Metallurgical Thermodynamics And Kinetics — Part 1 MCQs with Explanations
Practice high-yield Metallurgical Engineering MCQs on Metallurgical Thermodynamics And Kinetics — Part 1 with worked academic solutions for PAEC, NESCOM, HIT, FPSC.
Questions
40
Difficulty Level
Exam-Level
Target Exams
PAEC, NESCOM, HIT...
Estimated Time
48 mins
Exam-Level PAEC NESCOM HIT FPSC
Verified for Commission Syllabus • Oct 14, 2026
40
Verified Practice Questions
Interactive test mode with detailed academic worked solutions
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🎉 Set complete! All 40 questions answered.
Question 1 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The intensive thermodynamic variables among the following are: P. Pressure Q. Volume R. Temperature S. Enthalpy
Correct Answer: Option B — P, R
Detailed Academic Explanation:
P. Pressure is an intensive variable because it remains the same regardless of the system's size or quantity. Q. Volume is an extensive variable because it depends on the size or amount of the system. R. Temperature is an intensive variable because it remains constant regardless of the system's size or quantity. S. Enthalpy is an extensive variable because it depends on the size or amount of the system. Based on the given options, the correct answer is: B. P, R
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 2 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
What is enthalpy?
Correct Answer: Option A — Heat of any system
Detailed Academic Explanation:
Heat of any system is the correct answer to “What is enthalpy”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 3 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
What are the types of entropy?
Correct Answer: Option C — Both A and B
Detailed Academic Explanation:
Both A and B is the correct answer to “What are the types of entropy”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 4 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Single component system is called
Correct Answer: Option C — unary system
Detailed Academic Explanation:
unary system is the correct answer to “Single component system is called”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 5 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The specific heat (C p ) of pure iron expressed in J/(mol.K) as a function of temperature T (in K) is given as: C p = 17.49 + 24.77 × 10 -3 T What is the change in the enthalpy of pure iron (in J/mol) when it is heated from 25°C to 700°C?
Correct Answer: Option B — 22400
Detailed Academic Explanation:
22400 is the correct answer to “The specific heat (C p ) of pure iron expressed in J/(mol.K) as a function of temperature T (in K) is given as: C p = 17.49 + 24.77 × 10 -3 T What is the change in the enthalpy of pure iron (in J/mol) when it is heated from 25°C to 700°C”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 6 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Liquid steel contains initially 0.05 mass% P and this has to be reduced to 0.01 mass% using a basic slag. The equilibrium distribution ratio of P between slag and metal is $$Lp = \frac{{\left( {\% P} \right){\text{slag}}}}{{\left( {\% P} \right){\text{metal}}}}, = 80;$$ Assuming that in itially the slag does not contain any phosphorous (P), then the minimum weight of slag (ton) required per ton of steel is
Correct Answer: Option B — 0.05
Detailed Academic Explanation:
0.05 is the correct answer to “Liquid steel contains initially 0.05 mass% P and this has to be reduced to 0.01 mass% using a basic slag. The equilibrium distribution ratio of P between slag and metal is $$Lp = \frac{{\left( {\% P} \right){\text{slag}}}}{{\left( {\% P} \right){\text{metal}}}}, = 80;$$ Assuming that in itially the slag does not contain any phosphorous (P), then the minimum weight of slag (ton) required per ton of steel is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 7 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The fugacity of liquid water at 298 K is approximately 3171 Pa. Considering the ideal heat of vaporisation as 43723 J/gm. mole, its fugacity at 300 K would be . . . . . . . . Pascal.
