} \right) + 4\,\sin \left( {15\pi t} \right)$$ is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 37 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
A 5-point sequence x[n] is given as x[-3] = 1, x[-2] = 1, x[-1] = 0, x[0] = 5, x[1] = 1. Let X(e jω ) denote the discrete-time Fourier transform of x[n]. The value of $$\int\limits_{ - \pi }^\pi {X\left( {{e^{j\omega }}} \right)} d\omega $$
Correct Answer: Option B — 10π
Detailed Academic Explanation:
10π is the correct answer to “A 5-point sequence x[n] is given as x[-3] = 1, x[-2] = 1, x[-1] = 0, x[0] = 5, x[1] = 1. Let X(e jω ) denote the discrete-time Fourier transform of x[n]. The value of $$\int\limits_{ - \pi }^\pi {X\left( {{e^{j\omega }}} \right)} d\omega $$”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 38 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
The Fourier series representation of an impulse train denoted by $$s\left( t \right) = \sum\limits_{n = - \infty }^\infty {\delta \left( {t - n{T_0}} \right)} \,{\rm{is}}\,{\rm{given}}\,{\rm{by}}$$
$${1 \over {{T_0}}}\sum\limits_{n = - \infty }^\infty {\exp \left( { - {{j2\pi nt} \over {{T_0}}}} \right)} $$ is the correct answer to “The Fourier series representation of an impulse train denoted by $$s\left( t \right) = \sum\limits_{n = - \infty }^\infty {\delta \left( {t - n{T_0}} \right)} \,{\rm{is}}\,{\rm{given}}\,{\rm{by}}$$”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 39 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
Let Y(s) be the unit-step response of a causal system having a transfer function $$G\left( s \right) = {{3 - s} \over {\left( {s + 1} \right)\left( {s + 3} \right)}}$$ That is, $$Y\left( s \right) = {{G\left( s \right)} \over s}.$$ The forced response of the system is
u(t) - 2e-t u(t) + e-3t u(t) is the correct answer to “Let Y(s) be the unit-step response of a causal system having a transfer function $$G\left( s \right) = {{3 - s} \over {\left( {s + 1} \right)\left( {s + 3} \right)}}$$ That is, $$Y\left( s \right) = {{G\left( s \right)} \over s}.$$ The forced response of the system is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
Question 40 of 40
★ FPSC
★ PPSC
★ FPSC
★ PPSC
Consider the system shown in the figure below. The transfer function $$\frac{{Y\left( z \right)}}{{X\left( z \right)}}$$ of the system is
$$\frac{{1 + a{z^{ - 1}}}}{{1 + b{z^{ - 1}}}}$$ is the correct answer to “Consider the system shown in the figure below. The transfer function $$\frac{{Y\left( z \right)}}{{X\left( z \right)}}$$ of the system is”. This question is standard in competitive examination syllabi for Signal Processing.
💡Key Conceptual Anchor:Signal Processing
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Analog Electronics — Part 1
Master the next curriculum module with 40 exam-standard MCQs.
💡Examiner's Advisory for Electronics & Communications Engineering
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.