Physical Metallurgy — Part 1 MCQs with Explanations
Practice high-yield Metallurgical Engineering MCQs on Physical Metallurgy — Part 1 with worked academic solutions for PAEC, NESCOM, HIT, FPSC.
Questions
40
Difficulty Level
Exam-Level
Target Exams
PAEC, NESCOM, HIT...
Estimated Time
48 mins
Exam-Level PAEC NESCOM HIT FPSC
Verified for Commission Syllabus • Oct 14, 2026
40
Verified Practice Questions
Interactive test mode with detailed academic worked solutions
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🎉 Set complete! All 40 questions answered.
Question 1 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
A plastically deformed metal crystal at low temperature exhibits wavy slip line pattern due to
Correct Answer: Option B — Large number of slip systems
Detailed Academic Explanation:
Large number of slip systems is the correct answer to “A plastically deformed metal crystal at low temperature exhibits wavy slip line pattern due to”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 2 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Which of the following microstructures of the eutectic is not observed in binary alloys?
Correct Answer: Option B — Widmanstatten
Detailed Academic Explanation:
Widmanstatten is the correct answer to “Which of the following microstructures of the eutectic is not observed in binary alloys”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 3 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Upon addition of sodium oxide to molten silicate slag, the viscosity of the slag
Correct Answer: Option A — decreases because the oxygen ions supplied by the sodium oxide break the chain structure of the silicate slag
Detailed Academic Explanation:
decreases because the oxygen ions supplied by the sodium oxide break the chain structure of the silicate slag is the correct answer to “Upon addition of sodium oxide to molten silicate slag, the viscosity of the slag”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 4 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
A 0.4 wt% C steel is austenitised at 900°C for 1 hour and heat treated to get different. inicrostructures. Match the following microstructures to the heat treatments. P. Martensite + Retained austenite 1. Annealing Q. Ferrite + fine pearlite 2. Quenching R. Ferrite + spheroidal cementite 3. Quenching + temperature at 600°C S. Ferrite + coarse pearlite 4. Normalising
Correct Answer: Option D — P-2, Q-4, R-3, S-1
Detailed Academic Explanation:
P-2, Q-4, R-3, S-1 is the correct answer to “A 0.4 wt% C steel is austenitised at 900°C for 1 hour and heat treated to get different. inicrostructures. Match the following microstructures to the heat treatments. P. Martensite + Retained austenite 1. Annealing Q. Ferrite + fine pearlite 2. Quenching R. Ferrite + spheroidal cementite 3. Quenching + temperature at 600°C S. Ferrite + coarse pearlite 4. Normalising”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 5 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Which of the following has the highest hardness number?
Correct Answer: Option A — Martensite
Detailed Academic Explanation:
Martensite is the correct answer to “Which of the following has the highest hardness number”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 6 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Assertion: a : During hardening of steel, the component to be heat treated is strongly agitated in the quenching medium. Reason : r : The agitation breaks down the vapour barrier allowing the quench to proceed at a more rapid rate.
Correct Answer: Option B — Both 'a' and 'r' are false
Detailed Academic Explanation:
Both 'a' and 'r' are false is the correct answer to “Assertion: a : During hardening of steel, the component to be heat treated is strongly agitated in the quenching medium. Reason : r : The agitation breaks down the vapour barrier allowing the quench to proceed at a more rapid rate.”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 7 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Stretcher strains found in a low carbon sheet are associated with
Correct Answer: Option C — yield point phenomenon
Detailed Academic Explanation:
yield point phenomenon is the correct answer to “Stretcher strains found in a low carbon sheet are associated with”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 8 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Identify the type of the following invariant reaction: liquid 1 + solid 1 ⇋ solid 2
Correct Answer: Option C — Peritectic
Detailed Academic Explanation:
Peritectic is the correct answer to “Identify the type of the following invariant reaction: liquid 1 + solid 1 ⇋ solid 2”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 9 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
With increase in annealing temperature, the following defect density decreases.
