Recombinant Dna Technology — Part 1 MCQs with Explanations
Practice high-yield Biotechnology Engineering MCQs on Recombinant Dna Technology — Part 1 with worked academic solutions for PPSC, FPSC, NIH, NTS.
Questions
40
Difficulty Level
Exam-Level
Target Exams
PPSC, FPSC, NIH...
Estimated Time
48 mins
Exam-Level PPSC FPSC NIH NTS
Verified for Commission Syllabus • Oct 14, 2026
40
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Question 1 of 40
★ PPSC
★ FPSC
★ PPSC
★ FPSC
If bacterial cells are transformed with a mixture of linear and circular molecules resulting from a ligation reaction designed to produce a recombinant molecule
Correct Answer: Option D — The circular molecules will be amplified by the cells
Detailed Academic Explanation:
The circular molecules will be amplified by the cells is the correct answer to “If bacterial cells are transformed with a mixture of linear and circular molecules resulting from a ligation reaction designed to produce a recombinant molecule”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 2 of 40
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★ FPSC
A recombinant protein is to be expressed under the control of the lac promoter and operator in a strain of E. coli having the genotype lacI + crp + . Even in the absence of inducer IPTG, low levels of expression of the recombinant protein are seen (leaky expression). Which one of the following should be done to minimize such leaky expression?
Correct Answer: Option C — Addition of excess glucose to the medium
Detailed Academic Explanation:
Addition of excess glucose to the medium is the correct answer to “A recombinant protein is to be expressed under the control of the lac promoter and operator in a strain of E. coli having the genotype lacI + crp + . Even in the absence of inducer IPTG, low levels of expression of the recombinant protein are seen (leaky expression). Which one of the following should be done to minimize such leaky expression”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 3 of 40
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★ FPSC
Determine the correctness or otherwise of the following Assertion [A] and the Reason [R] . Assertion [A]: Dam methylase protects E. coli DNA from phage endonucleases. Reason [R]: E. coli Dam methylase methylates the adenosine residue in the sequence "GATC".
Correct Answer: Option D — [A] is false but [R] is true
Detailed Academic Explanation:
[A] is false but [R] is true is the correct answer to “Determine the correctness or otherwise of the following Assertion [A] and the Reason [R] . Assertion [A]: Dam methylase protects E. coli DNA from phage endonucleases. Reason [R]: E. coli Dam methylase methylates the adenosine residue in the sequence "GATC".”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 4 of 40
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★ FPSC
The schematic of a plasmid with a gap in one of the strands is shown below: Which of the following enzyme(s) is/are required to fill the gap and generate a covalently closed circular plasmid? P. DNA ligase Q. Alkaline phosphatase R. DNA polymerase S. Polynucleotide kinase
Correct Answer: Option B — P, R and S only
Detailed Academic Explanation:
P, R and S only is the correct answer to “The schematic of a plasmid with a gap in one of the strands is shown below: Which of the following enzyme(s) is/are required to fill the gap and generate a covalently closed circular plasmid? P. DNA ligase Q. Alkaline phosphatase R. DNA polymerase S. Polynucleotide kinase”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 5 of 40
★ PPSC
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★ FPSC
Match the following genetic elements with their functions. Genetic elements Functions P. neo R 1. Facilitates inducible expression of genes in eukaryotes. Q. SV40 2. Facilitates constitutive expression of genes in eukaryotes. R. LTR 3. Allows amplification of gene. S. S. dhfr. 4. Provides way of selecting eukaryotic cells, which have received foreign DNA.
Correct Answer: Option A — P-4, Q-2, R-1, S-3
Detailed Academic Explanation:
P-4, Q-2, R-1, S-3 is the correct answer to “Match the following genetic elements with their functions. Genetic elements Functions P. neo R 1. Facilitates inducible expression of genes in eukaryotes. Q. SV40 2. Facilitates constitutive expression of genes in eukaryotes. R. LTR 3. Allows amplification of gene. S. S. dhfr. 4. Provides way of selecting eukaryotic cells, which have received foreign DNA.”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 6 of 40
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★ FPSC
cDNA made from the mRNA of an organism was used to make a cDNA library in a vector that allows the expression as a fusion with a reporter tag. What percentage of the cDNA clones is likely to give rise to correct gene products?