Correct Answer: Option B — 3567
Detailed Academic Explanation:
3567 is the correct answer to “The fugacity of liquid water at 298 K is approximately 3171 Pa. Considering the ideal heat of vaporisation as 43723 J/gm. mole, its fugacity at 300 K would be . . . . . . . . Pascal.”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 8 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Intensive thermodynamic variables are:
Correct Answer: Option A — independent of the number of moles in the system
Detailed Academic Explanation:
independent of the number of moles in the system is the correct answer to “Intensive thermodynamic variables are:”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 9 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
In a dilute solution of elements X, Y etc. in liquid iron, the effect of Y on the activity co-efficient (fx) and the activity (hx) of X with respect to the Henrian 1wt% standard state is taken into account by the activity interaction co-efficient e y x , which is
$$e_x^y = \frac{{\partial \log fx}}{{\partial \left[ {\% Y} \right]}}$$ is the correct answer to “In a dilute solution of elements X, Y etc. in liquid iron, the effect of Y on the activity co-efficient (fx) and the activity (hx) of X with respect to the Henrian 1wt% standard state is taken into account by the activity interaction co-efficient e y x , which is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 10 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The rate of sequential multistep reaction, in a chemically controlled process, is expressed by the Arrhenius equation, $$k = A{e^{\left( { - \frac{Q}{{RT}}} \right)}}.$$ During an infinitesimallv small time step, this rate refers to the
Correct Answer: Option B — rate of the slowest step in the reaction
Detailed Academic Explanation:
rate of the slowest step in the reaction is the correct answer to “The rate of sequential multistep reaction, in a chemically controlled process, is expressed by the Arrhenius equation, $$k = A{e^{\left( { - \frac{Q}{{RT}}} \right)}}.$$ During an infinitesimallv small time step, this rate refers to the”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 11 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The entropy change, for a spontaneous process is
Correct Answer: Option D — < 0 for the system and the surrounding
Detailed Academic Explanation:
< 0 for the system and the surrounding is the correct answer to “The entropy change, for a spontaneous process is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 12 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The expression of chemical potential for binary real solution having components A and B are
Correct Answer: Option C — Both A and B
Detailed Academic Explanation:
Both A and B is the correct answer to “The expression of chemical potential for binary real solution having components A and B are”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 13 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
In a homogenous system (with C as the number of components) in equilibrium, the total number of independent intensive thermodynamic variable is
Correct Answer: Option C — C + 1
Detailed Academic Explanation:
C + 1 is the correct answer to “In a homogenous system (with C as the number of components) in equilibrium, the total number of independent intensive thermodynamic variable is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 14 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
For a reaction A ⟶ B, if the rate of change in concentration of A (C A ), can be written as $$\frac{{ - dCA}}{{dt}} = k.C_A^2,$$ then the change concentration with time from initial concentration of A, Cao is given by
$$\left( {\frac{1}{{{C_A}}}} \right) - \left( {\frac{1}{{{C_{AO}}}}} \right) = K.t$$ is the correct answer to “For a reaction A ⟶ B, if the rate of change in concentration of A (C A ), can be written as $$\frac{{ - dCA}}{{dt}} = k.C_A^2,$$ then the change concentration with time from initial concentration of A, Cao is given by”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 15 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
What are the ways through atoms can move inside the materials?
Correct Answer: Option D — All are correct
Detailed Academic Explanation:
All are correct is the correct answer to “What are the ways through atoms can move inside the materials”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 16 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Maxwell equation $${\left( {\frac{{\partial P}}{{\partial T}}} \right)_V} = {\left( {\frac{{\partial S}}{{\partial V}}} \right)_T}$$ is produced from which of the following equation
Correct Answer: Option C — dA = - PdV - SdT
Detailed Academic Explanation:
dA = - PdV - SdT is the correct answer to “Maxwell equation $${\left( {\frac{{\partial P}}{{\partial T}}} \right)_V} = {\left( {\frac{{\partial S}}{{\partial V}}} \right)_T}$$ is produced from which of the following equation”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 17 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The activity coefficient of Q in a liquid Q - R alloy is represented by the following equation at a given temperature. In γ Q = 0.6x 2 R - 0.2.x 3 R What is the activity of Q in an alloy of composition XR = 0.6 at the same temperature?