Correct Answer: Option D — All of them
Detailed Academic Explanation:
All of them is the correct answer to “With increase in annealing temperature, the following defect density decreases.”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 10 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The number of Bravais space lattices with two lattice points are
Correct Answer: Option D — 5
Detailed Academic Explanation:
5 is the correct answer to “The number of Bravais space lattices with two lattice points are”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 11 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Malleabilisation heat treatment is performed on
Correct Answer: Option C — white cast iron
Detailed Academic Explanation:
white cast iron is the correct answer to “Malleabilisation heat treatment is performed on”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 12 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
What are the crystal structure of Cu, AI, Si, Zn and Ge?
Correct Answer: Option A — FCC, FCC, DC, HCP, DC
Detailed Academic Explanation:
FCC, FCC, DC, HCP, DC is the correct answer to “What are the crystal structure of Cu, AI, Si, Zn and Ge”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 13 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Match the basic strengthening mechanisms in the following materials. Group-I Group-II P. 60 : 40 brass is stronger than 70 : 30 brass. 1. Case hardening Q. An automobile gear made from 0.6% C steel and quenched in water from a temperature of 850°C. 2. Strain hardening R. Tungsten filament drawn at a temperature of 400°C. 3. Martensitic strengthening S. A ball bearing heated in furnace in ammonia atmosphere. 4. Second phase strengthening
Correct Answer: Option A — P-4, Q-3, R-2, S-1
Detailed Academic Explanation:
P-4, Q-3, R-2, S-1 is the correct answer to “Match the basic strengthening mechanisms in the following materials. Group-I Group-II P. 60 : 40 brass is stronger than 70 : 30 brass. 1. Case hardening Q. An automobile gear made from 0.6% C steel and quenched in water from a temperature of 850°C. 2. Strain hardening R. Tungsten filament drawn at a temperature of 400°C. 3. Martensitic strengthening S. A ball bearing heated in furnace in ammonia atmosphere. 4. Second phase strengthening”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 14 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
In a dilute solid solution of nickel and carbon in y-iron.
Correct Answer: Option D — Dc = DNI
Detailed Academic Explanation:
Dc = DNI is the correct answer to “In a dilute solid solution of nickel and carbon in y-iron.”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 15 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Match the heat treatment for an eutectoid steel shown in the TTT diagram below (as P, Q, R and S) with the resulting microstructure listed below: 1. Fine pearlite 2. martensite 3. Bainite 4. Coarse pearlite
Correct Answer: Option B — P-4, Q-1, R-3, S-2
Detailed Academic Explanation:
P-4, Q-1, R-3, S-2 is the correct answer to “Match the heat treatment for an eutectoid steel shown in the TTT diagram below (as P, Q, R and S) with the resulting microstructure listed below: 1. Fine pearlite 2. martensite 3. Bainite 4. Coarse pearlite”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 16 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Match the phenomena listed in Group I with the possible mechanisms in Group II . Group I Group II P. Fatigue 1. Grain boundary sliding Q. Creep 2. Slip band extrusion and intrusion R. Strain hardening 3. Cottrell atmosphere S. Yield point phenomenon 4. Dislocation interaction
Correct Answer: Option C — P-2, Q-1, R-4, S-3
Detailed Academic Explanation:
P-2, Q-1, R-4, S-3 is the correct answer to “Match the phenomena listed in Group I with the possible mechanisms in Group II . Group I Group II P. Fatigue 1. Grain boundary sliding Q. Creep 2. Slip band extrusion and intrusion R. Strain hardening 3. Cottrell atmosphere S. Yield point phenomenon 4. Dislocation interaction”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 17 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
An Al 4.5 mass% Cu alloy solutionising at 500°C, quenched to room temperature and aged at 200°C for 2 hrs is found to exhibit an increase in hardness. Theprimary mechanism contributing to increased hardness is
Correct Answer: Option C — precipitation hardening
Detailed Academic Explanation:
precipitation hardening is the correct answer to “An Al 4.5 mass% Cu alloy solutionising at 500°C, quenched to room temperature and aged at 200°C for 2 hrs is found to exhibit an increase in hardness. Theprimary mechanism contributing to increased hardness is”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 18 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The low angle grain boundary occurs when the orientation difference between the adjacent grains is of the order of
Correct Answer: Option C — 1
Detailed Academic Explanation:
1 is the correct answer to “The low angle grain boundary occurs when the orientation difference between the adjacent grains is of the order of”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 19 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
An Fe - 3 wt % C - 1 wt % Si alloy is cooled very slowly from the liquid state to a temperature of 1023 K. Thereafter, it is cooled in air. The microstructure at room temperature will consist of
Correct Answer: Option B — pearlite + graphite
Detailed Academic Explanation:
pearlite + graphite is the correct answer to “An Fe - 3 wt % C - 1 wt % Si alloy is cooled very slowly from the liquid state to a temperature of 1023 K. Thereafter, it is cooled in air. The microstructure at room temperature will consist of”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 20 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
An annealed plain carbon steel, showing fully pearlitic microstructure, has a carbon content of . . . . . . . . wt%.