Correct Answer: Option C — 50%
Detailed Academic Explanation:
50% is the correct answer to “cDNA made from the mRNA of an organism was used to make a cDNA library in a vector that allows the expression as a fusion with a reporter tag. What percentage of the cDNA clones is likely to give rise to correct gene products”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 7 of 40
★ PPSC
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Commonly used reporter gene in plant expression vectors is
Correct Answer: Option B — Gus gene
Detailed Academic Explanation:
Gus gene is the correct answer to “Commonly used reporter gene in plant expression vectors is”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 8 of 40
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EcoRI restriction sites on a 10kb DNA fragment are shown below Upon partial digestion, what are the lengths (in kb) of all the possible DNA fragments obtained?
Correct Answer: Option A — 2, 3, 4, 5, 6, 7, 8, and 10
Detailed Academic Explanation:
2, 3, 4, 5, 6, 7, 8, and 10 is the correct answer to “EcoRI restriction sites on a 10kb DNA fragment are shown below Upon partial digestion, what are the lengths (in kb) of all the possible DNA fragments obtained”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 9 of 40
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★ FPSC
What are the experimental steps needed for screening an expression library for clone encoding a protein X that has been isolated and purified? P. mRNA isolation Q. Antibody preparation R. Cloning into an appropriate vector S. Western blotting on transferred plaques
Correct Answer: Option C — Q, R
Detailed Academic Explanation:
Q, R is the correct answer to “What are the experimental steps needed for screening an expression library for clone encoding a protein X that has been isolated and purified? P. mRNA isolation Q. Antibody preparation R. Cloning into an appropriate vector S. Western blotting on transferred plaques”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 10 of 40
★ PPSC
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★ FPSC
The basis for blue-white screening with pUC vectors is
Correct Answer: Option A — Intraallelic complementation
Detailed Academic Explanation:
Intraallelic complementation is the correct answer to “The basis for blue-white screening with pUC vectors is”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 11 of 40
★ PPSC
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Phage T7 promoter containing plasmids are used for over-expression of cloned genes because
Correct Answer: Option C — Exquisite specificity of T7 RNA polymerase to phage promoters
Detailed Academic Explanation:
Exquisite specificity of T7 RNA polymerase to phage promoters is the correct answer to “Phage T7 promoter containing plasmids are used for over-expression of cloned genes because”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 12 of 40
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Though the right border (RB) and left border (LB) of T-DNA are identical, the DNA transfer is specific for the DNA left of the RB (the T-DNA), rather than for the DNA left of the LB because
Correct Answer: Option A — The sequence context at the RB defines the direction of transfer
Detailed Academic Explanation:
The sequence context at the RB defines the direction of transfer is the correct answer to “Though the right border (RB) and left border (LB) of T-DNA are identical, the DNA transfer is specific for the DNA left of the RB (the T-DNA), rather than for the DNA left of the LB because”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 13 of 40
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★ FPSC
The restriction endonuclease Eco52I recognizes the sequence C/GGCGG and cuts between the first C and the first G, indicated by the slash. DNA cut by which of the following enzymes (given with their recognition sequences and cut sites) could be cloned into a plasmid digested with Eco52I?
Correct Answer: Option B — XmaIII (C/GGCGG)
Detailed Academic Explanation:
XmaIII (C/GGCGG) is the correct answer to “The restriction endonuclease Eco52I recognizes the sequence C/GGCGG and cuts between the first C and the first G, indicated by the slash. DNA cut by which of the following enzymes (given with their recognition sequences and cut sites) could be cloned into a plasmid digested with Eco52I”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 14 of 40
★ PPSC
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Which of the following are commonly used as reporter genes? P. NPTgene Q. Luciferase gene R. CFTR gene S. GFP gene
Correct Answer: Option A — Q, S
Detailed Academic Explanation:
Q, S is the correct answer to “Which of the following are commonly used as reporter genes? P. NPTgene Q. Luciferase gene R. CFTR gene S. GFP gene”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 15 of 40
★ PPSC
★ FPSC
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★ FPSC
Which one of the following statements about Agrobacterium Ti plasmid is correct?