Correct Answer: Option D — 0.48
Detailed Academic Explanation:
0.48 is the correct answer to “The activity coefficient of Q in a liquid Q - R alloy is represented by the following equation at a given temperature. In γ Q = 0.6x 2 R - 0.2.x 3 R What is the activity of Q in an alloy of composition XR = 0.6 at the same temperature”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 18 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Match the following: Group 1 Group 2 P. Debye temperature 1. Rate constant Q. State property 2. Specific heat R. Thermodynamic probability 3. Internal energy S. Activation energy 4. Microstate in a macrostate
Correct Answer: Option B — P-4, Q-3, R-2, S-1
Detailed Academic Explanation:
P-4, Q-3, R-2, S-1 is the correct answer to “Match the following: Group 1 Group 2 P. Debye temperature 1. Rate constant Q. State property 2. Specific heat R. Thermodynamic probability 3. Internal energy S. Activation energy 4. Microstate in a macrostate”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 19 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Match the following: Group 1 Group 2 P. Volume 1. State function Q. Temperature 2. Intensive property R. Work done 3. Extensive property S. Molar entropy 4. Path dependent
Correct Answer: Option D — P-3, Q-2, R-4, S-1
Detailed Academic Explanation:
P-3, Q-2, R-4, S-1 is the correct answer to “Match the following: Group 1 Group 2 P. Volume 1. State function Q. Temperature 2. Intensive property R. Work done 3. Extensive property S. Molar entropy 4. Path dependent”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 20 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Chemical potential of a component 1 in a binary solution can be defined as
Correct Answer: Option D — $$\left( {\frac{{\partial G}}{{\partial {n_1}}}} \right)S,p,{n_2}$$
Detailed Academic Explanation:
$$\left( {\frac{{\partial G}}{{\partial {n_1}}}} \right)S,p,{n_2}$$ is the correct answer to “Chemical potential of a component 1 in a binary solution can be defined as”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 21 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The oxidation reaction lines of metals/nonmetals parallel to x- axis in Ellingham diagram is corresponds to
Correct Answer: Option A — Change in entropy zero
Detailed Academic Explanation:
Change in entropy zero is the correct answer to “The oxidation reaction lines of metals/nonmetals parallel to x- axis in Ellingham diagram is corresponds to”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 22 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
What is the temperature range for CO where it can act as reducing agent for iron oxide reduction
Correct Answer: Option A — Less than 1000°C
Detailed Academic Explanation:
Less than 1000°C is the correct answer to “What is the temperature range for CO where it can act as reducing agent for iron oxide reduction”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 23 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The activity of pure hydrogen gas at 1000°C and 5 atm. pressure.
Correct Answer: Option D — depends on the choice of the standard state
Detailed Academic Explanation:
depends on the choice of the standard state is the correct answer to “The activity of pure hydrogen gas at 1000°C and 5 atm. pressure.”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 24 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
If two system P & Q are in thermal equi librium with a third system M, then P and Q will also be in thermal equilibrium with each other. This is following . . . . . . . . law of thermodynamics.
Correct Answer: Option D — zeroth
Detailed Academic Explanation:
zeroth is the correct answer to “If two system P & Q are in thermal equi librium with a third system M, then P and Q will also be in thermal equilibrium with each other. This is following . . . . . . . . law of thermodynamics.”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 25 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
As the temperature increases, the solubility of gas in molten metal . . . . . . . . at constant pressure
Correct Answer: Option A — increase
Detailed Academic Explanation:
increase is the correct answer to “As the temperature increases, the solubility of gas in molten metal . . . . . . . . at constant pressure”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 26 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
A chemical reaction whose rate does not depend on concentration of reactants is called
Correct Answer: Option A — Zero order reaction
Detailed Academic Explanation:
Zero order reaction is the correct answer to “A chemical reaction whose rate does not depend on concentration of reactants is called”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 27 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
If k is the rate constant for a reaction and T is the absolute temperature in the given figure, the activation energy for the reaction is . . . . . . . . J/K mole.
Correct Answer: Option D — 8314
Detailed Academic Explanation:
8314 is the correct answer to “If k is the rate constant for a reaction and T is the absolute temperature in the given figure, the activation energy for the reaction is . . . . . . . . J/K mole.”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 28 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The erder of a chemical reaction
Correct Answer: Option B — can be determined from the stoichiometry of the reaction
Detailed Academic Explanation:
can be determined from the stoichiometry of the reaction is the correct answer to “The erder of a chemical reaction”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 29 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
In reaction equilibria occuring between pure condensed phases and a gas phase, the equilibrium constant, K
Correct Answer: Option A — can be written solely in terms of those species which occur only in the gas phase
Detailed Academic Explanation:
can be written solely in terms of those species which occur only in the gas phase is the correct answer to “In reaction equilibria occuring between pure condensed phases and a gas phase, the equilibrium constant, K”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 30 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
When one mole of the substance is completely burnt in oxygen. The heat evolve is known
Correct Answer: Option A — Heat of combustion
Detailed Academic Explanation:
Heat of combustion is the correct answer to “When one mole of the substance is completely burnt in oxygen. The heat evolve is known”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 31 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
If 'Δx' represents adherent oxide layer thickness and 't' is time, which of the following curves represents diffusion controlled oxidation kinetics?