Correct Answer: Option C — 0.77
Detailed Academic Explanation:
0.77 is the correct answer to “An annealed plain carbon steel, showing fully pearlitic microstructure, has a carbon content of . . . . . . . . wt%.”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 21 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
A 10 mm thick En-24 steel yielded a valid plane strain fracture toughness of 80 Mpa √m. The minimum yield strength of the steel is . . . . . . . . MPa.
Correct Answer: Option B — 1265
Detailed Academic Explanation:
1265 is the correct answer to “A 10 mm thick En-24 steel yielded a valid plane strain fracture toughness of 80 Mpa √m. The minimum yield strength of the steel is . . . . . . . . MPa.”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 22 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
In precipitation hardenable alloy like duralumin, intermediate precipitates can form due to
Correct Answer: Option D — coherency strain
Detailed Academic Explanation:
coherency strain is the correct answer to “In precipitation hardenable alloy like duralumin, intermediate precipitates can form due to”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 23 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Identify the incorrect statement with respect to grain growth.
Correct Answer: Option A — As the average grain size increases, the grain boundary energy per unit area deceases
Detailed Academic Explanation:
As the average grain size increases, the grain boundary energy per unit area deceases is the correct answer to “Identify the incorrect statement with respect to grain growth.”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 24 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Coring is often being removed by subsequent
Correct Answer: Option D — All are correct
Detailed Academic Explanation:
All are correct is the correct answer to “Coring is often being removed by subsequent”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 25 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
During the solidification of a pure metal, it was found that dendrites are formed. Assuming that the liquid-solid interface is at the melting temperature, the temperature from the interface into the liquid
Correct Answer: Option A — Decreases
Detailed Academic Explanation:
Decreases is the correct answer to “During the solidification of a pure metal, it was found that dendrites are formed. Assuming that the liquid-solid interface is at the melting temperature, the temperature from the interface into the liquid”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 26 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Creep resistance decreases due to
Correct Answer: Option A — Small grain size
Detailed Academic Explanation:
Small grain size is the correct answer to “Creep resistance decreases due to”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 27 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
What is the eutectic composition in Pb-Sn diagram
Correct Answer: Option C — 38.1% Pb and 61.9% Sn
Detailed Academic Explanation:
38.1% Pb and 61.9% Sn is the correct answer to “What is the eutectic composition in Pb-Sn diagram”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 28 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The net effect of continuous cooling on the TTT curves is that the curves are shifted to the
Correct Answer: Option C — right and raised
Detailed Academic Explanation:
right and raised is the correct answer to “The net effect of continuous cooling on the TTT curves is that the curves are shifted to the”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 29 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Substantial amount of bainite can form during continous cooling in
Correct Answer: Option C — alloy steel
Detailed Academic Explanation:
alloy steel is the correct answer to “Substantial amount of bainite can form during continous cooling in”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 30 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
A 0.2% C steel is equilibriated just above the eutectoid temperature and then quenched in iced brine. The room temperature microstructure will consist of
Correct Answer: Option B — 76% ferrite and 24% pearlite
Detailed Academic Explanation:
76% ferrite and 24% pearlite is the correct answer to “A 0.2% C steel is equilibriated just above the eutectoid temperature and then quenched in iced brine. The room temperature microstructure will consist of”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 31 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The relation between dendrite arm spacing (x) and the solidification time (t) is given by (A and n are constants)
Correct Answer: Option C — $$x = A{t^{ - \frac{1}{n}}}$$
Detailed Academic Explanation:
$$x = A{t^{ - \frac{1}{n}}}$$ is the correct answer to “The relation between dendrite arm spacing (x) and the solidification time (t) is given by (A and n are constants)”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 32 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The hardenability of steels decreases with
Correct Answer: Option D — decrease in grain size
Detailed Academic Explanation:
decrease in grain size is the correct answer to “The hardenability of steels decreases with”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 33 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The angle between the line vector and the burgers vector of an edge dislocation is
Correct Answer: Option B — 90 degrees
Detailed Academic Explanation:
90 degrees is the correct answer to “The angle between the line vector and the burgers vector of an edge dislocation is”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 34 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Which of the following cooling curves (shown in schematic) in an eutectoid steel will produce 50% bainitic structure?