Correct Answer: Option D — Opine biosynthesis genes are located within the T-DNA segment
Detailed Academic Explanation:
Opine biosynthesis genes are located within the T-DNA segment is the correct answer to “Which one of the following statements about Agrobacterium Ti plasmid is correct”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 16 of 40
★ PPSC
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Match the items in Group I with Group II . Group I (Vectors) Group II (Maximum DNA packaging) P. λ phage 1. 35 - 45 kb Q. Bacterial Artificial Chromosomes (BACs) 2. 100 - 300 kb R. P1 derived Artificial Chromosomes (PACs) 3. ≤ 300 kb S. λ cosmid 4. 5 - 25 kb
Correct Answer: Option C — P-4, Q-3, R-2, S-1
Detailed Academic Explanation:
P-4, Q-3, R-2, S-1 is the correct answer to “Match the items in Group I with Group II . Group I (Vectors) Group II (Maximum DNA packaging) P. λ phage 1. 35 - 45 kb Q. Bacterial Artificial Chromosomes (BACs) 2. 100 - 300 kb R. P1 derived Artificial Chromosomes (PACs) 3. ≤ 300 kb S. λ cosmid 4. 5 - 25 kb”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 17 of 40
★ PPSC
★ FPSC
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★ FPSC
A single base pair of DNA weighs 1.1 × 10 -21 grams. How many picomoles of a plasmid vector of length 2750 bp are contained in 1 μg of purified DNA?
Correct Answer: Option B — 0.55
Detailed Academic Explanation:
0.55 is the correct answer to “A single base pair of DNA weighs 1.1 × 10 -21 grams. How many picomoles of a plasmid vector of length 2750 bp are contained in 1 μg of purified DNA”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 18 of 40
★ PPSC
★ FPSC
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★ FPSC
Many plasmids have ampr marker. This implies
Correct Answer: Option C — The plasmid contains the gene encoding β-lactamase
Detailed Academic Explanation:
The plasmid contains the gene encoding β-lactamase is the correct answer to “Many plasmids have ampr marker. This implies”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 19 of 40
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Expression in poor amount and in inactive form of cDNA of a eukaryotic protein in Escherichia coli using its expression vector is due to P. The absence of capping mechanism of mRNA. Q. Codon bias. R. Absence of polyadenylation. S. Absence of proper glycosylation.
Correct Answer: Option C — Q, S
Detailed Academic Explanation:
Q, S is the correct answer to “Expression in poor amount and in inactive form of cDNA of a eukaryotic protein in Escherichia coli using its expression vector is due to P. The absence of capping mechanism of mRNA. Q. Codon bias. R. Absence of polyadenylation. S. Absence of proper glycosylation.”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 20 of 40
★ PPSC
★ FPSC
★ PPSC
★ FPSC
T4 polynucleotide kinase is used for
Correct Answer: Option B — Labeling 5' ends of DNA
Detailed Academic Explanation:
Labeling 5' ends of DNA is the correct answer to “T4 polynucleotide kinase is used for”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 21 of 40
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Restriction endonucleases which recognize and cut same recognition sequences are known as
Correct Answer: Option A — Isoschizomers
Detailed Academic Explanation:
Isoschizomers is the correct answer to “Restriction endonucleases which recognize and cut same recognition sequences are known as”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 22 of 40
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The length of each boarder sequence in Ti plasmid is about
Correct Answer: Option D — 25 base pairs
Detailed Academic Explanation:
25 base pairs is the correct answer to “The length of each boarder sequence in Ti plasmid is about”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 23 of 40
★ PPSC
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★ FPSC
A DNA fragment of 4500 bp has to be tailed with dT residues by using dTTP and the enzyme 'terminal transferase' The stock solution of dTTP that is used as a substrate has concentration of 150 μM. Ten μL of this stock solution is added to a total volume of 200 μL reaction. What will be the concentration of dTTP in the reaction?