Correct Answer: Option B — Q
Detailed Academic Explanation:
Q is the correct answer to “If 'Δx' represents adherent oxide layer thickness and 't' is time, which of the following curves represents diffusion controlled oxidation kinetics”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 32 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The reduction of FeO with CO gas in co-current flow is given by the following equation: FeO + CO = Fe + CO 2 , ΔG° = 8120 J at 1173K The ratio of pco/pco 2 for this reaction at 1173K is
Correct Answer: Option D — 2.3
Detailed Academic Explanation:
2.3 is the correct answer to “The reduction of FeO with CO gas in co-current flow is given by the following equation: FeO + CO = Fe + CO 2 , ΔG° = 8120 J at 1173K The ratio of pco/pco 2 for this reaction at 1173K is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 33 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Zinc oxide is reduced at a constant temperature in a closed reactor using ZnO(s) and C(s) as the only starting materials. The following reactions are assumed to be at thermodynamic equilibrium: ZnO(s) + C(s) = Zn(g) + CO(g) 2CO(g) = CO 2 (g) + C(s) Assume ideal gas behaviour. Based on mole balance, the relationship applicable to the system at equilibrium is
Correct Answer: Option A — Pzn = Pco + 2Pco2
Detailed Academic Explanation:
Pzn = Pco + 2Pco2 is the correct answer to “Zinc oxide is reduced at a constant temperature in a closed reactor using ZnO(s) and C(s) as the only starting materials. The following reactions are assumed to be at thermodynamic equilibrium: ZnO(s) + C(s) = Zn(g) + CO(g) 2CO(g) = CO 2 (g) + C(s) Assume ideal gas behaviour. Based on mole balance, the relationship applicable to the system at equilibrium is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 34 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
For the irreversible reaction, Ca + C = CaC 2 , ΔH° 298 = - 60,000 J.mol -1 . If a system, initially containing 2 moles of calcium, 3 moles of carbon and one mole of calcium carbide, is allowed to react to completion, the heat evolved, at 298 K will be . . . . . . . . J.
Correct Answer: Option C — 90,000
Detailed Academic Explanation:
90,000 is the correct answer to “For the irreversible reaction, Ca + C = CaC 2 , ΔH° 298 = - 60,000 J.mol -1 . If a system, initially containing 2 moles of calcium, 3 moles of carbon and one mole of calcium carbide, is allowed to react to completion, the heat evolved, at 298 K will be . . . . . . . . J.”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 35 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The half-life period for second order reactions is given as
Correct Answer: Option C — $${t_{\frac{1}{2}}} = \frac{1}{{K\left[ {{A_0}} \right]}}$$
Detailed Academic Explanation:
$${t_{\frac{1}{2}}} = \frac{1}{{K\left[ {{A_0}} \right]}}$$ is the correct answer to “The half-life period for second order reactions is given as”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 36 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The expression for first law of thermodynamics
Correct Answer: Option A — dU = δq - δW
Detailed Academic Explanation:
dU = δq - δW is the correct answer to “The expression for first law of thermodynamics”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 37 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The effect of change in temperature on the entropy of formation of an ideal binary solution, ΔS M, id , is such that ΔS M, id
Correct Answer: Option B — decreases with temperature
Detailed Academic Explanation:
decreases with temperature is the correct answer to “The effect of change in temperature on the entropy of formation of an ideal binary solution, ΔS M, id , is such that ΔS M, id”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 38 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
At absolute zero temperature, for any reaction involving condensed phases
Correct Answer: Option C — ΔS° = 0, ΔE° = 0
Detailed Academic Explanation:
ΔS° = 0, ΔE° = 0 is the correct answer to “At absolute zero temperature, for any reaction involving condensed phases”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 39 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
In a binary system, the difference in chemical potentials of two components (μi - μj) is equal to
Correct Answer: Option D — $$ - \frac{{d{G_m}}}{{dxj}}$$
Detailed Academic Explanation:
$$ - \frac{{d{G_m}}}{{dxj}}$$ is the correct answer to “In a binary system, the difference in chemical potentials of two components (μi - μj) is equal to”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
Question 40 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
One mole of element P is mixed with one mole of element Q. The entropy of jnixing at 0°K is
Correct Answer: Option B — - R In 0.5
Detailed Academic Explanation:
- R In 0.5 is the correct answer to “One mole of element P is mixed with one mole of element Q. The entropy of jnixing at 0°K is”. This question is standard in competitive examination syllabi for Metallurgical Thermodynamics And Kinetics.
💡Key Conceptual Anchor:Metallurgical Thermodynamics And Kinetics
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Electrometallurgy And Corrosion — Part 1
Master the next curriculum module with 40 exam-standard MCQs.
💡Examiner's Advisory for Metallurgical Engineering
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.