Correct Answer: Option B — Q
Detailed Academic Explanation:
Q is the correct answer to “Which of the following cooling curves (shown in schematic) in an eutectoid steel will produce 50% bainitic structure”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 35 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
At 910°C γ-Fe transforms to α - Fe resulting in a percentage volume expansion of
Correct Answer: Option D — 8.8
Detailed Academic Explanation:
8.8 is the correct answer to “At 910°C γ-Fe transforms to α - Fe resulting in a percentage volume expansion of”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 36 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The boundary line between (liquid) and (liquid+solid) regions is called
Correct Answer: Option B — Liquidus
Detailed Academic Explanation:
Liquidus is the correct answer to “The boundary line between (liquid) and (liquid+solid) regions is called”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 37 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Metal A nucleates as a spheres in a melt. Assuming Y(liquid/solid surface energy) = 200mJ/m 2 and ΔGv (change in volume free energy) = -10 8 J/M 3 the critical radius (in nm) for stable nuclei is
Correct Answer: Option D — 4
Detailed Academic Explanation:
4 is the correct answer to “Metal A nucleates as a spheres in a melt. Assuming Y(liquid/solid surface energy) = 200mJ/m 2 and ΔGv (change in volume free energy) = -10 8 J/M 3 the critical radius (in nm) for stable nuclei is”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 38 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Two Cu-Ni alloys, one with 47 wt.% Ni and the other with 53 wt.% Ni, are kept in separate crucibles and are allowed to equilibrate at the same-temperature T 1 between the liquidus and the solidus. The two alloys have
Correct Answer: Option B — the same composition of the liquid but the weight fractions of the liquid are different
Detailed Academic Explanation:
the same composition of the liquid but the weight fractions of the liquid are different is the correct answer to “Two Cu-Ni alloys, one with 47 wt.% Ni and the other with 53 wt.% Ni, are kept in separate crucibles and are allowed to equilibrate at the same-temperature T 1 between the liquidus and the solidus. The two alloys have”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 39 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
Match the following. Gruop-I Gruop-II P. Line defect 1. Vacancy Q. Point defect 2. Grain boundary R. Area defect 3. Voids S. Volume defect 4. Dislocations
Correct Answer: Option A — P-4, Q-1, R-2, S-3
Detailed Academic Explanation:
P-4, Q-1, R-2, S-3 is the correct answer to “Match the following. Gruop-I Gruop-II P. Line defect 1. Vacancy Q. Point defect 2. Grain boundary R. Area defect 3. Voids S. Volume defect 4. Dislocations”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
Question 40 of 40
★ PAEC
★ NESCOM
★ PAEC
★ NESCOM
The primary strengthening mechanism in 70 : 30 brass is
Correct Answer: Option A — solid solution strengthening
Detailed Academic Explanation:
solid solution strengthening is the correct answer to “The primary strengthening mechanism in 70 : 30 brass is”. This question is standard in competitive examination syllabi for Physical Metallurgy.
💡Key Conceptual Anchor:Physical Metallurgy
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Electrometallurgy And Corrosion — Part 1
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💡Examiner's Advisory for Metallurgical Engineering
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.