Correct Answer: Option A — 7.5 μM
Detailed Academic Explanation:
7.5 μM is the correct answer to “A DNA fragment of 4500 bp has to be tailed with dT residues by using dTTP and the enzyme 'terminal transferase' The stock solution of dTTP that is used as a substrate has concentration of 150 μM. Ten μL of this stock solution is added to a total volume of 200 μL reaction. What will be the concentration of dTTP in the reaction”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 24 of 40
★ PPSC
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Baculovirus expression system is used to express heterologous genes in
Correct Answer: Option C — Insects
Detailed Academic Explanation:
Insects is the correct answer to “Baculovirus expression system is used to express heterologous genes in”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 25 of 40
★ PPSC
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A variety of genetic elements are used in the transgenic plant research. Match the genetic elements (Group I) with their corresponding source (Group II) . Group I Group II P. Ubiquitin1 promoter 1. Agrobacterium tumefaciens Q. Nos transcriptional terminator 2. Streptomyces hygroscopicus R. bar selection marker gene 3. Escherichia coli S. gus reporter gene 4. Zea mays
Correct Answer: Option D — P-4, Q-1, R-2, S-3
Detailed Academic Explanation:
P-4, Q-1, R-2, S-3 is the correct answer to “A variety of genetic elements are used in the transgenic plant research. Match the genetic elements (Group I) with their corresponding source (Group II) . Group I Group II P. Ubiquitin1 promoter 1. Agrobacterium tumefaciens Q. Nos transcriptional terminator 2. Streptomyces hygroscopicus R. bar selection marker gene 3. Escherichia coli S. gus reporter gene 4. Zea mays”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 26 of 40
★ PPSC
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★ FPSC
The essential component of Ti plasmid required for integration into plant genome is
Correct Answer: Option B — Tumor inducing gene
Detailed Academic Explanation:
Tumor inducing gene is the correct answer to “The essential component of Ti plasmid required for integration into plant genome is”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 27 of 40
★ PPSC
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★ PPSC
★ FPSC
The bacteria known to be naturally competent for transformation of DNA is
Correct Answer: Option B — Bacillus subtilis
Detailed Academic Explanation:
Bacillus subtilis is the correct answer to “The bacteria known to be naturally competent for transformation of DNA is”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 28 of 40
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BAC, which can be used to clone large DNA fragments, is derived from
Correct Answer: Option B — F plasmid
Detailed Academic Explanation:
F plasmid is the correct answer to “BAC, which can be used to clone large DNA fragments, is derived from”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 29 of 40
★ PPSC
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★ PPSC
★ FPSC
Transfer of T-DNA from Ti plasmid into plant cell is mediated by
Correct Answer: Option B — Vir gene
Detailed Academic Explanation:
Vir gene is the correct answer to “Transfer of T-DNA from Ti plasmid into plant cell is mediated by”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 30 of 40
★ PPSC
★ FPSC
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★ FPSC
Antibiotic resistance marker that cannot be used in a cloning vector in Gram negative bacteria is
Correct Answer: Option C — Vancomycin
Detailed Academic Explanation:
Vancomycin is the correct answer to “Antibiotic resistance marker that cannot be used in a cloning vector in Gram negative bacteria is”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 31 of 40
★ PPSC
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★ FPSC
A gene cannot be isolated from a human genomic DNA library by functional complementation in E. coli because of
Correct Answer: Option B — The absence of splicing machinery
Detailed Academic Explanation:
The absence of splicing machinery is the correct answer to “A gene cannot be isolated from a human genomic DNA library by functional complementation in E. coli because of”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 32 of 40
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During a positive-negative selection process, transformed animal cells expressing . . . . . . . . are killed in presence of ganciclovir in the medium.
Correct Answer: Option B — Viral thymidine kinase
Detailed Academic Explanation:
Viral thymidine kinase is the correct answer to “During a positive-negative selection process, transformed animal cells expressing . . . . . . . . are killed in presence of ganciclovir in the medium.”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 33 of 40
★ PPSC
★ FPSC
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★ FPSC
To isolate a gene coding for glucagon, the cDNA library as to be constructed using mRNA isolated from
Correct Answer: Option B — Pancreas
Detailed Academic Explanation:
Pancreas is the correct answer to “To isolate a gene coding for glucagon, the cDNA library as to be constructed using mRNA isolated from”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 34 of 40
★ PPSC
★ FPSC
★ PPSC
★ FPSC
Which one of the following cannot be a recognition sequence for a type II restriction enzyme?
Correct Answer: Option D — ATGCCT
Detailed Academic Explanation:
ATGCCT is the correct answer to “Which one of the following cannot be a recognition sequence for a type II restriction enzyme”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 35 of 40
★ PPSC
★ FPSC
★ PPSC
★ FPSC
To be a cloning vector, a plasmid does not require
Correct Answer: Option B — An antibiotic resistance marker
Detailed Academic Explanation:
An antibiotic resistance marker is the correct answer to “To be a cloning vector, a plasmid does not require”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 36 of 40
★ PPSC
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★ FPSC
Select the correct combination of genetic components that are essential for the transfer of T-DNA segment from Agrobacterium tumefaciens to plant cells.
Correct Answer: Option B — Border repeat sequences and vir genes
Detailed Academic Explanation:
Border repeat sequences and vir genes is the correct answer to “Select the correct combination of genetic components that are essential for the transfer of T-DNA segment from Agrobacterium tumefaciens to plant cells.”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 37 of 40
★ PPSC
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★ FPSC
A linear DNA fragment is 100% labeled at one end and has 3 restriction sites for EcoRI. If it is partially digested by EcoRI so that all possible fragments are produced, how many of these fragments will be labeled and how many will not be labeled?
Correct Answer: Option A — 4 labeled; 6 unlabeled
Detailed Academic Explanation:
4 labeled; 6 unlabeled is the correct answer to “A linear DNA fragment is 100% labeled at one end and has 3 restriction sites for EcoRI. If it is partially digested by EcoRI so that all possible fragments are produced, how many of these fragments will be labeled and how many will not be labeled”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 38 of 40
★ PPSC
★ FPSC
★ PPSC
★ FPSC
A cell has five molecules of a rare mRNA. Each cell contains 4 × 10 5 mRNA molecules. How many clones one will need to screen to have 99% probability of finding at least one recombinant cDNA of the rare mRNA, after making cDNA library from such cell?
Correct Answer: Option D — 4.05 × 105
Detailed Academic Explanation:
4.05 × 105 is the correct answer to “A cell has five molecules of a rare mRNA. Each cell contains 4 × 10 5 mRNA molecules. How many clones one will need to screen to have 99% probability of finding at least one recombinant cDNA of the rare mRNA, after making cDNA library from such cell”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 39 of 40
★ PPSC
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★ FPSC
The enzymes that can be used in 5' end labeling of DNA are
Correct Answer: Option A — Alkaline phosphatase
Detailed Academic Explanation:
Alkaline phosphatase is the correct answer to “The enzymes that can be used in 5' end labeling of DNA are”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
Question 40 of 40
★ PPSC
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★ FPSC
The restriction endonuclease HaeIII recognizes the sequence GG ↓ CC and the point of cleavage is given by the arrow. If you want to clone a piece of DNA in a plasmid digested by HaeIII, what will be restriction enzyme of choice
Correct Answer: Option C — SalmIII (GG↓CC)
Detailed Academic Explanation:
SalmIII (GG↓CC) is the correct answer to “The restriction endonuclease HaeIII recognizes the sequence GG ↓ CC and the point of cleavage is given by the arrow. If you want to clone a piece of DNA in a plasmid digested by HaeIII, what will be restriction enzyme of choice”. This question is standard in competitive examination syllabi for Recombinant Dna Technology.
💡Key Conceptual Anchor:Recombinant Dna Technology
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Analytical Tools In Biotechnology — Part 1
Master the next curriculum module with 40 exam-standard MCQs.
💡Examiner's Advisory for Biotechnology Engineering
In competitive commission exams (FPSC, PPSC, KPPSC, SPSC, CSS, PMS), questions are frequently phrased with distractor options designed to catch rote learners. Whenever you answer an MCQ, read the Detailed Academic Explanation and Conceptual Anchor to understand why the remaining options are incorrect.